名校
解题方法
1 . 已知点
为焦点在
轴上的等轴双曲线上的一点.
(1)求双曲线的方程;
(2)已知直线
且
交双曲线右支于
两点,直线
分别交该双曲线斜率为正的渐近线于
两点,设四边形
和三角形
的面积分别为
和
,求
的取值范围.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6f40d5459e1385ab7d829ea96ca0b946.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/81dea63b8ce3e51adf66cf7b9982a248.png)
(1)求双曲线的方程;
(2)已知直线
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/108cab3ffbf5705366ad2f3af6bb9e09.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0f85fca60a11e1af2bf50138d0e3fe62.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7789a500686c7a73770404ead6af0590.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2ec8858389f4c3156a946ba8bf0d8a7b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ad056c25c0fdcbcc765eb5cbc6093f2b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/12f4248e8021130ab60365e3d2e9a694.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9d246f9eceab371ebf47a47c2f11a4ad.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e097c8d4c948de063796bd19f85b3a9a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1e0bd63f55069a3bc870915010b39225.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/235f0a6fb218d28383e6f27f2df1f50f.png)
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2 . 已知正方体
是边长为1的正方体,点
为正方体棱上的一动点,则使得
的点
有__________ 个.(用数字作答)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6e09725691ee7851f54c0dee86b2bf55.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ac047e91852b91af639feec23a9598b2.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3fa501be0fafcaaa3fa31731e929e301.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ac047e91852b91af639feec23a9598b2.png)
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名校
解题方法
3 . 在高等数学中对于二阶线性递推式
求数列通项,有一个特殊的方法特征根法:我们把递推数列
的特征方程写为
①,若①有两个不同实数根
,则可令
;若①有两个相同的实根
,则可令
,再根据
求出
,代入即可求出数列
的通项.
(1)斐波那契数列(Fibonacci sequence),又称黄金分割数列,因出自于意大利数学家斐波那契的一道兔子繁殖问题而得名.斐波那契数列指的是形如
的数列,这个数列的前两项为1,从第三项开始,每一项都等于前两项之和,请求出斐波那契数列的通项公式;
(2)已知数列
中
,数列
满足
,数列
满足
,求数列
的前
项和
.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c48a2440b4b2c3723ad87edfc8193c68.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c48a2440b4b2c3723ad87edfc8193c68.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/594d0e29aa2515d2eba9a5ddafd144f7.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c4e288596fa3811dd2c17bded60e82e7.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3490528838590538ce9b50f4ae6885e8.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e170f206fdbbd834aad7580c727e2cc6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/91bd27ae250b40955a3c30e60095b6ef.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c0158862238e250d2a2598b7d4ecd148.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/595978a4c58acd102b120735f963a631.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/83cf38189d5cbf627d2b82ac0eb76006.png)
(1)斐波那契数列(Fibonacci sequence),又称黄金分割数列,因出自于意大利数学家斐波那契的一道兔子繁殖问题而得名.斐波那契数列指的是形如
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/72a59cc32eebe1accdf2fa8ba0aa916d.png)
(2)已知数列
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/83cf38189d5cbf627d2b82ac0eb76006.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/db1be42847d98a18aeffba68d2dbd8de.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/034ba25825c13725931c483aa47c9363.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/97a8e8e16b1adc46119e77d74b7ed519.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/57ef6d44448092ebdb9e4a49d866a749.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/65146e1a9e8192e773871cad3cc48d89.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/57ef6d44448092ebdb9e4a49d866a749.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b6a24198bd04c29321ae5dc5a28fe421.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f1ae9a3b0b7aeb1545b65d91aa371b3c.png)
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名校
解题方法
4 . 已知函数的定义域为
,
,且当
时,
,则下列说法正确的是( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/24a57996290794e082b21d8f1dfc322a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/322eb46d949b9580bcc057d146b7fc58.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/71bb7883ea87e6275472dbe14ee62357.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/93bec8b1d8c2a5bd5095cb5a42719175.png)
A.当![]() ![]() |
B.当![]() ![]() |
C.若对任意的![]() ![]() ![]() ![]() |
D.若![]() ![]() |
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5 . 已知函数
(
是自然对数的底数),则下列说法正确的是( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7c715d433b58fea1e74049279cbbd17f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a82d68ed3c2ae422e6b0a312f0bf5523.png)
A.若![]() ![]() ![]() |
B.若![]() ![]() ![]() |
C.若![]() ![]() ![]() |
D.当![]() ![]() ![]() ![]() |
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6 . 已知
,对任意
都有
,则实数
的取值范围是__________ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1d33da711e50e96568facb18cef27165.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4921923069c4f38a0af1ff8637e35b3c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9fdce16cdc4ea681fd41ef0cf7b08fb7.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0a6936d370d6a238a608ca56f87198de.png)
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名校
解题方法
7 . 已知椭圆
的右焦点为
,过点
作圆
的切线与椭圆
相交于
两点,且
,则椭圆
的离心率是( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e512e98081d08ea4c557fe2d16141b35.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a0ed1ec316bc54c37c4286c208f55667.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a0ed1ec316bc54c37c4286c208f55667.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6410a2febd562ed24199b410b3fd7640.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b1241216f3c1cb5e73043dd1037f556d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/01c74a907dda6bb7d9d56d009d9df253.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d780f0607ef7e19996aa5274409cd103.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b1241216f3c1cb5e73043dd1037f556d.png)
A.![]() | B.![]() | C.![]() | D.![]() |
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8 . 早在公元5世纪,我国数学家祖暅在求球体积时,就创造性地提出了一个原理“幂势既同,则积不容异”,意思是夹在两个平行平面之间的两个几何体,被平行于这两个平面的任意平面所截,如果截得的两个截面的面积总相等,那么这两个几何体的体积相等.
