解题方法
1 . 已知抛物线C:
,过点A(12,0)作直线
垂直
轴交抛物线于
两点,
于E,AE//OM,O为坐标原点.
(Ⅰ)求
的值;
(Ⅱ)若抛物线
上存在不同的两点G、H关于直线
对称,求
取值的范围.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3764ba3aa0a241787f4661026bb14053.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411461db15ee8086332c531e086c40c7.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/81dea63b8ce3e51adf66cf7b9982a248.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e6670479a0083dd2dfd5ad55b47b1ab6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ef7f1b8df54cd7b0837ce89de920a474.png)
(Ⅰ)求
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b1010846eeec6c9da29640f5aa3f8738.png)
(Ⅱ)若抛物线
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c5db41a1f31d6baee7c69990811edb9f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/54479885d4ab2f717d2e97718da04b43.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/294f5ba74cdf695fc9a8a8e52f421328.png)
您最近一年使用:0次
2 . 如图,小明同学先把一根直尺固定在画板上面,把一块三角板的一条直角边紧靠在直尺边沿,再取一根细绳,它的长度与另一直角边相等,让细绳的一端固定在三角板的顶点A处,另一端固定在画板上点F处,用铅笔尖扣紧绳子(使两段细绳绷直),靠住三角板,然后将三角板沿着直尺上下滑动,这时笔尖在平面上画出了圆锥曲线C的一部分图象.已知细绳长度为3,经测量,当笔尖运动到点P处,此时,
,
.设直尺边沿所在直线为a,以过F垂直于直尺的直线为x轴,以过F垂直于a的垂线段的中垂线为y轴,建立平面直角坐标系.
![](https://img.xkw.com/dksih/QBM/editorImg/2024/1/20/3280b562-4d23-4d61-98de-88a447bfabe8.jpg?resizew=138)
(1)求曲线C的方程;
(2)斜率为k的直线
过点
,且与曲线C交于不同的两点M,N,已知k的取值范围为
,若
,求
的范围.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2b885ab7c607be0dbd27c1e57941e81f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dc603cd2426c2eb1a7f330d768e5d2cb.png)
![](https://img.xkw.com/dksih/QBM/editorImg/2024/1/20/3280b562-4d23-4d61-98de-88a447bfabe8.jpg?resizew=138)
(1)求曲线C的方程;
(2)斜率为k的直线
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0f85fca60a11e1af2bf50138d0e3fe62.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9d307720f68b610bf1a7660f0c46424b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4772c835cbe626040ecc4df30e6f0ccc.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c0df31126849d010525cbeee019bae5f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/df64046e91b047037f19e4032e3b6de3.png)
您最近一年使用:0次
2023-12-21更新
|
498次组卷
|
3卷引用:河南省南阳市2023-2024学年高二上学期12月月考数学试题
解题方法
3 . 如图已知抛物线C的方程为
,焦点为F,过抛物线内一点A作抛物线准线的垂线,垂足为
,与抛物线交于点P,已知
,
,
,
![](https://img.xkw.com/dksih/QBM/editorImg/2023/12/27/95123bb1-911d-4d72-8335-f305e8e71eb2.png?resizew=166)
(1)求p的值;
(2)斜率为k的直线过点
,且与曲线C交于不同的两点M,N,已知k的取值范围为
,探究:是否存在
,使得
,若存在,求出
的范围,若不存在,说明理由.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7089148c36cb3c39af71de653756396a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e7c314398e26ffc7164b82946eeb4273.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/fd21a4e45dc1beb069d7e78f84a51544.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b90675b0443eaa6607d217e6a32a690b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2b885ab7c607be0dbd27c1e57941e81f.png)
![](https://img.xkw.com/dksih/QBM/editorImg/2023/12/27/95123bb1-911d-4d72-8335-f305e8e71eb2.png?resizew=166)
(1)求p的值;
(2)斜率为k的直线过点
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/137c4624509cdea01ec665854cfb03d0.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/afa482d7bcaa385bfc3548b42a4bfb60.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/df64046e91b047037f19e4032e3b6de3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c0df31126849d010525cbeee019bae5f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/df64046e91b047037f19e4032e3b6de3.png)
您最近一年使用:0次
2023-11-26更新
|
501次组卷
|
2卷引用:安徽省淮北市树人高级中学2023-2024学年高二上学期期中数学试题
名校
解题方法
4 . 如图:小明同学先把一根直尺固定在画板上面,把一块三角板的一条直角边紧靠在直尺边沿,再取一根细绳,它的长度与另一直角边相等,让细绳的一端固定在三角板的顶点
处,另一端固定在画板上点
处,用铅笔尖扣紧绳子(使两段细绳绷直),靠住三角板,然后将三角板沿着直尺上下滑动,这时笔尖在平面上画出了圆锥曲线
的一部分图象.已知细绳长度为
,经测量,当笔尖运动到点
处,此时,
,
.设直尺边沿所在直线为
,以过
垂直于直尺的直线为
轴,以过
垂直于
的垂线段的中垂线为
轴,建立平面直角坐标系.
