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1 . 平面几何中有一定理如下:三角形任意一个顶点到其垂心(三角形三条高所在直线的交点)的距离等于外心(外接圆圆心)到该顶点对边距离的2倍.已知
的垂心为D,外心为E,D和E关于原点O对称,
.
(1)若
,点B在第二象限,直线
轴,求点B的坐标;
(2)若A,D,E三点共线,椭圆T:
与
内切,证明:D,E为椭圆T的两个焦点.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15c0dbe3c080c4c4636c64803e5c1f76.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c24e12c97516329a6776fe48c450d93b.png)
(1)若
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/25c8ef6f3640bd70e40f3b591c8bcc14.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/05b45db8dd8768994af51206565379fd.png)
(2)若A,D,E三点共线,椭圆T:
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7dd54b9df3402ad91e2d34c40efe0c7a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15c0dbe3c080c4c4636c64803e5c1f76.png)
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2024-05-20更新
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4卷引用:河北省保定市九校2024届高三下学期二模数学试题