综合与实践
综合与实践课上,老师让同学们以“中点”为主题展开讨论.
【问题情景】
如图①,在矩形
中,点O是
边的中点,点M是边
上一动点,点P在线段
上(不与点A重合),且满足
,连接
.
(1)判断
的形状,并说明理由;
(2)如图②,当点M为边
中点时,连接
并延长交
于点N.求证:
;
【问题解决】
(3)在(2)的条件下,若
,作点N关于直线
的对称点
,连接
并延长交矩形的边所在的直线于点E,请直接写出
的长.
综合与实践课上,老师让同学们以“中点”为主题展开讨论.
【问题情景】
如图①,在矩形
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411b38a18046fea8e9fab1f9f9b80a5f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f52a58fbaf4fea03567e88a9f0f6e37e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9e52a8f07834cbbbe4224962672fbbb2.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d50703c46b6153945d718b198f03b4b5.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3b0dcec7555bfdbf4f0e7b7a9cfce964.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2cdba1337ec85fa9722cb4b320a82ae6.png)
(1)判断
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7a855335176fc36a15017f50a8561348.png)
(2)如图②,当点M为边
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9e52a8f07834cbbbe4224962672fbbb2.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/63a253c7fdf589ee3dece13d5b5b5732.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/03902478df1a55bc99703210bccab910.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2b834e4da06ce3803b92bb62273050c9.png)
【问题解决】
(3)在(2)的条件下,若
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b3aee03496362082fa314f751852dcae.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d50703c46b6153945d718b198f03b4b5.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/28b1ba4307cfde9b424d468bfcdf6c5a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5e91df8b5d2d51900151398baf13a15d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4eedae8d316c76e3d0b451256de03fb9.png)
更新时间:2024-05-22 21:08:22
|
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【推荐1】如图,在平面直角坐标系中,直线
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(1)求过O、A、C三点的抛物线的解析式;
(2)求证:
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(1)求过O、A、C三点的抛物线的解析式;
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![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b90e0f35eda1a729fed485f83da5ea9d.png)
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【推荐2】直角三角形中一个锐角的大小与两条边的长度的比值之间有明确的联系,我们用锐角三角比来表示.类似的,在等腰三角形中也可以建立边角之间的联系,我们定义:等腰三角形中底边与腰的长度的比值叫做顶角的正对.如图,在
中,
,顶角A的正对记作
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![](https://img.xkw.com/dksih/QBM/editorImg/2024/6/9/c6df6b40-1d87-42a0-a1de-5e46267645eb.png?resizew=87)
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(1)
的值为( ).
A.
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(2)对于
,
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A.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f89eef3148f2d4d09379767b4af69132.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/860884c0017c8bceb5b0edff796c144f.png)
(2)对于
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/be46c4b7a1b131d4b37fa43f1dcaa6ae.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3818a2c9919d358b4c3713396093822b.png)
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(3)如果
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【推荐2】如图1,在矩形
中,点E为
上一点,沿
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的形状是_________;
(2)若图2中的四边形
是菱形,且
,
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的面积.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411b38a18046fea8e9fab1f9f9b80a5f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0dc5c9827dfd0be5a9c85962d6ccbfb1.png)
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(1)判断图2中四边形
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(2)若图2中的四边形
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【推荐1】如图,在等边△ABC中,点P是BC边上一点,∠BAP=
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②通过截长补短,利用60°角构造等边三角形,进而构造出全等三角形,从而达到转移边的目的.
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![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e170f206fdbbd834aad7580c727e2cc6.png)
(1)依题意补全图形,并直接写出∠AEB的度数;
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分析:①涉及的知识要素:图形轴对称的性质;等边三角形的性质;全等三角形的判定与性质……
②通过截长补短,利用60°角构造等边三角形,进而构造出全等三角形,从而达到转移边的目的.
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![](https://img.xkw.com/dksih/QBM/2022/1/11/2892225726160896/2892914781208576/STEM/4812bfb1-25e1-426d-8442-d7175d1c8feb.png?resizew=169)
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解答题-作图题
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【推荐2】请仅用无刻度的直尺完成下列画图,不写画法,保留画图痕迹.
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【推荐1】如图,在等腰Rt△ABC中,∠C=90°,AC=4,矩形DEFG的顶点D、G分别在AC、BC上,边EF在AB上.
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【推荐2】如图,在锐角
中,以
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作
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(2)若
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![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5df7626240940eb340420a605e95aeee.png)
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