在平面直角坐标系xOy中,已知圆
,动圆M与直线
相切且与圆F外切.
(1)记圆心M的轨迹为曲线C,求曲线C的方程;
(2)已知
,曲线C上一点P满足
,求
的大小.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2207e059e927c76f82b5af2dd430e620.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b4180dae966f648d368a10edf3b7e3c3.png)
(1)记圆心M的轨迹为曲线C,求曲线C的方程;
(2)已知
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/913f78382630e50543e5f7192cae3ed3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ad50bd00e232f32cf21d2a5dd5c71c11.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/cf34d7984aa53ae3efb6088aeaacc718.png)
更新时间:2020-11-29 22:19:19
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解答题-问答题
|
适中
(0.65)
【推荐1】平面上有一条长度为定值
的线段AB.
(1)到线段AB两个端点距离的平方差为k的点的轨迹是什么图形?说明理由;
(2)到线段AB两个端点距离的平方和为k的点的轨迹是什么图形?说明理由.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c6bdac20e214b2cb3bd07f8d4778dcca.png)
(1)到线段AB两个端点距离的平方差为k的点的轨迹是什么图形?说明理由;
(2)到线段AB两个端点距离的平方和为k的点的轨迹是什么图形?说明理由.
您最近一年使用:0次
【推荐2】已知点
是圆
上的定点,点
是圆内一点,
、
为圆上的动点.
(1)求线段AP的中点
的轨迹方程.
(2)若
,求线段
中点
的轨迹方程.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/448c0a5ee776d19ce8e42ac9a5fd27c4.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a5f5d967ad135991b6075ee45df55643.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/18d3bfa155ad67018da4d65815c5e5b8.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dad2a36927223bd70f426ba06aea4b45.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/acc290b44635265137fdf13146b6a6d9.png)
(1)求线段AP的中点
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ac047e91852b91af639feec23a9598b2.png)
(2)若
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4d7d6b576fe46cb4492515701e893edb.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7a5f1641947153c80b987320885a2b57.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/54a5d7d3b6b63fe5c24c3907b7a8eaa3.png)
您最近一年使用:0次
解答题-证明题
|
适中
(0.65)
【推荐1】已知抛物线Γ的准线方程为
.焦点为
.
(1)求证:抛物线Γ上任意一点
的坐标
都满足方程:![](https://staticzujuan.xkw.com/quesimg/Upload/formula/22d644a7ee7c0b3e9da120480a8ad717.png)
(2)请求出抛物线Γ的对称性和范围,并运用以上方程证明你的结论;
(3)设垂直于
轴的直线与抛物线交于
两点,求线段
的中点
的轨迹方程.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6274852e643a635e7340efa732edddc4.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/632541024f42a0eab66f8e43911db06a.png)
(1)求证:抛物线Γ上任意一点
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dad2a36927223bd70f426ba06aea4b45.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/82a79a33a83a7ba57a34b5093d1d1d02.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/22d644a7ee7c0b3e9da120480a8ad717.png)
(2)请求出抛物线Γ的对称性和范围,并运用以上方程证明你的结论;
(3)设垂直于
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/81dea63b8ce3e51adf66cf7b9982a248.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e52586ca2a3b783bc8092415e2d4bf6d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f52a58fbaf4fea03567e88a9f0f6e37e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ac047e91852b91af639feec23a9598b2.png)
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解答题-问答题
|
适中
(0.65)
解题方法
【推荐2】焦点为
的抛物线
与圆
交于
两点,其中
点横坐标为
,方程
的曲线记为
,
是曲线
上一动点.
在抛物线上且满足
,求直线
的斜率;
(2)
是
轴上一定点. 若动点
在
上满足
的范围内运动时,
恒成立,求
的取值范围;
(3)
是曲线
上另一动点,且满足
,若
的面积为4 ,求线段
的长.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a0ed1ec316bc54c37c4286c208f55667.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ac8a3bffe545af2299cf999d44767206.png)
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![](https://staticzujuan.xkw.com/quesimg/Upload/formula/16e4e4c7a79d9d3cdb9ac5949d53e33e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5963abe8f421bd99a2aaa94831a951e9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/14c97938d07092ac2803ff89a47e5b23.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dcec04cff66ddf1c021d73d6c681ebb7.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4b454cdb97c408300b50d945f002c2cb.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dad2a36927223bd70f426ba06aea4b45.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4b454cdb97c408300b50d945f002c2cb.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dad2a36927223bd70f426ba06aea4b45.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/360d86f0ec1c4d9d0dfc06a9064db0b1.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4fb26d84907c923278ac4626a9d58947.png)
(2)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/388f9a492789afe93cd09bced064e06e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/81dea63b8ce3e51adf66cf7b9982a248.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dad2a36927223bd70f426ba06aea4b45.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4b454cdb97c408300b50d945f002c2cb.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4ff8450b7dd0330a9686594a14baa9f9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9f0b68e4289ee07e6a7d1dbea801aecc.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/294f5ba74cdf695fc9a8a8e52f421328.png)
(3)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/acc290b44635265137fdf13146b6a6d9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4b454cdb97c408300b50d945f002c2cb.png)
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