如图,
、
分别是
的高和角平分线,
,
,求
的度数.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9d78abbad68bbbf12af10cd40ef4c353.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4eedae8d316c76e3d0b451256de03fb9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15c0dbe3c080c4c4636c64803e5c1f76.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0f3018c687427b6257767eda4a8c6612.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/284e282bb1d9fbf8634b3506ee5358ab.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1384d0a02d097ac7aa8a19e8da6f9767.png)
更新时间:2024-05-05 22:31:33
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解答题-问答题
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【推荐1】如图,在
中,
于点D,
平分
.
(1)若
,求
的度数;
(2)若
,
,求
的度数(用含
、
的式子来表示).
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15c0dbe3c080c4c4636c64803e5c1f76.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8b5f215a42c4b7078d8d65923eb9980e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/68a83fdd2ba72a2dba0b6b10bb3e06b9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7cbce11aa19b8bd2bf6ee5a834e005de.png)
![](https://img.xkw.com/dksih/QBM/editorImg/2023/12/3/cf1c4838-2bd5-43e9-97b1-16725e2c5d24.jpg?resizew=125)
(1)若
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/eeadc201de3b6511b72e880f0dbb684e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1e37b078d02601f76f0f8320b410809f.png)
(2)若
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/148cdaa1d55e9a3d940a4af77610cade.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2883e8d5eb46991be74fa91633aa65d5.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1e37b078d02601f76f0f8320b410809f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e170f206fdbbd834aad7580c727e2cc6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5b5858ee1ce52b251816757257a11c29.png)
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【推荐2】如图,△ABC中,AD是BC边上的高线,BE是一条角平分线,AD、BE相交于点P,已知∠EPD=125°,求∠BAD的度数.
![](https://img.xkw.com/dksih/QBM/2018/3/30/1913176415305728/1915513364037632/STEM/338c5468cbce47c8aafc37bbd10d25a1.png?resizew=168)
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【推荐1】如图,△ABC中CD⊥AB于点D,CE平分∠ACB,点F在AC的延长线上,过点C作直线MN∥AB,且∠ACM=58°,∠BCN=36°.
(1)求∠BCF的度数;
(2)求∠DCE的度数.
(1)求∠BCF的度数;
(2)求∠DCE的度数.
![](https://img.xkw.com/dksih/QBM/2021/8/20/2790008942436352/2791174699180032/STEM/0803f6f07cd942cf9eb8562d4911521c.png?resizew=181)
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【推荐2】小明在学习过程中,对教材中的一个有趣问题做如图探究:
![](https://img.xkw.com/dksih/QBM/2022/9/22/3071988154327040/3091626167541760/STEM/bb1266dbd3ba4979a38c5479b9e4e7ff.png?resizew=313)
(1)[习题回顾]:已知:如图1,在△ABC中,∠ACB=90°,AE是角平分线,CD是高,AE、CD相交于点F.试说明:∠CFE=∠CEF;
(2)[变式思考]:如图2,在△ABC中,∠ACB=90°,CD是AB边上的高,△ABC的外角∠BAG的平分线AF交CD的延长线于点F,AF的反向延长线与BC边的延长线交于点E,若∠B=40°,求∠CEF和∠CFE的度数.
![](https://img.xkw.com/dksih/QBM/2022/9/22/3071988154327040/3091626167541760/STEM/bb1266dbd3ba4979a38c5479b9e4e7ff.png?resizew=313)
(1)[习题回顾]:已知:如图1,在△ABC中,∠ACB=90°,AE是角平分线,CD是高,AE、CD相交于点F.试说明:∠CFE=∠CEF;
(2)[变式思考]:如图2,在△ABC中,∠ACB=90°,CD是AB边上的高,△ABC的外角∠BAG的平分线AF交CD的延长线于点F,AF的反向延长线与BC边的延长线交于点E,若∠B=40°,求∠CEF和∠CFE的度数.
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