在等边△ABC中,P,Q是BC边上两点(不与B,C重合),点P在点Q的左侧,且AP=AQ.
![](https://img.xkw.com/dksih/QBM/editorImg/2022/9/21/f4574dcd-4f02-483d-8e0b-4bcc8e7f2917.png?resizew=416)
(1)如图1,若∠BAP=20°,求∠AQB的度数;
(2)如图2,点Q关于直线AC的对称点为M,连接AM,PM.
①依题意将图2补全;
②求证:PA=PM.
![](https://img.xkw.com/dksih/QBM/editorImg/2022/9/21/f4574dcd-4f02-483d-8e0b-4bcc8e7f2917.png?resizew=416)
(1)如图1,若∠BAP=20°,求∠AQB的度数;
(2)如图2,点Q关于直线AC的对称点为M,连接AM,PM.
①依题意将图2补全;
②求证:PA=PM.
更新时间:2022-02-19 13:11:26
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相似题推荐
解答题-证明题
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【推荐1】如图,
,
,
,点
在线段
上.
![](https://img.xkw.com/dksih/QBM/editorImg/2024/3/6/8d6200af-4459-4332-bf3b-e9cb56e0a80d.png?resizew=168)
(1)求证:
;
(2)求
的度数.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d5adc18ca424552b35ab939e9d57943e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/984c1cdb454d47d5f5278593aa08fc89.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1beff025b32f688316009552d2fd8e1a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2a30f3a8b673cc28bd90c50cf1a35281.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0dc5c9827dfd0be5a9c85962d6ccbfb1.png)
![](https://img.xkw.com/dksih/QBM/editorImg/2024/3/6/8d6200af-4459-4332-bf3b-e9cb56e0a80d.png?resizew=168)
(1)求证:
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ef7894c7a063cfbbc8bf41c30775a69b.png)
(2)求
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4598486f8c5ac28b1165b76e78105979.png)
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【推荐2】一个三角形纸片ABC沿DE折叠,使点A落在点A′处.(点A′在△ABC的内部)
![](https://img.xkw.com/dksih/QBM/editorImg/2022/10/21/a0521df0-1d3a-4e2c-95f6-61f9d36803e5.png?resizew=307)
(1)如图1,若∠A=45°,则∠1+∠2= °.
(2)利用图1,探索∠1,∠2与∠A之间的数量关系,并说明理由.
(3)如图2,把△ABC折叠后,BA′平分∠ABC,CA′平分∠ACB,若∠1+∠2=108°,利用(2)中得出的结论求∠BA′C的度数.
![](https://img.xkw.com/dksih/QBM/editorImg/2022/10/21/a0521df0-1d3a-4e2c-95f6-61f9d36803e5.png?resizew=307)
(1)如图1,若∠A=45°,则∠1+∠2= °.
(2)利用图1,探索∠1,∠2与∠A之间的数量关系,并说明理由.
(3)如图2,把△ABC折叠后,BA′平分∠ABC,CA′平分∠ACB,若∠1+∠2=108°,利用(2)中得出的结论求∠BA′C的度数.
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【推荐1】如图:在直角
中,
,点D在
边上,连接
.
![](https://img.xkw.com/dksih/QBM/editorImg/2022/11/3/64d4c713-af49-401e-94c2-a26e0492dc43.png?resizew=440)
(1)如图1,若
是
的角平分线,且
,探究
与
的数量关系,说明理由;
(2)如图2,若
,
于点F,交
于点G,点E在
的延长线上且
,连接
,求证:
.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15c0dbe3c080c4c4636c64803e5c1f76.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c0e2347966b716391fd2c3a443763e8e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b79dd200766db27fb90d6bd1992cf658.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e1ffb98f1e3c1317c0db403d3af04bdc.png)
![](https://img.xkw.com/dksih/QBM/editorImg/2022/11/3/64d4c713-af49-401e-94c2-a26e0492dc43.png?resizew=440)
(1)如图1,若
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e1ffb98f1e3c1317c0db403d3af04bdc.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8fabb884dc5f9609de491245463bbe9a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/89a6e9864194f5b8d6e0dc534376aef5.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/764509115979e9958101808383672ec0.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e1a9c6a736e6eac98a676fa3232db5a5.png)
(2)如图2,若
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2398c0ed4fe3aef9355d3763d8199a20.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8f2a245381e615882ee5feb7793a1df6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e1ffb98f1e3c1317c0db403d3af04bdc.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b79dd200766db27fb90d6bd1992cf658.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ff654d578b8f29ad7a8b436235a5d68b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a37911e56b9180699c76cc0eba7fe5c3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/212e5082ecc5c980762b06dddbe703dc.png)
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【推荐2】如图,在四边形ABCD中,AD∥BC,∠ABC=90°,AD=CD,O是对角线AC的中点,连接BO并延长交边CD于点E.
