已知圆锥
的底面半径
长度为1,母线
的长度为2,球
与圆锥的侧面相切,切于底面圆心H,球
与球
、圆锥的底面和侧面均相切,球
与球
、圆锥的底面和侧面均相切,照此规律进行下去,得到一系列球
,且球
与圆锥底面的切点均在半径
上,记球
的半径为
,表面积为
,则![](https://staticzujuan.xkw.com/quesimg/Upload/formula/576d5a0b998d633ce26ffa094e6a85d9.png)
______ ,![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a7973bece8d07cb2fc87e26e1f0d3fa3.png)
______ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/35d58f9019097bd05037aefd5c322916.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/184921a45f87423e92cf1e627ad55143.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/bd33764ff4efddfe11a98a609753715c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/23f919bd3dde10dbbc076f7ec5149699.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3c4f6f74444b2b7947fc6e35c8d62322.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/23f919bd3dde10dbbc076f7ec5149699.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6dacb04fa29178c0af4353e4369a7e69.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3c4f6f74444b2b7947fc6e35c8d62322.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c944959a02da95b7d6eda7518d63d857.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c944959a02da95b7d6eda7518d63d857.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/184921a45f87423e92cf1e627ad55143.png)
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![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a135cb036833400f3fa1edc92d5ce410.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/08eb71ecf8d733b6932f4680874dbbf3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/576d5a0b998d633ce26ffa094e6a85d9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a7973bece8d07cb2fc87e26e1f0d3fa3.png)
![](https://img.xkw.com/dksih/QBM/editorImg/2022/11/23/93f51ff4-9ac6-4fbf-9f10-6feeeba0f3a9.jpg?resizew=158)
更新时间:2020-07-16 08:10:11
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解题方法
【推荐1】已知数列
:
的前
项和为
,则![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b916d8017d0c8ca772dfec81ce68c6b8.png)
_______ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/83cf38189d5cbf627d2b82ac0eb76006.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9252a07dec2c5d4b1ba6c4d2a737848a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b6a24198bd04c29321ae5dc5a28fe421.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/08eb71ecf8d733b6932f4680874dbbf3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b916d8017d0c8ca772dfec81ce68c6b8.png)
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【推荐2】记
上的可导函数
的导函数为
,满足
的数列
称为“牛顿数列”.若函数
,且
,数列
为牛顿数列.设
,已知
,则![](https://staticzujuan.xkw.com/quesimg/Upload/formula/af9bbe98100c8067ff36ac536d043a85.png)
______ ,数列
的前
项和为
,若不等式
对任意的
恒成立,则
的最大值为______ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/cf3ed15aa3dcc4211fb520b5b942c989.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/09f86f37ec8e15846bd731ab4fcdbacd.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/724340d69477c0ec2418c392b22b1cab.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/33610d2a46105e3c8456257221d3d07b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e976c0663fa749ca749f99842d21ca03.png)
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![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7bd2d9c376d608c2a5cef50e0acd006f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/af9bbe98100c8067ff36ac536d043a85.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/83cf38189d5cbf627d2b82ac0eb76006.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b6a24198bd04c29321ae5dc5a28fe421.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/08eb71ecf8d733b6932f4680874dbbf3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b38f76ec3596e138bcc09945c6fbde96.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/930bc56406e69b785b37a83d48e36724.png)
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【推荐1】如图,用一个平面去截圆锥,得到的截口曲线是椭圆.在圆锥内放两个大小不同的球,使得它们分别与圆锥的侧面相切.椭圆截面与两球相切于椭圆的两个焦点
,
.过椭圆上一点
作圆锥的母线,分别与两个球相切于点
.由球和圆的几何性质可知,
,
.已知两球半径分为别
和
,椭圆的离心率为
