如图,正方形ABCD中,点E是对角线BD上一点,且BE=2DE,连接AE并延长交CD于G,点F是BC边上一点,且CF=2BF,连接AF、EF、FG.下列四个结论:①DG=CG;②AF=AG;③S△ABF=S△FCG;④AE=EF.其中正确的结论是 ___ .(写出所有正确结论的序号)
![](https://img.xkw.com/dksih/QBM/editorImg/2022/8/17/c6765b58-06f5-4da3-8f1d-f45515259d2a.png?resizew=150)
更新时间:2021-11-01 12:51:21
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