名校
1 . 设二次函数
,若
,
.
(1)若
,求
的值;
(2)求证:方程
必有两个不等实数根
,且
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/331d5e308cd5469e0f28a8d75f79903f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ee761a6feb47d20768453deea2e62b7f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7c30919cbd015f55cefdd9bbe2a33687.png)
(1)若
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0b550ee821ee1838384835e81fc34b67.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e5d55ef0d1b7ea88d92fd6e1ecebb5f5.png)
(2)求证:方程
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/86b92b70365c63607daecdc8deb73ecf.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8ce7ae90d808f05e86ea063238e4b2f9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/fb0a7fde8d96329f882de5040b490d05.png)
您最近一年使用:0次
2 . 已知函数f(x)=x2+ax+b,实数x1,x2满足x1∈(a-1,a),x2∈(a+1,a+2).
(Ⅰ)若a<-
,求证:f(x1)>f(x2);
(Ⅱ)若f(x1)=f(x2)=0,求b-2a的取值范围.
(Ⅰ)若a<-
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3d0e7bfbd56fe73dfe04c04da749d942.png)
(Ⅱ)若f(x1)=f(x2)=0,求b-2a的取值范围.
您最近一年使用:0次
解题方法
3 . 已知函数
,
.
(Ⅰ)当
,
时,求
的最小值(用
表示);
(Ⅱ)记集合
,集合
,若
,
(i)求证:
;
(ii)求实数
的取值范围.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f999f08ecb8d23752dc451cec73219c7.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9dd42f780c2a802ec023ca445d193a5e.png)
(Ⅰ)当
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/88c2c4b82d87e769807270fc5361fde3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/292d4d1675298d11d1cba3b2867c7572.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d479a86a1711709b2d100fe4daf3e7cf.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0a6936d370d6a238a608ca56f87198de.png)
(Ⅱ)记集合
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/01b325d394a4dff23dfb9888325171cb.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e3255a5457f2e4eec0f6fe1bf2f8099e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b5fb5ae3d077beeae781da19e0b21c7a.png)
(i)求证:
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/47aed4c293bb0f322b2e24085ae3d426.png)
(ii)求实数
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0a6936d370d6a238a608ca56f87198de.png)
您最近一年使用:0次
解题方法
4 . 已知a>0,b∈R,函数f(x)=4ax2﹣2bx﹣a+b,x∈[0,1].
(Ⅰ)当a=b=2时,求函数f(x)的最大值;
(Ⅱ)证明:函数f(x)的最大值|2a﹣b|+a;
(Ⅲ)证明:f(x)+|2a﹣b|+a≥0.
(Ⅰ)当a=b=2时,求函数f(x)的最大值;
(Ⅱ)证明:函数f(x)的最大值|2a﹣b|+a;
(Ⅲ)证明:f(x)+|2a﹣b|+a≥0.
您最近一年使用:0次
2016-12-04更新
|
384次组卷
|
2卷引用:2015-2016学年浙江省台州市高一上期末数学试卷