名校
1 . 数列
的前
项和为
,若
,
,则下列结论正确的是( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c19bf566cd9dd81916f53ed33248197c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b6a24198bd04c29321ae5dc5a28fe421.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/08eb71ecf8d733b6932f4680874dbbf3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b065334d8f60c49f4bd3d9f1373fe4cd.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c9faad57128c31c9d3bb45e02e04e7f2.png)
A.![]() | B.![]() |
C.![]() | D.![]() |
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3卷引用:江西省萍乡市2024届高三二模考试数学试卷
2 . 唐代大诗人李白喜好饮酒作诗,民间有“李白斗酒诗百篇”之说.《算法统宗》中记载了一个“李白沽酒”的故事.诗云:今携一壶酒,游春郊外走.逢朋加一倍,入店饮半斗.注:古代一斗是10升.大意是:李白在郊外春游时,做出这样一条约定:遇见朋友,先到酒店里将壶里的酒增加一倍(假定每次加酒不会溢出),再喝掉其中的5升酒.那么根据这个规则,若李白酒壶中原来有酒6升,将李白在第5家店饮酒后所剩酒量是( )
A.37升 | B.21升 | C.26升 | D.32升 |
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3 . 已知数列
满足
,且
,则![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0acca5aa6b2285d897a65c289c1b54ba.png)
__________ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/83cf38189d5cbf627d2b82ac0eb76006.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0ea8d0e50065114b05ef2dc1ea1129cf.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a2ef0ebc1f6c549657060811dfb4f29e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0acca5aa6b2285d897a65c289c1b54ba.png)
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4 . 已知数列{}满足
,
,
,且其前n项和为
,则( )
A.存在![]() ![]() |
B.存在![]() ![]() |
C.存在![]() ![]() ![]() |
D.![]() |
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名校
解题方法
5 . 牛顿迭代法(Newton's method)又称牛顿–拉夫逊方法(Newton–Raphsonmethod),是牛顿在17世纪提出的一种近似求方程根的方法.如图,设
是
的根,选取
作为
初始近似值,过点
作曲线
的切线
,
与
轴的交点的横坐标
(
),称
是
的一次近似值,过点
作曲线
的切线,则该切线与
轴的交点的横坐标为
,称
是
的二次近似值.重复以上过程,直到
的近似值足够小,即把
作为
的近似解.设
,
,
,
,
构成数列
.对于下列结论:
(
);
②
(
);
③
;
④
(
).
其中正确结论的序号为__________ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/11bc05f41215f9894e11d1df0465751a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f8ec28f6f007c118c4fb3dc2e0531ca1.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/015740ce0b7022cf0a5503747c020999.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/11bc05f41215f9894e11d1df0465751a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/43db00e106c7d08a76a7ba71ca5e63d1.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/89f4eff3125c5e63a994ba1ad5be58e5.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0f85fca60a11e1af2bf50138d0e3fe62.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0f85fca60a11e1af2bf50138d0e3fe62.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/81dea63b8ce3e51adf66cf7b9982a248.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/453cee2ac9dfd92e2edfa0b4c4004ba2.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b41800503c5e7a04a54819c596aa8fd1.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b12a4eecd249473a831d0ee472470240.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/11bc05f41215f9894e11d1df0465751a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d27c0ab3e2d7698f082854bafe4174dc.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/89f4eff3125c5e63a994ba1ad5be58e5.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/81dea63b8ce3e51adf66cf7b9982a248.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9565876bc50bceb63e5793c8c67a9032.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9565876bc50bceb63e5793c8c67a9032.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/11bc05f41215f9894e11d1df0465751a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/11bc05f41215f9894e11d1df0465751a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3282e5fde4ae53fcb1bb072a685304c9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f8ec28f6f007c118c4fb3dc2e0531ca1.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c814128ea2139e33db94ea590e7c2223.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/aec19b68e3add9d5bfcc6269a1855b87.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/291c25fc6a69d6d0ccfb8d839b9b4462.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/daa5e9bd516f6282483b92cfe6074623.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3282e5fde4ae53fcb1bb072a685304c9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e976c0663fa749ca749f99842d21ca03.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/69004a81950ee4b3a23dd3c0748be821.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0704f453b2de48d36911f7db496bbf82.png)
②
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/38e2dc498840932eb1f8e359e4e3b931.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0704f453b2de48d36911f7db496bbf82.png)
③
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ac12f7f9467c2d446c2d83df051d6f85.png)
④
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6fa385ab812298518070dff2a4b8057d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0704f453b2de48d36911f7db496bbf82.png)
其中正确结论的序号为
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|
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10卷引用:江西省萍乡市芦溪中学2022届高三上学期开学考试数学(理)试题
江西省萍乡市芦溪中学2022届高三上学期开学考试数学(理)试题2020届宁夏银川景博中学高三下学期第一次模拟数学(文)试题(已下线)学科网3月第一次在线大联考(新课标Ⅰ)数学(文科)试题河南省郑州市2019-2020学年高二下学期阶段性学业检测题(5月) 数学(文)试题河南省郑州市2019-2020学年高二(下)期中数学(文科)试题(已下线)文科数学-学科网3月第一次在线大联考(新课标Ⅰ卷)(已下线)专题01 利用构造或猜想,解决数列递推问题 (第三篇)-2020高考数学压轴题命题区间探究与突破(已下线)第三篇 数列、排列与组合 专题1 建立递推关系求通项公式 微点2 建立递推关系求通项公式综合训练(已下线)第01讲 导数的概念与运算(三大题型)(讲义)(已下线)【一题多变】零点估计 牛顿切线
6 . 在数列
中,
,
,则
( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/83cf38189d5cbf627d2b82ac0eb76006.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b065334d8f60c49f4bd3d9f1373fe4cd.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/89f1f2cd9423d67152a6324bec2c5a3c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/42e4487468ab2823d6dbf7f0ebd2eb38.png)
A.5 | B.6 | C.14 | D.15 |
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|
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名校
解题方法
7 . 已知数列
的前
项和为
,其中
且
.
(1)试求:
,
的值;
(2)由此猜想数列
的通项公式
;
(3)用数学归纳法加以证明.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/83cf38189d5cbf627d2b82ac0eb76006.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b6a24198bd04c29321ae5dc5a28fe421.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/08eb71ecf8d733b6932f4680874dbbf3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a95f4df39a90946616bc7216acd48154.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/abf2672a8b9e3502e228db21456d76c6.png)
(1)试求:
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3e88093a749c0d46e0ee931ecfaff925.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6c1ccc6c74b8754e9bcbb3f39a11b6f1.png)
(2)由此猜想数列
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/83cf38189d5cbf627d2b82ac0eb76006.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/96abfe2da27a63e6affb19a0c80236d9.png)
(3)用数学归纳法加以证明.
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8 . 已知数列
满足
,
,则![](https://staticzujuan.xkw.com/quesimg/Upload/formula/42e4487468ab2823d6dbf7f0ebd2eb38.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/63d471926f7b27322d90c82b9ce21d3d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b065334d8f60c49f4bd3d9f1373fe4cd.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4ed102f3ac0fe5f99f4d8c4a552cd85b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/42e4487468ab2823d6dbf7f0ebd2eb38.png)
A.4 | B.-4 | C.8 | D.-8 |
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