1 . 解不等式组及计算:
(1)解不等式组![](https://staticzujuan.xkw.com/quesimg/Upload/formula/09b2fdadaaec3762b29658146dd94010.png)
(2)因式分解:![](https://staticzujuan.xkw.com/quesimg/Upload/formula/93aeb4732bc25e7793e70e618e2a60b5.png)
(3)解方程:
;
(4)先化简,再求值:
,从
,0,2中取一个合适的数作为x的值代入求值.
(1)解不等式组
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/09b2fdadaaec3762b29658146dd94010.png)
(2)因式分解:
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/93aeb4732bc25e7793e70e618e2a60b5.png)
(3)解方程:
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6f4a16ba60d105e018f5bad9ed3e3ad0.png)
(4)先化简,再求值:
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0053981d6fa80df1c15ec84fccd700a4.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/274a9dc37509f01c2606fb3086a46f4f.png)
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2022高一·全国·专题练习
2 . 已知
,
满足方程组
,且
.
(1)试用含
的式子表示方程组的解;
(2)求实数
的取值范围;
(3)化简
.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/81dea63b8ce3e51adf66cf7b9982a248.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d053b14c8588eee2acbbe44fc37a6886.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/74505a91ab0c9038b2e5481131bb1342.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/fc8d93ef14e700c6bed4e4d31625925a.png)
(1)试用含
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/294f5ba74cdf695fc9a8a8e52f421328.png)
(2)求实数
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/294f5ba74cdf695fc9a8a8e52f421328.png)
(3)化简
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ea3d52af08461102a97ea9cc12ea168a.png)
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2022高一·全国·专题练习
3 . (1)解不等式
,并将其解集在数轴上表示出来;
(2)解不等式组并把解集在数轴上表示出来:
.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a64628175df0e4fd35d2d618e615f4bc.png)
(2)解不等式组并把解集在数轴上表示出来:
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5683b7974117fff8aa416c389b985ff3.png)
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2024·全国·模拟预测
解题方法
4 . 在解决问题“已知正实数
满足
,求
的取值范围”时,可通过重新组合,利用基本不等式构造关于
的不等式,通过解不等式求范围.具体解答如下:
由
,得
,即
,解得
的取值范围是
.
请参考上述方法,求解以下问题:
已知正实数
满足
,则
的取值范围是______ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9b0fffbec1fe851795dfdd448bf0d165.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/fb975603433961a27ff01c734d39575f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6f29d5f376c75c41ae6af0c8a8565449.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6f29d5f376c75c41ae6af0c8a8565449.png)
由
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d14a76fbd7733394b3a7a8c7508ae8f7.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/09a2ebb75f6dc5ba596a98ccbc2bb9be.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/60ef066cf9a851361e923ed40c97b842.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6f29d5f376c75c41ae6af0c8a8565449.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/eed05aa46ec16ee8f98272565d2a2ed9.png)
请参考上述方法,求解以下问题:
已知正实数
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9b0fffbec1fe851795dfdd448bf0d165.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/fb975603433961a27ff01c734d39575f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d4e7bf9200b351a259ddfc6c0266129d.png)
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20-21高一上·全国·课前预习
5 . 不等式的解:_______ ,解不等式的过程中要不断地使用______ .
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6 . 牛顿迭代法是我们求方程近似解的重要方法.对于非线性可导函数
在
附近一点的函数值可用
代替,该函数零点更逼近方程的解,以此法连续迭代,可快速求得合适精度的方程近似解.利用这个方法,解方程
,选取初始值
,在下面四个选项中最佳近似解为( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/09f86f37ec8e15846bd731ab4fcdbacd.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/79b752f0f189e5d8666daea73e145dff.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4288ce7da394135a8c5b0b067d384d09.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/910717f3df9f31b0ff377f65a16a4ca5.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8e099a6abe3e9566b2ad385906e323fc.png)
A.![]() | B.![]() | C.![]() | D.![]() |
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名校
7 . 根据多元微分求条件极值理论,要求二元函数
在约束条件
的可能极值点,首先构造出一个拉格朗日辅助函数
,其中
为拉格朗日系数.分别对
中的
部分求导,并使之为0,得到三个方程组,如下:
,解此方程组,得出解
,就是二元函数
在约束条件
的可能极值点.
的值代入到
中即为极值.
补充说明:【例】求函数
关于变量
的导数.即:将变量
当做常数,即:
,下标加上
,代表对自变量x进行求导.即拉格朗日乘数法方程组之中的
表示分别对
进行求导.
(1)求函数
关于变量
的导数并求当
处的导数值.
(2)利用拉格朗日乘数法求:设实数
满足
,求
的最大值.
(3)①若
为实数,且
,证明:
.
