小明发现,任意一个直角三角形都可以分割成两个等腰三角形,已知:在
中,
.求作:直线
,使得直线
将
分割成两个等腰三角形。下面是小明设计的尺规作图过程.
作法:如图,①作直角边
的垂直平分线
,与斜边
相交于点D;②作直线
,则直线
就是所求作的直线.
根据小明设计的尺规作图过程,解决下列问题:
(1)使用直尺和圆规,补全图形(保留作图痕迹);
(2)小明进一步探究:以点D为圆心,适当长为半径画弧分别交
于P、Q两点,再分别以点P、Q为圆心,大于
的长为半径画弧,两弧在
内交于点M,直线
交
于点E,则
( )(填写理由),使用尺规作图在图中补全作图痕迹.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15c0dbe3c080c4c4636c64803e5c1f76.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ed10df4140819d5451773a45de66201b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9d78abbad68bbbf12af10cd40ef4c353.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9d78abbad68bbbf12af10cd40ef4c353.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15c0dbe3c080c4c4636c64803e5c1f76.png)
作法:如图,①作直角边
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6b1bd1adfe4cc6566218f19970c2fd3b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411461db15ee8086332c531e086c40c7.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f52a58fbaf4fea03567e88a9f0f6e37e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9d78abbad68bbbf12af10cd40ef4c353.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9d78abbad68bbbf12af10cd40ef4c353.png)
![](https://img.xkw.com/dksih/QBM/editorImg/2023/8/31/53310c76-d66c-4c55-a42a-a0791dff4cf4.png?resizew=228)
根据小明设计的尺规作图过程,解决下列问题:
(1)使用直尺和圆规,补全图形(保留作图痕迹);
(2)小明进一步探究:以点D为圆心,适当长为半径画弧分别交
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8c24127d3e9da4b4a2547aa8de84ea45.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1e34652865d75f195cfe551b3fcf41bc.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3981e7286d41960daf4e110c1c84e03a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15a424b50eaeafa6f302ffd95476cb86.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/60ef95894ceebaf236170e8832dcf7e3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/553a93e0b6156befa00b50bdfaef95d9.png)
更新时间:2023-08-18 21:17:20
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解答题-作图题
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适中
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【推荐1】已知:点
和直线![](https://staticzujuan.xkw.com/quesimg/Upload/formula/294f5ba74cdf695fc9a8a8e52f421328.png)
求作:以点
为直角顶点的等腰直角三角形,使它的斜边落在直线上,并在三角形内部做出以斜边中点为圆心的面积最大的半圆
.
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![](https://staticzujuan.xkw.com/quesimg/Upload/formula/294f5ba74cdf695fc9a8a8e52f421328.png)
求作:以点
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dad2a36927223bd70f426ba06aea4b45.png)
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解答题-作图题
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适中
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【推荐2】如图,在6×6的正方形方格纸中,
的顶点在格点上.
![](https://img.xkw.com/dksih/QBM/editorImg/2022/8/11/85e58e08-6699-4fa4-aa64-9526da428c3a.png?resizew=156)
(1)直接写出
______.
(2)仅用直尺,画出
的平分线
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______.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7cbce11aa19b8bd2bf6ee5a834e005de.png)
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(1)直接写出
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(2)仅用直尺,画出
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7cbce11aa19b8bd2bf6ee5a834e005de.png)
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解答题-证明题
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【推荐1】如图,
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(1)求证:四边形
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(2)若
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(1)求证:四边形
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(2)若
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解答题-问答题
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适中
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【推荐2】如图,在
中,
,斜边
的垂直平分线交
于点
,交
于点
,求
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解答题-作图题
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适中
(0.65)
【推荐1】请你根据要求作图,保留作图痕迹(不要求写作图过程)
![](https://img.xkw.com/dksih/QBM/2021/1/27/2645199156953088/2645870217797632/STEM/649fb7e5f1c645a2a633c995c28988be.png?resizew=361)
(1)请试一试用一把三角尺,找出图①中圆的圆心,并写出作图的依据.
(2)据第( 1 )题中的作图经验 ,请你仅用无刻度 的直尺和圆规在图②的
中作出
边上的高.
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(1)请试一试用一把三角尺,找出图①中圆的圆心,并写出作图的依据.
(2)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15c0dbe3c080c4c4636c64803e5c1f76.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f52a58fbaf4fea03567e88a9f0f6e37e.png)
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解答题-作图题
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适中
(0.65)
【推荐2】如图,已如
中,
平分
.
![](https://img.xkw.com/dksih/QBM/editorImg/2024/1/15/e764cabe-c51b-4589-92b8-1eeabed5b593.png?resizew=195)
(1)用尺规完成以下基本作图:作线段
的垂直平分线,分别交
、
、
于点
、
、
,连接
;(不写作法,保留清晰的作图痕迹)
(2)求证:
,请根据下列证明思路完成填空:
证明:
平分![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d39b8d91afc34e4a9b0fdbb6bafb9087.png)
①
是线段
的垂直平分线,
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2de0d10ef8b748d4531250c37c5d3f9e.png)
,
在
和
中,
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/45abcc39ca0b8c65e5cb4e7b006d8f0e.png)
(③ ).