,则两球的球心距离为_______________ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f5076289823db419f94e9c0c8f4aafd9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a3fb78c5f885034612c0e030b920143d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dad2a36927223bd70f426ba06aea4b45.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7789a500686c7a73770404ead6af0590.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/cc7fff1c966e2fa450a93e8c24d40b22.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/eb229aa7bc3e94f6f73d1b085a418269.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/bdaa19de263700a15fcf213d64a8cd57.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5ca7d1107389675d32b56ec097464c14.png)
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【推荐2】半径为
的球被平面截下的部分叫做球缺,垂直于截面的直径被截后的线段叫做球缺的高
,球缺的体积公式为
.已知圆锥
的轴截面是边长为2的正三角形,在圆锥内部放置一个小球
,使其与圆锥侧面和底面都相切,过小球与圆锥侧面的切点所在的平面将小球分成两部分,则较小部分的球缺的体积与球
的体积之比为_______ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/11bc05f41215f9894e11d1df0465751a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3eabd5f3a86afe49dcd70571e2b96cfd.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/41b11bbf1a80154eb6aafec797c7cfab.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/18e5ef91fb27dd684a27ae7f1993cfba.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/12fe32dfbd66709875c5b9f79c9496da.png)
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【推荐3】南北朝时期的伟大数学家祖暅在数学上有突出贡献,他在实践的基础上提出祖暅原理:“幂势既同,则积不容异”.其含义是:夹在两个平行平面之间的两个几何体,被平行于这两个平行平面的任意平面所截,如果截得两个截面的面积总相等,那么这两个几何体的体积相等.已知曲线
,直线
为曲线
在点
处的切线,如图所示,阴影部分为曲线
,直线
以及
轴所围成的平面图形,记该平面图形绕
轴旋转一周所得的几何体为
.过点
作
的水平截面,所得截面面积是______ (用
表示).试借助一个圆锥,并利用祖暅原理,得出
的体积是______ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/fc7ad3432ac96b0a38beaa7f2edc3499.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0f85fca60a11e1af2bf50138d0e3fe62.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c5db41a1f31d6baee7c69990811edb9f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/aa00c1c5523913141d43d0f1ad92a4c8.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c5db41a1f31d6baee7c69990811edb9f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0f85fca60a11e1af2bf50138d0e3fe62.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/81dea63b8ce3e51adf66cf7b9982a248.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d053b14c8588eee2acbbe44fc37a6886.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b52b4f24969673c863b5aff4fb6751ce.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0dd652548a38341692019efe4f0e294f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b52b4f24969673c863b5aff4fb6751ce.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d053b14c8588eee2acbbe44fc37a6886.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b52b4f24969673c863b5aff4fb6751ce.png)
![](https://img.xkw.com/dksih/QBM/2021/5/2/2712253761314816/2716161444339712/STEM/c61d5ecf81aa4e499a912f37cd69a517.png?resizew=463)
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解题方法
【推荐1】矩形
中,
,现将
沿对角线
向上翻折,得到四面体
,则该四面体外接球的表面积为______ ;若翻折过程中
的长度在
范围内变化,则点
的运动轨迹的长度是______ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411b38a18046fea8e9fab1f9f9b80a5f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2587e6d16d316d57e5e6836413489bec.png)
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![](https://staticzujuan.xkw.com/quesimg/Upload/formula/60ef95894ceebaf236170e8832dcf7e3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d4357d5744046d4d44abb09e1ee35fcb.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d40b319212a7e7528b053e1c7097e966.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1e3002aba1e3ab8b58dcb36e629d3d73.png)
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【推荐2】如图1,在一个正方形S1S2S3S4内,有一个小正方形和四个全等的等边三角形.将四个等边三角形折起来,使S1、S2、S3、S4重合于点S,且折叠后的四棱锥S-ABCD的外接球的表面积是16π(如图2),则四棱锥S-ABCD的体积是___________ ;若在四棱锥S-ABCD内放一个正方体,使正方体可以在四棱锥S-ABCD内任意转动,则正方体棱长的最大值为___________ .
![](https://img.xkw.com/dksih/QBM/2022/1/25/2902193765310464/2918165220016128/STEM/8780457b-dea4-4283-92c6-4e0a391fb955.png?resizew=310)
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