(1)求曲线
的方程;
(2)斜率为
的直线过点
,且与曲线
交于不同的两点
,已知
的取值范围为
,探究:是否存在
,使得
,若存在,求出
的范围,若不存在,说明理由.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5963abe8f421bd99a2aaa94831a951e9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a0ed1ec316bc54c37c4286c208f55667.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c5db41a1f31d6baee7c69990811edb9f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5ca7d1107389675d32b56ec097464c14.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dad2a36927223bd70f426ba06aea4b45.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/741b63b4017c322eb60efaeb10efbf3b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/33a891e388fdad657dc83dec208d23dc.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0a6936d370d6a238a608ca56f87198de.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a0ed1ec316bc54c37c4286c208f55667.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/81dea63b8ce3e51adf66cf7b9982a248.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a0ed1ec316bc54c37c4286c208f55667.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0a6936d370d6a238a608ca56f87198de.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d053b14c8588eee2acbbe44fc37a6886.png)
![](https://img.xkw.com/dksih/QBM/editorImg/2023/9/11/8d3cf6df-3b76-45ad-8bd8-2ff0c22fa9e1.png?resizew=140)
(1)求曲线
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c5db41a1f31d6baee7c69990811edb9f.png)
(2)斜率为
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f0a532e15e232cb4b99a8d4d07c89575.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/137c4624509cdea01ec665854cfb03d0.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c5db41a1f31d6baee7c69990811edb9f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7789a500686c7a73770404ead6af0590.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f0a532e15e232cb4b99a8d4d07c89575.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/afa482d7bcaa385bfc3548b42a4bfb60.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/df64046e91b047037f19e4032e3b6de3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c0df31126849d010525cbeee019bae5f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/df64046e91b047037f19e4032e3b6de3.png)
您最近一年使用:0次
2023-09-10更新
|
508次组卷
|
10卷引用:广西桂林市、崇左市2023届高三一模数学(理)试题
广西桂林市、崇左市2023届高三一模数学(理)试题山西省太原市第五中学2023届高三一模数学试题(AB卷)(已下线)专题16解析几何(解答题)广西玉林市博白县中学2023届高三"逐梦高考"数学(理)模拟测试试题(二)辽宁省沈阳市第二中学2023届高三第五次模拟考试数学试题广西壮族自治区防城港市2023届高三下学期4月第三次联合调研考试数学(理)试题(已下线)专题突破卷23 圆锥曲线大题归类(已下线)考点19 解析几何中的探索性问题 2024届高考数学考点总动员【练】黑龙江省大庆铁人中学2023-2024学年高二上学期期中考试数学试题(已下线)专题08 抛物线的压轴题(5类题型+过关检测)-【常考压轴题】2023-2024学年高二数学上学期压轴题攻略(人教A版2019选择性必修第一册)
解题方法
5 . 动圆
与圆
相外切且与
轴相切,则动圆
的圆心的轨迹记
,
(1)求轨迹
的方程;
(2)经过定点
的直线
,试分析直线
与轨迹
的公共点个数,并指明相应的直线
的斜率
是否存在,若存在求
的取值或取值范围情况.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ac047e91852b91af639feec23a9598b2.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e383fcc122f267043fbafe0972bfb900.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d053b14c8588eee2acbbe44fc37a6886.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ac047e91852b91af639feec23a9598b2.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c5db41a1f31d6baee7c69990811edb9f.png)
(1)求轨迹
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c5db41a1f31d6baee7c69990811edb9f.png)
(2)经过定点
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3f89b18f69812fb34fd1290e2f1b36aa.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/294f5ba74cdf695fc9a8a8e52f421328.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/294f5ba74cdf695fc9a8a8e52f421328.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c5db41a1f31d6baee7c69990811edb9f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/294f5ba74cdf695fc9a8a8e52f421328.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f0a532e15e232cb4b99a8d4d07c89575.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f0a532e15e232cb4b99a8d4d07c89575.png)
您最近一年使用:0次
2020-09-01更新
|
224次组卷
|
2卷引用:湖南省邵阳市邵东县第十中学2020届高三下学期模拟考试数学(文)试题