1 . 现有一张长为
,宽为
(
)的长方形铁皮
,准备用它做成一个无盖长方体铁皮容器,要求材料利用率为100%,不考虑焊接处损失.如图,在长方形
的一个角上剪下一块边长为
的正方形铁皮,作为铁皮容器的底面,用余下材料剪拼后作为铁皮容器的侧面,设长方体的高为
,体积为
.
(Ⅰ)求
关于
的函数关系式;
(Ⅱ)求该铁皮容器体积
的最大值.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dd8a1eba08105f302efdbf7a88783d44.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8e831bff707e76cf3aebf426b13d18d4.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d4b79610dc644ce35a837abfb848376e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411b38a18046fea8e9fab1f9f9b80a5f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411b38a18046fea8e9fab1f9f9b80a5f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4da6a52e3eb6cef810c7770b8e53fdcf.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b2a8e2712494bc2022c30d37e395cf10.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/04b785a4b6636ed1f145ed8f7e3a0fef.png)
(Ⅰ)求
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d053b14c8588eee2acbbe44fc37a6886.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/81dea63b8ce3e51adf66cf7b9982a248.png)
(Ⅱ)求该铁皮容器体积
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/be54e84508decfcce6d2fcbe6c8c1a92.png)
![](https://img.xkw.com/dksih/QBM/2017/8/17/1754071406075904/1754141751353344/STEM/ae357ce9d449461db7e01cab4b908455.png?resizew=129)
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解题方法
2 . 要做一个圆锥形的漏斗,其母线长为20cm,当其体积最大时,底面半径和高分别为多少?
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3 . 要做一个圆锥形漏斗,其母线长为20cm,要使其体积最大,则高为( )
A.![]() | B.![]() | C.![]() | D.![]() |
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2017-07-16更新
|
567次组卷
|
7卷引用:山西省应县一中2016-2017学年高二下学期3月月考数学(理)试题
名校
解题方法
4 . 如图,有一边长为
的正方形铁片,在铁片的四角各截去一个边长为
的小正方形后,沿图中虚线部分折起,做成一个无盖方盒.
![](https://img.xkw.com/dksih/QBM/2017/7/4/1723017036963840/1724323404636160/STEM/88d0d14bf96b42fdbf7dacb09988c682.png?resizew=98)
(1)试用
表示方盒的容积
,并写出
的范围;
(2)求方盒容积
的最大值及相应
的值.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6f8c4c029e552954bd493b49aeab82d5.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/81dea63b8ce3e51adf66cf7b9982a248.png)
![](https://img.xkw.com/dksih/QBM/2017/7/4/1723017036963840/1724323404636160/STEM/88d0d14bf96b42fdbf7dacb09988c682.png?resizew=98)
(1)试用
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/81dea63b8ce3e51adf66cf7b9982a248.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e766305fcae007508b086d27cf73bd5d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/81dea63b8ce3e51adf66cf7b9982a248.png)
(2)求方盒容积
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e766305fcae007508b086d27cf73bd5d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/81dea63b8ce3e51adf66cf7b9982a248.png)
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2017-07-06更新
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908次组卷
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2卷引用:湖北省孝感市七校教学联盟2016-2017学年高二下学期期末考试数学(文)试题
5 . 圆柱形金属饮料罐容积一定时,它的高(
)与半径(
)应怎样选择,才能使所用材料最省?
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3eabd5f3a86afe49dcd70571e2b96cfd.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4aa0df7f1e45f9de29e802c7f19a4f64.png)
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解题方法
6 . 如图,在半径为30cm的半圆形铁皮上截取一块矩形材料
点A,B在直径上,点C,D在半圆周上
,并将其卷成一个以AD为母线的圆柱体罐子的侧面
不计剪裁和拼接损耗
.
![](https://img.xkw.com/dksih/QBM/editorImg/2022/8/21/dd50f37f-e5ab-420a-ad48-de43a434525d.png?resizew=163)
(1)若要求圆柱体罐子的侧面积最大,应如何截取?
(2)若要求圆柱体罐子的体积最大,应如何截取?
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2118e5d9ce2fb68b4d2970176ff79251.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/04582116cd765fcc5a52f44279ad6c94.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/fd995178601c2ad7b40f973d268c7bb7.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/04582116cd765fcc5a52f44279ad6c94.png)
![](https://img.xkw.com/dksih/QBM/editorImg/2022/8/21/dd50f37f-e5ab-420a-ad48-de43a434525d.png?resizew=163)
(1)若要求圆柱体罐子的侧面积最大,应如何截取?
(2)若要求圆柱体罐子的体积最大,应如何截取?
