如图,在
中,点D、E在
上,
.
,②
中,选择一个作为条件,另外一个作为结论,构成一个真命题,并证明; 条件: , 结论: (填序号).
(2)在(1)的条件下,当
时, 求
的度数.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15c0dbe3c080c4c4636c64803e5c1f76.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0dc5c9827dfd0be5a9c85962d6ccbfb1.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f2e629756a5766f170ecce81ab157b1b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/047dc9795efa99b6fb9fdf9778085dab.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e2d212c1709b8e72a055cf1b5381ef64.png)
(2)在(1)的条件下,当
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d2b34233772c4c26d6669499d9b1f15a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7cbce11aa19b8bd2bf6ee5a834e005de.png)
23-24八年级上·江苏泰州·期中 查看更多[5]
江苏省泰州市泰兴市2023-2024学年八年级上学期期中数学学情调查 试卷(已下线)江苏省泰州市姜堰区实验初级中学2023-2024学年八年级上学期数学独立作业12.5(已下线)寒假作业06 等腰(等边)三角形-【寒假分层作业】2024年八年级数学寒假培优练(人教版)(已下线)第01讲 等腰三角形和等边三角形-【寒假自学课】2024年八年级数学寒假提升学与练(北师大版)(已下线)专题01 等腰三角形与直角三角形01(十二种考法)
更新时间:2023-11-20 11:46:31
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【推荐1】如图,在平行四边形ABCD中,
,
,
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【推荐2】已知
中,
,
为
边上一点,
为
边上一点,
,设
,
.
![](https://img.xkw.com/dksih/QBM/editorImg/2024/2/2/d4360e2b-a431-4a83-904a-313f4faa4bd4.png?resizew=192)
(1)如图1,若
,
,求
,
的值;
(2)如图2,若点
是
边上任意一点,则
,
之间有什么数量关系?说明理由.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15c0dbe3c080c4c4636c64803e5c1f76.png)
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(1)如图1,若
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e075468e7fb0bf30229aec01a7205977.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5b64d9d2b7e21497153310e653f89704.png)
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(2)如图2,若点
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8455657dde27aabe6adb7b188e031c11.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0dc5c9827dfd0be5a9c85962d6ccbfb1.png)
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【推荐1】等边△ABC中,F为边BC边上的点,作∠CBE=∠CAF,延长AF与BE交于点D,截取BE=AD,连接CE.
(1) 求证:CE=CD
(2) 求证:DC平分∠ADE
(3) 试判断△CDE的形状,并说明理由.
(1) 求证:CE=CD
(2) 求证:DC平分∠ADE
(3) 试判断△CDE的形状,并说明理由.
![](https://img.xkw.com/dksih/QBM/editorImg/2023/12/19/8ee79e8d-5afa-4805-817d-8707b0026c1f.png?resizew=132)
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【推荐2】已知:如图所示,A、B、C、D在同一直线上,AD=BC,AE=BF,CE=DF,试说明:
(1)DF∥CE;
(2)DE=CF.
(1)DF∥CE;
(2)DE=CF.
![](https://img.xkw.com/dksih/QBM/2020/10/15/2571626879123456/2572798363017216/STEM/d4547b4a-4039-48ee-b376-6f86d0247d53.png)
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【推荐2】如图,
中,
,点
是线段
延长线上一点,
,垂足为
,
交线段
于点
,点
在线段
上,
经过
、
两点,交
于点
.
![](https://img.xkw.com/dksih/QBM/editorImg/2023/3/9/9f346b98-1d98-4489-adf1-6a96f8769ed3.png?resizew=176)
(1)求证:
是
的切线;
(2)若
,
,
,求
的半径.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0faed94a64b2dcfc6801b4fca0f16675.png)
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(1)求证:
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(2)若
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【推荐1】如图,已知点D为等腰直角三角形ABC内一点,AC=BC,∠ACB=90°,∠CAD=∠CBD=15°,E为AD的延长线上的一点,且CE=CA.
(1)求证:DE平分∠BDC;
(2)若点M在DE上,且DC=DM,求证ME=BD.
(1)求证:DE平分∠BDC;
(2)若点M在DE上,且DC=DM,求证ME=BD.
![](https://img.xkw.com/dksih/QBM/2021/11/22/2857012994285568/2858167077888000/STEM/5a048cc1-1b08-40cd-bf4d-ebda5b6065ec.png)
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【推荐2】如图,
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