![](https://img.xkw.com/dksih/QBM/editorImg/2022/12/14/12f449ea-442e-4922-ae46-85eb6ad8efb5.png?resizew=149)
(1)求证:△DAC∽△OBC;
(2)若BE⊥CD,求
的值.
![](https://img.xkw.com/dksih/QBM/editorImg/2022/12/14/12f449ea-442e-4922-ae46-85eb6ad8efb5.png?resizew=149)
(1)求证:△DAC∽△OBC;
(2)若BE⊥CD,求
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/606ff826406d9fc8403d365762cd9e4c.png)
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【推荐3】【问题探究】如图1,锐角△ABC中,分别以AB、AC为边向外作等腰直角△ABE和等腰直角△ACD,使AE=AB,AD=AC,∠BAE=∠CAD=90°,连接BD,CE,试猜想BD与CE的大小关系,不需要证明.
![](https://img.xkw.com/dksih/QBM/2022/4/18/2960644832034816/2961510655361024/STEM/6b5e1b8c-8ad5-47ad-b728-630c17ed75fa.png?resizew=179)
【深入探究】如图2,锐角△ABC中,以AB为边在AB的右侧作等腰直角△ABE,以AC为边在AC的左侧作等腰直角△ACD,使AE=AB,AD=AC,∠BAE=∠CAD=90°,连接BD,CE,试猜想BD与CE的大小关系,并说明理由.
![](https://img.xkw.com/dksih/QBM/2022/4/18/2960644832034816/2961510655361024/STEM/ab128f83-9b47-4cf0-aa84-3f9e23257445.png?resizew=181)
【变式思考】(1)如图1,四边形ABCD中,AB=2
cm,BC=2cm,∠ABC=∠ACD=∠ADC=45°,则BD的长=______.(直接写出答案)
![](https://img.xkw.com/dksih/QBM/2022/4/18/2960644832034816/2961510655361024/STEM/77db57ec-7f72-4ee6-9a5f-6de3f9a308d3.png?resizew=173)
(2)如图3,在(1)的条件下,当△ACD在线段AC的左侧时,请求出BD的长.
![](https://img.xkw.com/dksih/QBM/2022/4/18/2960644832034816/2961510655361024/STEM/6b5e1b8c-8ad5-47ad-b728-630c17ed75fa.png?resizew=179)
【深入探究】如图2,锐角△ABC中,以AB为边在AB的右侧作等腰直角△ABE,以AC为边在AC的左侧作等腰直角△ACD,使AE=AB,AD=AC,∠BAE=∠CAD=90°,连接BD,CE,试猜想BD与CE的大小关系,并说明理由.
![](https://img.xkw.com/dksih/QBM/2022/4/18/2960644832034816/2961510655361024/STEM/ab128f83-9b47-4cf0-aa84-3f9e23257445.png?resizew=181)
【变式思考】(1)如图1,四边形ABCD中,AB=2
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/cf298f00799cbf34b4db26f5f63af92f.png)
![](https://img.xkw.com/dksih/QBM/2022/4/18/2960644832034816/2961510655361024/STEM/77db57ec-7f72-4ee6-9a5f-6de3f9a308d3.png?resizew=173)
(2)如图3,在(1)的条件下,当△ACD在线段AC的左侧时,请求出BD的长.
![](https://img.xkw.com/dksih/QBM/2022/4/18/2960644832034816/2961510655361024/STEM/35c730db-b1c9-4693-afb8-c35e05f1363b.png?resizew=128)
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【推荐1】如图,P是等边
内的一点,
,将线段
绕点B逆时针方向旋转
得到线段
,连接
.
