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解题方法
1 . 我国魏晋时期的数学家刘徽创造了一个称为“牟合方盖”的立体图形,如图1,在一个棱长为2r的立方体内作两个互相垂直的内切圆柱,其相交的部分就是牟合方盖(如图2),我国南北朝时期数学家祖暅基于“势幂既同则积不容异”这一观点和对牟合方盖性质的研究,推导出了球体体积公式.设平行于水平面且与水平面距离为
的平面为
,则平面
截牟合方盖所得截面的形状为______ (填“正方形”或“圆形”),设半径为r的球体体积为
,图2所示牟合方盖体积为
,则![](https://staticzujuan.xkw.com/quesimg/Upload/formula/625dbbd5d5f2617b7c53acdb936b1d07.png)
______ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/82d38e62ba27b42d838c51a6e0a88e40.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e170f206fdbbd834aad7580c727e2cc6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e170f206fdbbd834aad7580c727e2cc6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c4764374bd2fb78e59cd0b283637baeb.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c63055a5d6916f99d07fede49120753f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/625dbbd5d5f2617b7c53acdb936b1d07.png)
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2 . 直线
与圆
:
交于
,
两点,若
,则![](https://staticzujuan.xkw.com/quesimg/Upload/formula/88bee8e70f1fab639be1636c7bce0477.png)
________ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0f85fca60a11e1af2bf50138d0e3fe62.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1dde8112e8eb968fd042418dd632759e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a5f5d967ad135991b6075ee45df55643.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5963abe8f421bd99a2aaa94831a951e9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7f9e8449aad35c5d840a3395ea86df6d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15aab800f41f7a47bde139498e19d294.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/88bee8e70f1fab639be1636c7bce0477.png)
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3 . 已知两点
,
所在直线的斜率为
,则![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a6c57bbef89a37f1a3808c0ceeac0c22.png)
________ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/18e23b74ed51912d236727c0ee5e3e64.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/68ad0f94243a1600321c4b2b27c307de.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/bdaa19de263700a15fcf213d64a8cd57.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a6c57bbef89a37f1a3808c0ceeac0c22.png)
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7日内更新
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186次组卷
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3卷引用:贵州省都匀市民族中学2023-2024学年高二上学期期中考试数学试题
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4 . 已知直线
经过两点
,
,则它的斜率为________ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0f85fca60a11e1af2bf50138d0e3fe62.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5800c6d0b70eb19a205fc83a070ccd1e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a80a5bed5c0f5514bffd7ea196c5ce39.png)
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5 . 已知三棱锥
的四个顶点在球O的球面上,
,
是边长为6的正三角形,E为SA的中点,直线CE,SB所成角为90°,则球O的表面积为______ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/41e5db1d2fd912f77923e4c120a7dc19.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/700f2f0f1cf306f7fc18d18fe91d0acb.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15c0dbe3c080c4c4636c64803e5c1f76.png)
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解题方法
6 . 已知
是球
表面上的点,
平面
若球
的体积为
,则![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1c3e0e93b586844f67ca7a3b157dd310.png)
__________ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/523bdb05d8e5de2a84ccedb6db738037.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1dde8112e8eb968fd042418dd632759e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/10c83f8945042b9c8fb2fbdac9308d62.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2c880085b1eb986f6ce3653337433789.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1dde8112e8eb968fd042418dd632759e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/67fb457e8ac0d3ac35e1c668ea138f91.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1c3e0e93b586844f67ca7a3b157dd310.png)
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7 . 直线
的倾斜角为______ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/76d4bf927dc9908d573434578a25d5a4.png)
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解题方法
8 . 在《九章算术》中,将四个面都是直角三角形的四面体称为鳖臑,在鳖臑
中
,
,
,
,
,已知动点E从C点出发,沿外表面经过棱AD上一点到点B的最短距离为
,则该棱锥的外接球的体积为________ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/891579e7c231584a8e16b8eeff79888e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/080db3af81b29ed10144a1c2e2a4fb8a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8915e8e775538d41debf1933102c6b86.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6c90da0cd2708481057fe19acebf2ec7.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ce4ab7e657f01bdfa235f8c4d6681d13.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1ed18447a59016c8c89d1561f7dd5172.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d4056761b8f826eeb6ad8c9a151d3c9c.png)
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解题方法
9 . 如图,在直三棱柱
中,
,
,
,
,点
在棱
上,点
在棱
上,给出下列三个结论:
的体积为定值;
②三棱锥
的体积的最大值为
;
③
的最小值为
.
请写出所有正确结论的序号______
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/42d3a82b8e587ee890467835bc4e854c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/615fc8790237a1b09af51d6bcad6b595.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7bb5b12692517a39c320f99a479eb055.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/aa7aeb2a8d1437eeb4482c3b6ad9f315.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/92535536bd3c2761724fd058427f95a8.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8455657dde27aabe6adb7b188e031c11.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/60ef95894ceebaf236170e8832dcf7e3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2a30f3a8b673cc28bd90c50cf1a35281.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e0a851907ada2ac2c3c4880a6736d28a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3f44b0a6c08b088d7be63aef9761d473.png)
②三棱锥
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/52753d89bf58589e2e83b19bd3d140b8.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/bf31876698721a199c7c53c6b320aa86.png)
③
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/17499bf1e5114115fa29ba7f7f045795.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ed728f911042364c77b78b597aafd344.png)
请写出所有正确结论的序号
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解题方法
10 . 如图,已知正三棱柱
的底面边长为1,侧棱
的长为2,E、F分别为
和AC中点,则直线EF与平面
所成角的余弦值为______ ,异面直线
与
所成角的余弦值为______ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/42d3a82b8e587ee890467835bc4e854c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2777840758e70e7dbbc18cef8f3d6d2b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/11ddc92d84d188c66b435664a7e7b5a4.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7bef5239ddbb0972700ce01daf9ee7cf.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e26d9636ad77369535852c6e4493446a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/24bb49fdc6b6bbb2449fdf8a0de769d3.png)
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