的半球体中,挖去一个半径为
的球体,求剩余部分的体积.
(2)如图二,由抛物线![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8ef476b5e912aca6ae9494fcba5a2b2b.png)
跟线段![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c9355031ea0b2dc9cef3777621bc6d38.png)
围成一个几何形,将该几何形绕
轴旋转得到一个抛物线旋转体,请运用祖暅原理求该旋转体的体积.
(3)将两个底面半径为1,高为3圆柱体按如图三所示正交拼接在一起,构成一个十字型几何体.求这个十字型的体积,等价于求两个圆柱公共部分几何体的体积,请运用祖暅原理求出该公共部分几何体的体积.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5ca7d1107389675d32b56ec097464c14.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a4b8503f4706b8321e4e79a87eadea84.png)
(2)如图二,由抛物线
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8ef476b5e912aca6ae9494fcba5a2b2b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0b52c00fb7f2a3d8e6bd232b1b70ad46.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c9355031ea0b2dc9cef3777621bc6d38.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0b52c00fb7f2a3d8e6bd232b1b70ad46.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d053b14c8588eee2acbbe44fc37a6886.png)
(3)将两个底面半径为1,高为3圆柱体按如图三所示正交拼接在一起,构成一个十字型几何体.求这个十字型的体积,等价于求两个圆柱公共部分几何体的体积,请运用祖暅原理求出该公共部分几何体的体积.
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2024-05-07更新
|
536次组卷
|
2卷引用:浙江省温州中学2023-2024学年高一下学期期中考试数学试题
名校
9 . 如图,在四边形
中,![](https://staticzujuan.xkw.com/quesimg/Upload/formula/03902478df1a55bc99703210bccab910.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d67be899bc131ec1b9921ae9787c40d5.png)
,将
沿
进行翻折,在这一翻折过程中,下列说法正确的是( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411b38a18046fea8e9fab1f9f9b80a5f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/03902478df1a55bc99703210bccab910.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d67be899bc131ec1b9921ae9787c40d5.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d5a260249fa9917c7f52e90a2daea30e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ab2a2834d80ff574e79eae8ca8d4e94f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d40b319212a7e7528b053e1c7097e966.png)
A.始终有![]() |
B.当平面![]() ![]() ![]() ![]() |
C.当平面![]() ![]() ![]() ![]() ![]() |
D.当平面![]() ![]() ![]() ![]() |
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2024-05-06更新
|
554次组卷
|
2卷引用:浙江省嘉兴市平湖市当湖高级中学2023-2024学年高一下学期5月月考数学试题
名校
10 . 斐波那契数列(Fibonacci sequence),又称黄金分割数列,因数学家莱昂纳多·斐波那契(Leonardo Fibonacci)以兔子繁殖为例子而引入,故又称为“兔子数列”,指的是这样一个数列:1、1、2、3、5、8、13、21、34、…,在数学上,斐波那契数列以如下递推的方式定义:
,
,
(
,
),已知
,则集合A中的元素个数可表示为
,又有
且
.
(1)求集合A中奇数元素的个数,不需说明理由;并求出集合B中所有元素之积为奇数的概率;
(2)求集合B中所有元素之和为奇数的概率.
(3)取其中的6个数1,2,3,5,13,21,任意排列,若任意相邻三数之和都不能被3整除,求这样的排列的个数.(如排列1,2,3,5,13,21中,相邻三数如“1,2,3”(“3,5,13”、“5,13,21”),和能被3整除,则此排列不合题意)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b065334d8f60c49f4bd3d9f1373fe4cd.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f966272f7781790ff27e40db6b525253.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d6a404164c8d199f60d183a59b3647cc.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3bcfc48f9bc23cc43085bdb910e7a136.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/48f093c61867ee4ce75f951d46b9b123.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/eb976cc41026ce1540505e9c5f9e81a5.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/82e5ee1d004ae893eb0190b6e9a4c6c8.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/caf22d7d1a965bda25168a233fb6290c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3331942d1f39489803a81d76844cc442.png)
(1)求集合A中奇数元素的个数,不需说明理由;并求出集合B中所有元素之积为奇数的概率;
(2)求集合B中所有元素之和为奇数的概率.
(3)取其中的6个数1,2,3,5,13,21,任意排列,若任意相邻三数之和都不能被3整除,求这样的排列的个数.(如排列1,2,3,5,13,21中,相邻三数如“1,2,3”(“3,5,13”、“5,13,21”),和能被3整除,则此排列不合题意)
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