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2017-06-02更新
|
891次组卷
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4卷引用:【市级联考】广东省中山市2018-2019学年高二上学期期末考试数学(理)试题
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解题方法
7 . 如图是一块地皮
,其中
,
是直线段,曲线段
是抛物线的一部分,且点
是该抛物线的顶点,
所在的直线是该抛物线的对称轴.经测量,
km,
km,
.现要从这块地皮中划一个矩形
来建造草坪,其中点
在曲线段
上,点
,
在直线段
上,点
在直线段
上,设
km,矩形草坪
的面积为
km2.
![](https://img.xkw.com/dksih/QBM/2017/5/27/1695796686774272/1695906734637056/STEM/9f89ab7aabc945ea8d0314ca587c145a.png?resizew=199)
(1)求
,并写出定义域;
(2)当
为多少时,矩形草坪
的面积最大?
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9a44aa6beb0b8948618d252e7b765de6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ae7a3e520a16d4fdd73c4e6a4ce7be0e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b79dd200766db27fb90d6bd1992cf658.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d62e8aadaadebf1454fde21a390ebdea.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1dde8112e8eb968fd042418dd632759e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ae7a3e520a16d4fdd73c4e6a4ce7be0e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/def4f2e101a80da9bec891ee951b5022.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/510cad489ea9604845d41a1795b2b7e3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ab1c418c847ac26d0db60d587edfdc30.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/779c26a41987ef67c2f09812c4f15ac4.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c5db41a1f31d6baee7c69990811edb9f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d62e8aadaadebf1454fde21a390ebdea.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8455657dde27aabe6adb7b188e031c11.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2a30f3a8b673cc28bd90c50cf1a35281.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ae7a3e520a16d4fdd73c4e6a4ce7be0e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a0ed1ec316bc54c37c4286c208f55667.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b79dd200766db27fb90d6bd1992cf658.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f706aae1ab18d347033dcdd4c3ddc1fb.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/779c26a41987ef67c2f09812c4f15ac4.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9b66cc2aec27971dd907615fde4173b0.png)
![](https://img.xkw.com/dksih/QBM/2017/5/27/1695796686774272/1695906734637056/STEM/9f89ab7aabc945ea8d0314ca587c145a.png?resizew=199)
(1)求
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9b66cc2aec27971dd907615fde4173b0.png)
(2)当
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0a6936d370d6a238a608ca56f87198de.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/779c26a41987ef67c2f09812c4f15ac4.png)
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2017-05-27更新
|
882次组卷
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6卷引用:江苏省泰州中学2017-2018学年高二12月月考数学试题
江苏省泰州中学2017-2018学年高二12月月考数学试题贵州省铜仁市伟才学校2017-2018学年高二3月份月考数学(理)试题江苏省徐州市2017届高三信息卷数学(理)试题江苏省徐州市2017届高三信息卷数学试题江苏省扬州市江都中学2019-2020学年度高三上学期数学第一次学情调研考试试题卷(已下线)数学-2020年高考数学押题预测卷03(江苏卷)《2020年高考押题预测卷》
8 . 已知正四棱锥
中,
,那么当该棱锥的体积最大时,它的高为__________ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/faeb97acf19bd3b2c6c77c2814df4d2f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2fb9a768239f8efec81d9ef718c585c8.png)
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2017-05-18更新
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6卷引用:重庆市巴蜀中学2018-2019学年高二上学期期末复习模拟题(1)(文科)数学试题
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9 . 如图,由
围成的曲边三角形,在曲线
弧上求一点
,使得过
所作的
的切线
与
围城的三角形
的面积最大,并求得最大值.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/febed000c8420f772768354c326a2cf9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b90e0f35eda1a729fed485f83da5ea9d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ac047e91852b91af639feec23a9598b2.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ac047e91852b91af639feec23a9598b2.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/344ccbf79da6ad7e3709d6fa72efb756.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7a5f1641947153c80b987320885a2b57.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5c87b8e05d61ddc69dbc02772d719d2e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1685f39771b21ab0e9fc5f4abe4aa144.png)
![](https://img.xkw.com/dksih/QBM/2017/2/16/1625386780647424/1664945024081920/STEM/81f6250a80d540459eca534d8f3109af.png?resizew=155)
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2017-04-13更新
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373次组卷
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3卷引用:2016-2017学年海南省海南中学高二上学期期末考试数学(文)试卷
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10 . 现有一段长为
的铁丝,要把它围成一个底面一边长为另一边长2倍的长方体形状的框架,当长方体体积最大时,底面的较短边长是
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/19d4166fee97516ad1b1d4759a8e4ce6.png)
A.![]() | B.![]() | C.![]() | D.![]() |
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