![](https://img.xkw.com/dksih/QBM/2024/3/7/3448474622795776/3448671309463552/STEM/dfd51053c2af4c53bce7bdde47f304c9.png?resizew=139)
(1)判断
的形状,并说明理由.
(2)求
的度数.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15c0dbe3c080c4c4636c64803e5c1f76.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e51ebe31c9801764ed91a6feeec96da6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d2be49c37e30a3ced0364c3e74d8c687.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/be6a6301878fed2a01413020b27310a5.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/70c733c8bb6ee8666dc5477d5fb8c6ab.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a7eb2fca7063066e90e4cd7b1006eb34.png)
![](https://img.xkw.com/dksih/QBM/2024/3/7/3448474622795776/3448671309463552/STEM/dfd51053c2af4c53bce7bdde47f304c9.png?resizew=139)
(1)判断
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c8e6ceca9d08093ea22df1506bb99be0.png)
(2)求
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ef0433f8116768b42642a7f7e5977ce6.png)
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【推荐2】已知:如图1,
中,D为AC边上一点,连接BD,
,点E为AB边上一点,连接CE与BD交于点F,且点F为CE中点.
![](https://img.xkw.com/dksih/QBM/editorImg/2022/9/25/306ffc32-071e-447b-aa8a-226ab087b751.png?resizew=392)
(1)求证:
.
(2)若
,点E为AB中点,点P是DB延长线上一点,且
,连接PE并延长交AC于点Q,
,在图2中补全图形并求PE的长.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15c0dbe3c080c4c4636c64803e5c1f76.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ba31b85739b8e16e4839d0a31d569c0f.png)
![](https://img.xkw.com/dksih/QBM/editorImg/2022/9/25/306ffc32-071e-447b-aa8a-226ab087b751.png?resizew=392)
(1)求证:
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/024dc2ccbbe321774df5d44e8785b203.png)
(2)若
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3f5fc4ad65b723b6a8da4c8dac154e6e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/75b5d4c7feb93c8ee84f1b3c39f73ce0.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4d46e3cdfe9ddecb0e02342d9ffc0705.png)
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【推荐1】如图,AD是
的高,点B关于直线AC的对称点为E,连接CE,F为线段CE上—点(不与点E重合),
.
![](https://img.xkw.com/dksih/QBM/2022/1/11/2892417537515520/2895005367107584/STEM/84e6ea194bfd4825aa417c6bee7731a8.png?resizew=455)
(1)比较
与
的大小;
(2)用等式表示线段BD,EF的数量关系,并证明.
(3)连接BF,取BF的中点M,连接DM.判断DM与AC的位置关系,并证明.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15c0dbe3c080c4c4636c64803e5c1f76.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/14833dbeed409b33acd4c9071fd0be36.png)
![](https://img.xkw.com/dksih/QBM/2022/1/11/2892417537515520/2895005367107584/STEM/84e6ea194bfd4825aa417c6bee7731a8.png?resizew=455)
(1)比较
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/13a2e6494cf8d2dff0746a9bb72cef43.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d39b8d91afc34e4a9b0fdbb6bafb9087.png)
(2)用等式表示线段BD,EF的数量关系,并证明.
(3)连接BF,取BF的中点M,连接DM.判断DM与AC的位置关系,并证明.
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【推荐2】如今,露营成为一种非常流行的休闲方式,为了遮阳和防雨会搭建一种“天幕”,其截面示意图是轴对称图形,对称轴是垂直于地面的支杆
,且
,用绳子拉直
后系在树干
上的点E处,使得点A,D,E在一条直线上,通过调节点E的高度可控制“天幕”的开合,若
,求点E的高度
.(结果精确到
,参考数据:
)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f52a58fbaf4fea03567e88a9f0f6e37e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d82700926f46ae833a66de60b6e1b92f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/03902478df1a55bc99703210bccab910.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/49b50357a6545cae8348e3059312f520.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a7e722ba9b709528bdc0333a881b3117.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/49b50357a6545cae8348e3059312f520.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/bfaa19eeaf415ed419e77fe92794f443.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d52df28029dbf9418dfec713920b2587.png)
![](https://img.xkw.com/dksih/QBM/editorImg/2024/4/5/775f130c-8c71-4478-99e2-d0f79e363d3c.png?resizew=157)
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