已知函数f(x)=x3+ax2﹣9x+1(a∈R),当x≠1时,曲线y=f(x)在点(x0,f(x0)和点(2﹣x0,f(2﹣x0))处的切线总是平行,现过点(﹣2a,a﹣2)作曲线y=f(x)的切线,则可作切线的条数为( )
A..3 | B..2 | C.1 | D..0 |
更新时间:2019-12-26 23:40:36
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