明朝程大位的《算法统宗》中有首依等算钞歌:“甲乙丙丁戊己庚,七人钱本不均分,甲乙念三七钱钞,念六一钱戊已庚,惟有丙丁钱无数,要依等第数分明,请问先生能算者,细推详算莫差争.”大意是:“现有甲、乙、丙、丁、戊、己、庚七人,他们手里钱不一样多,依次成等差数列,已知甲、乙两人共237钱,戊、已、庚三人共261钱,求各人钱数.”根据题目的已知条件,乙有( )
A.122钱 | B.115钱 | C.108钱 | D.107钱 |
更新时间:2022-03-12 23:20:40
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【知识点】 等差数列通项公式的基本量计算
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【推荐1】已知
是首项为
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【推荐2】在等差数列
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