④
是线段
的垂直平分线,
⑤
.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15c0dbe3c080c4c4636c64803e5c1f76.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7ead683c30937825ab5fb9318265ac9a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d39b8d91afc34e4a9b0fdbb6bafb9087.png)
![](https://img.xkw.com/dksih/QBM/editorImg/2024/1/15/e764cabe-c51b-4589-92b8-1eeabed5b593.png?resizew=195)
(1)用尺规完成以下基本作图:作线段
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d40b319212a7e7528b053e1c7097e966.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f52a58fbaf4fea03567e88a9f0f6e37e.png)
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![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e6e490f703eb6c9bb1278c78ebc2d661.png)
(2)求证:
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/86d1125b47dec1c5e93143ee59ad862a.png)
证明:
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d558048f4591f82e669ae89e20ebc082.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d39b8d91afc34e4a9b0fdbb6bafb9087.png)
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![](https://staticzujuan.xkw.com/quesimg/Upload/formula/173f7d26d069c0f16a0f6fcb517aa28c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d40b319212a7e7528b053e1c7097e966.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b5f96d400f5d5f0a40f17048dc0fa480.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3e879350fafa58e3ee192076c9ee3375.png)
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解答题-计算题
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适中
(0.65)
名校
解题方法
【推荐1】若一条直线把一个平面图形分成面积相等的两部分,那么这条直线叫做该平面图形的“和谐线”,其“和谐线”被该平面图形截得的线段叫做该平面图形的“和谐线段”(例如圆的直径就是圆的“和谐线段”)
问题探究:
![](https://img.xkw.com/dksih/QBM/2020/5/15/2463348497006592/2463488197861376/STEM/b693e1cf4d034996bb876b2cfcd740d3.png?resizew=371)
(1)如图①,已知△ABC中,AB=6,BC=8,∠B=90°,请写出△ABC的两条“和谐线段”的长.
(2)如图②,平行四边形ABCD中,AB=6,BC=8,∠B=60°,请直接写出该平行四边形ABCD的“和谐线段”长的最大值和最小值;
问题解决
(3)如图③,四边形ABCD是某市规划中的商业区示意图,其中AB=2,CD=10,∠A=135°,∠B=90°,tanC=
,现计划在商业区内修一条笔直的单行道MN(小道的宽度不计),入口M在BC上,出口N在CD上,使得MN为四边形ABCD“和谐线段”,在道路一侧△MNC区域规划为公园,为了美观要求△MNC是以CM为腰的等腰三角形,请通过计算说明设计师的想法能否实现?若可以,请确定点M的位置(即求CM的长).
问题探究:
![](https://img.xkw.com/dksih/QBM/2020/5/15/2463348497006592/2463488197861376/STEM/b693e1cf4d034996bb876b2cfcd740d3.png?resizew=371)
(1)如图①,已知△ABC中,AB=6,BC=8,∠B=90°,请写出△ABC的两条“和谐线段”的长.
(2)如图②,平行四边形ABCD中,AB=6,BC=8,∠B=60°,请直接写出该平行四边形ABCD的“和谐线段”长的最大值和最小值;
问题解决
(3)如图③,四边形ABCD是某市规划中的商业区示意图,其中AB=2,CD=10,∠A=135°,∠B=90°,tanC=
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8b2a698891d42c70b597f0da4f215f09.png)
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解答题-问答题
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适中
(0.65)
【推荐2】如图,在△ABC中,AB=AC,BD是AC边上的高,试说明∠CBD=
∠BAC的理由
解:过点A作AE⊥BC,垂足为点E,
则∠AEC=90°( )
在△AEC中,∠AEC+∠EAC+∠C=180°( )
所以∠EAC+∠C=90°( )
因为BD是AC边上的高(已知)
所以∠BDA=______________(三角形高的意义)
因为∠BDA=∠CBD+∠C( )
所以∠C+∠CBD=90°(等量代换)
所以∠EAC=∠CBD( )
因为AB=AC(已知),AE⊥BC(已作)
所以∠EAC=
∠BAC( )
所以∠CBD=
∠BAC(等量代换)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f89eef3148f2d4d09379767b4af69132.png)
解:过点A作AE⊥BC,垂足为点E,
则∠AEC=90°( )
在△AEC中,∠AEC+∠EAC+∠C=180°( )
所以∠EAC+∠C=90°( )
因为BD是AC边上的高(已知)
所以∠BDA=______________(三角形高的意义)
因为∠BDA=∠CBD+∠C( )
所以∠C+∠CBD=90°(等量代换)
所以∠EAC=∠CBD( )
因为AB=AC(已知),AE⊥BC(已作)
所以∠EAC=
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f89eef3148f2d4d09379767b4af69132.png)
所以∠CBD=
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f89eef3148f2d4d09379767b4af69132.png)
![](https://img.xkw.com/dksih/QBM/2019/6/13/2224913076191232/2228049583316992/STEM/29f052ada4d74907b4fc09e36a9b1583.png?resizew=165)
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