②设
,求
的最小值.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e4a1d0dba29a77dd111efcde543d6c1f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/bc4c14935585e8fa61d032730867d771.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/67b6f154c6b2de5695eb1807b98c2c63.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/df64046e91b047037f19e4032e3b6de3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/809615d1f91508e2c6c0cda7e592c479.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/244021f826099b18e31af1143597bba2.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/eb5be11a5e6aaf00b2833930b198b4cf.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0203b006524305c3d8ee0b6c34cd872b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e4a1d0dba29a77dd111efcde543d6c1f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/bc4c14935585e8fa61d032730867d771.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9b0fffbec1fe851795dfdd448bf0d165.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f1c3c1ed4fb65ab9505ad8078d8d0fb5.png)
补充说明:【例】求函数
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0d7ca0caa9933b7afd4bed2683140a07.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/81dea63b8ce3e51adf66cf7b9982a248.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d053b14c8588eee2acbbe44fc37a6886.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/aebdee8d81b048b5aa520f7e8ba56ff2.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/81dea63b8ce3e51adf66cf7b9982a248.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5a1e15a54c6122c695239107dd0901bc.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/244021f826099b18e31af1143597bba2.png)
(1)求函数
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9b3d9ab2fcf15b94f33cb64f84ed906c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d053b14c8588eee2acbbe44fc37a6886.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9b384412acba251d87902ab928902f16.png)
(2)利用拉格朗日乘数法求:设实数
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9b0fffbec1fe851795dfdd448bf0d165.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6c45d8122b61de13875003d00c002c5b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/de725a9fc66f67abbe0015131846a648.png)
(3)①若
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1a14c388e1e2e5a2ff1ccf6caffbee0d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/bd24c686fbaaa68705d654b880481ffe.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e778f95c72fec00bfbbc63e6dfd0c460.png)
②设
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/497d269c30eec393e3f0e877ddbe2983.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ade042c085bbad8aeaf111b9f4c33408.png)
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8 . 阅读理解:高斯上小学时,有一次数学老师让同学们计算“从1到100这100个正整数的和”.许多同学都采用了依次累加的计算方法,计算起来非常烦琐,且易出错.聪明的小高斯经过探索后,给出了下面漂亮的解答过程.
解:设
①,则
②,
①+②,得
.
(两式左右两端分别相加,左端等于2S,右端等于100个101的和)
所以
,
③,所以
.
后来人们将小高斯的这种解答方法概括为“倒序相加法”
计算:
= _____ .
解:设
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/45d05f7125540086a961efd2afddb588.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4663fd551144091fcd826a6ecd7a9603.png)
①+②,得
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6800c25d59d4bf730f469ce16412a7fe.png)
(两式左右两端分别相加,左端等于2S,右端等于100个101的和)
所以
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d46540f510d1f3537e0453ebb1bd6e9a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/da9c674c761493e544d7af9bb5046a86.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4ac52232d822e91ac25df49702ba8c71.png)
后来人们将小高斯的这种解答方法概括为“倒序相加法”
计算:
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/24d7c6e74c5501a04785b710ffe91ec6.png)
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解题方法
9 . 在组合恒等式的证明中,构造一个具体的计数模型从而证明组合恒等式的方法叫做组合分析法,该方法体现了数学的简洁美,我们将通过如下的例子感受其妙处所在.
(1)对于
元一次方程
,试求其正整数解的个数;
(2)对于
元一次方程组
,试求其非负整数解的个数;
(3)证明:
(可不使用组合分析法证明).
注:
与
可视为二元一次方程的两组不同解.
(1)对于
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b6a24198bd04c29321ae5dc5a28fe421.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/114b84ba3234b9bb1bf9f64c172292d7.png)
(2)对于
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b6a24198bd04c29321ae5dc5a28fe421.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/aa38e21db62123319c9557d1bc52825d.png)
(3)证明:
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d63a043e64f7ed5d168cd2c9384e953b.png)
注:
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/65fe832c0460e00120d4bc3636aebcaf.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/aa6c8fe63bb58df1c5a12422e9c9e291.png)
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2024-03-08更新
|
1116次组卷
|
3卷引用:辽宁省2024届高三下学期3+2+1模式新高考适应性统一考试数学试卷
10 . 判断正误,正确的写“正确”,错误的写“错误”.
(1)若两直线相交,则交点坐标一定是两直线方程所组成的二元一次方程组的解.( )
(2)无论m为何值,
与
必相交.( )
(3)若两直线的方程组成的方程组有解,则两直线相交.( )
(4)点
和点
之间的距离为
.( )
(5)在两点间的距离公式中
与
,
与
的位置可以互换,不影响计算结果.( )
(1)若两直线相交,则交点坐标一定是两直线方程所组成的二元一次方程组的解.
(2)无论m为何值,
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1b979396a703fb14715ba39232f5786a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2a09ee5220b905b6cadccbe09100fb25.png)
(3)若两直线的方程组成的方程组有解,则两直线相交.
(4)点
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f3acbcf5ca270d1b5edd8982bc8d590c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/af13e3c26639ac539f13f559b74a0cce.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c9f2416d1f75a45a314331146550832e.png)
(5)在两点间的距离公式中
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/aec19b68e3add9d5bfcc6269a1855b87.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c814128ea2139e33db94ea590e7c2223.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/46f6872ffb1934339c53c2c2282d5889.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/54015ff5b49e3283901da1291b6b921d.png)
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