已知四棱锥
,底面
是边长为6的菱形,
,
底面
且
.若此四棱锥的内切球的表面积为
,则该四棱锥的体积为_______ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/faeb97acf19bd3b2c6c77c2814df4d2f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411b38a18046fea8e9fab1f9f9b80a5f.png)
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2020·全国·模拟预测 查看更多[3]
福建省宁德市2020届高三毕业班6月质量检查理科数学试题江苏省南京师范大学附属中学2019-2020学年高一下学期期末模拟数学试题(已下线)第29练 空间几何体的表面积和体积-2021年高考数学(理)一轮复习小题必刷
更新时间:2020-06-25 06:28:17
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解题方法
【推荐1】在
中,
,D是边AC的中点,E是边AB上的动点(不与A,B重合),过点E作AC的平行线交BC于点F,将
沿EF折起,点B折起后的位置记为点P,得到四棱锥
,如图所示,给出下列四个结论,其中所有正确结论的序号是__________ .
不可能为等腰三角形;
②
平面PEF;
③当E为AB中点时,三棱锥
体积的最大值为
;
④存在点E,P,使得
.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15c0dbe3c080c4c4636c64803e5c1f76.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d5701ee5fb156e25cc18db1229590d49.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5f2ea13010e2399194be2a681310543e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/57650963051ccb44a3cfb24f08228405.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1f9596850884048064a3ec8bd48c4762.png)
②
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3f81fa367ec317fe2a30142e1c30cce7.png)
③当E为AB中点时,三棱锥
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5e73fe210736ce7b30b039d34587e3c1.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4dac452fbb5ef6dd653e7fbbef639484.png)
④存在点E,P,使得
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9986e9390b44ddde72b54779f5825bb6.png)
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【推荐2】如图,已知直四棱柱
的所有棱长等于1,
,
和
分别是上下底面对角线的交点,
在线段
上,
,点
在线段
上移动,则三棱锥
的体积最小值为______ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6e09725691ee7851f54c0dee86b2bf55.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/05740f0c6071846227dc0ec177ad15e8.png)
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![](https://img.xkw.com/dksih/QBM/editorImg/2022/12/10/cca4971c-bd98-4e9f-98fe-f0bf6ca0c575.png?resizew=194)
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解题方法
【推荐1】已知四棱锥
平面
,底面
是矩形,
,点
分别在
上,当空间四边形
的周长最小时,则三棱锥
外接球的体积为__________ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e9cd31c659a01b64c1a241c81815c044.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411b38a18046fea8e9fab1f9f9b80a5f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411b38a18046fea8e9fab1f9f9b80a5f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/25de259db34000cbaeda1e018cd09ede.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ad056c25c0fdcbcc765eb5cbc6093f2b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/374fe9986ebbc986fc422e514ab93a51.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ed2455ff2c23cf7b59284eb68a9e5e80.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8504651146697b0ecca4f789790d41ed.png)
![](https://img.xkw.com/dksih/QBM/editorImg/2023/12/21/d242f233-f183-4af1-963c-e57754423440.png?resizew=192)
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【推荐2】根据高中的解析几何知识,我们知道平面与圆锥面相交时,根据相交的角度不同,可以是三角形、圆、椭圆、抛物线、双曲线.如图,AB是圆锥底面圆O的直径,圆锥的母线
,
,E是其母线PB的中点.若平面
过点E,且PB⊥平面
,则平面
与圆锥侧面的交线是以E为顶点的抛物线的一部分,此时抛物线的焦点F到底面圆心O的距离为______ ;截面
把圆锥分割成两部分,在两部分内部,分别在截面
的上方作一个半径最大的球M,在截面
下方作一个半径最大的球N,则球M与球N的半径的比值为______ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0b80ee363635d73f601654339028daec.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/080ca48cd27d4bf9d9ef084b558fc17a.png)
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【推荐1】在三棱锥
中,
,
,
,
,若
与平面
所成角的最大值为
,则
的值为__________ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/41e5db1d2fd912f77923e4c120a7dc19.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/27697383fc4fff764df9e066650d8b2b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/fcd0ced286a0fbc7e4862f8147264277.png)
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![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2c2bc5e50b8dfa02601c70822252854a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/bc9c9cfa597b444b5c9dbae7a825a695.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c24095e409b025db711f14be783a406c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ad8fcf5e8037a9087ac78d59d6a3f942.png)
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【推荐2】已知直四棱柱
的棱长均4,且
,则以
为球心,
为半径的球面与侧面
的交线长为______ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6e09725691ee7851f54c0dee86b2bf55.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/72f427d187aad86252e188bd0649bfd7.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8455657dde27aabe6adb7b188e031c11.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dbff61fe9d4e93d7cc338489d1c99c40.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e168672b47d7e64dc1b404f8882c7dcf.png)
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