23-24高二上·上海·课后作业
1 . 根据下列方程,判定直线
与
的位置关系,若相交,求出夹角.
(1)
,
;
(2)
,
;
(3)
,
.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2e9b0f5f44abbc6544a2f672b025b013.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3f6f17bc385bafb37e8f964e5eb99cd0.png)
(1)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c15d419ac2b9832ef6fb704d98790487.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2db191a381bcc131aad1216844cfe0fc.png)
(2)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b00b8eb5fee88a104b321d1c2d5c5b59.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0031a6f0727e81ec9966c95fb2a5eb12.png)
(3)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/83342b9d257e062198077c2897e77dc9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5810390abd0a156828293ad5885442d8.png)
您最近一年使用:0次
2 . 求直线
的倾斜角.(用反三角正切值表示)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/047af94fe520e6ec4f554eaa6b1df83e.png)
您最近一年使用:0次
23-24高二上·上海·课后作业
3 . 求经过下列两点的直线的斜率与倾斜角:
(1)
、
;
(2)
、
,其中
是常数.
(1)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/530e5817131adf2c05b99ff18eb9060f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/63297c48d9a2dfecb249f101b571e0a4.png)
(2)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/85d23fc512ad69a2d5919ce690407704.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ac3cf8a80a8c008e42d6a75ed61ebdc3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/10bbdef421c976962a270a2beabbad91.png)
您最近一年使用:0次
23-24高三上·上海浦东新·开学考试
名校
解题方法
4 . 活动场地的“得地率”是指可供人活动的区域的占地面积与总占地面积之比.某大型商场欲将地下一层的一块半圆形空地改建为亲子乐园,建造一个供亲子游玩的海洋球池和两个大小完全相同的休息区,供人们休息和娱乐.除海洋球池和休息区外的剩余空地全部用气垫筑起高墙作为防护.如图,设半圆形空地的圆心为
,半径为
为直径,矩形海洋球池
的顶点
在
上,顶点
在半圆的圆周上,矩形休息区
和
的顶点
在
上,顶点
在半圆的圆周上,顶点
分别在线段
上.已知
,设
.
(1)当
时,求亲子乐园可供人活动区域的面积
;
(2)为使亲子乐园的“得地率”最大,求
的取值.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1dde8112e8eb968fd042418dd632759e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5422148ab07e809f7df74d0c322b27ec.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411b38a18046fea8e9fab1f9f9b80a5f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e52586ca2a3b783bc8092415e2d4bf6d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411461db15ee8086332c531e086c40c7.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8c29a7e8eea08197bf53164a560bee58.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/fbc7ee0ef8945ba1b90e59aed7cab889.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/cc8cedba8cf78fb20381c72e9b5f6b06.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7aaca640804990a67999d69918cfc0a4.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411461db15ee8086332c531e086c40c7.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dc9d014faa51e470534e519617672847.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7f9fd4f55e38217c37fd835bb3916f46.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f6c8b21a087818284c9cd909cc56c814.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0d777a41834c51955d719bd68e7bd45d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/216f9d2e571371442770ce5e3e4d6e4a.png)
![](https://img.xkw.com/dksih/QBM/editorImg/2023/9/7/eb16b2c1-b39b-498d-91ce-0dcd84e7eb1d.png?resizew=214)
(1)当
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/905dd10639c9fef5ef8d66a124756140.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/cf231f8f86fb922df4ca0c87f044cec3.png)
(2)为使亲子乐园的“得地率”最大,求
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c24095e409b025db711f14be783a406c.png)
您最近一年使用:0次
14-15高二上·上海徐汇·期中
名校
解题方法
5 . 直角坐标系xOy中,点A坐标为(2,0),点B坐标为(4,3),点C坐标为(1,3),且
(t∈R).
![](https://img.xkw.com/dksih/QBM/editorImg/2022/11/1/7c0c1482-5cb1-4cda-9f4b-c6ceb4ddb4c6.png?resizew=250)
(1) 若CM⊥AB,求t的值;
(2) 当0≤ t ≤1时,求直线CM的斜率k和倾斜角θ的取值范围.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6111d3ee495ede3eada105f02038714f.png)
![](https://img.xkw.com/dksih/QBM/editorImg/2022/11/1/7c0c1482-5cb1-4cda-9f4b-c6ceb4ddb4c6.png?resizew=250)
(1) 若CM⊥AB,求t的值;
(2) 当0≤ t ≤1时,求直线CM的斜率k和倾斜角θ的取值范围.
您最近一年使用:0次