已知直线l:
与椭圆
:
(
)交于A、B两点,与圆
:
交于C、D两点.若存在
,使得
,则椭圆
的离心率的取值范围是______ .
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19-20高三上·湖南郴州·阶段练习 查看更多[3]
湖南省郴州市2019-2020学年高三第一次教学质量监测(12月) 数学(理)试题河南省濮阳市2019-2020学年高二下学期升级考试(期末)数学(理)试题(已下线)第3章 圆锥曲线与方程 单元综合检测(基础过关)(单元培优)-2021-2022学年高二数学课后培优练(苏教版2019选择性必修第一册)
更新时间:2020-01-17 20:19:05
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【推荐1】平面内与两定点
,
连线的斜率之积等于非零常数
的点的轨迹,加上
、
两点所成的曲线
可以是圆、椭圆或双曲线,给出以下四个结论:①当
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是一个圆;②当
时,曲线
的离心率为
;③当
时,曲线
的渐近线方程为
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的焦点坐标分别为
和
时,
的范围是
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【推荐2】已知
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【推荐3】如图①,用一个平面去截圆锥,得到的截口曲线是椭圆.许多人从纯几何的角度出发对这个问题进行过研究,其中比利时数学家Germinal dandelin(1794-1847)的方法非常巧妙,极具创造性.在圆锥内放两个大小不同的球,使得它们分别与圆锥的侧面,截面相切,两个球分别与截面相切于E,F,在截口曲线上任取一点A,过A作圆锥的母线,分别与两个球相切于C,B,由球和圆的几何性质,可以知道,
,于是
.由B,C的产生方法可知,它们之间的距离
是定值,由椭圆定义可知,截口曲线是以E,F为焦点的椭圆.如图②,一个半径为3的球放在桌面上,桌面上方有一个点光源P,则球在桌面上的投影是椭圆.已知
是椭圆的长轴,
垂直于桌面且与球相切,
,则椭圆的离心率为_______________ .
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______ ;过点
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