解题方法
1 . 在
中,
的中点为
,把
绕
旋转一周,得到一个旋转体.
(1)求旋转体的体积;
(2)设从
点出发绕旋转体一周到达
点的最近路程为
,探究
与
的大小,并证明你的结论.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15c0dbe3c080c4c4636c64803e5c1f76.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/226fdcba5527912ee7d4c32eb74d7245.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8455657dde27aabe6adb7b188e031c11.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15c0dbe3c080c4c4636c64803e5c1f76.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/60ef95894ceebaf236170e8832dcf7e3.png)
(1)求旋转体的体积;
(2)设从
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8455657dde27aabe6adb7b188e031c11.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7f9e8449aad35c5d840a3395ea86df6d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/cf231f8f86fb922df4ca0c87f044cec3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/cf231f8f86fb922df4ca0c87f044cec3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6682956839817dd487ede5cbfc50f710.png)
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2 . 如图,在四棱锥
中,底面
为等腰梯形,
,
为等腰梯形的高,
,
平面
,
,
.
![](https://img.xkw.com/dksih/QBM/editorImg/2022/11/19/e2c68775-a270-46db-81ff-8fcef16f062e.png?resizew=233)
(1)证明:平面
平面
;
(2)求将
以
为旋转轴旋转一周得到的几何体的体积.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/80c753cb1eb73fd8d136d00462970797.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411b38a18046fea8e9fab1f9f9b80a5f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/10df84d553a8826a7ce9bff4bf0d95b9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a6655e2fa64a32cd12fe0279afd65d73.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ecdb8041c0cf7f3da0b449f1b282ab36.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9f4c3f9dd5d0343597a7f58a1989b537.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/90311cc187ccac8cb2113ed301582f45.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c03559a409275e0de25c861d80916e3f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7df42ded56944398787d0c17744ae3b7.png)
![](https://img.xkw.com/dksih/QBM/editorImg/2022/11/19/e2c68775-a270-46db-81ff-8fcef16f062e.png?resizew=233)
(1)证明:平面
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/eb57138eeb7b885bca148a8e869e1d8e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0c2a35f6795aed3f3b1a13713df357a4.png)
(2)求将
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/03a706b08c69fe2daf2e7cc8652d4902.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/826c728050e3378921442ace20269ef6.png)
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名校
解题方法
3 . 在空间直角坐标系
中,以坐标原点
为圆心,
为半径的球体上任意一点
,它到坐标原点
的距离
,可知以坐标原点为球心,
为半径的球体可用不等式
表示.还有很多空间图形也可以用相应的不等式或者不等式组表示,记
满足的不等式组
表示的几何体为
.
(1)当
表示的图形截
所得的截面面积为
时,求实数
的值;
(2)祖暅原理“幂势既同,则积不容异”.意思是:夹在两个平行平面之间的两个几何体,被平行于这两个平面的任意平面所截,如果截得的两个截面的面积相等,则这两个几何体的体积相等.记
满足的不等式组
所表示的几何体为
请运用祖暅原理求证
与
的体积相等,并求出体积的大小.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d5e336d6ca2cae3d6e6c3810d7e521a4.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1dde8112e8eb968fd042418dd632759e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/11bc05f41215f9894e11d1df0465751a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/80889d020ffcd8dbc2499fe135f82bd1.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1dde8112e8eb968fd042418dd632759e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/50fa0f65abad2a110595a4e5d0229cd2.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/11bc05f41215f9894e11d1df0465751a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6a081fb17e159a4378a2414cb1fac1c4.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2708fa6298e52f617383efc175b71ddc.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1c7b230f0873760f043aeb5299fabc85.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5c3ff0b0fea1cb642d3f6be77a1ff32f.png)
(1)当
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dfcff373b650f57e068b74b3356a9f4f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5c3ff0b0fea1cb642d3f6be77a1ff32f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0cb9c018281fcaaf52863e1f83d9dad0.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3eabd5f3a86afe49dcd70571e2b96cfd.png)
(2)祖暅原理“幂势既同,则积不容异”.意思是:夹在两个平行平面之间的两个几何体,被平行于这两个平面的任意平面所截,如果截得的两个截面的面积相等,则这两个几何体的体积相等.记
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9b9cb8e6ff801523b0304576cd69fd2d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/09961db78b0c4ed3ff88c811285142c5.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ad8301e48190608ab476dc69ec6a26dd.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a6eaa137a2290a9a9ec7ad635d17dbb6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5c3ff0b0fea1cb642d3f6be77a1ff32f.png)
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解题方法
4 . 如图,在正方体
中,作棱锥
,其中点
在侧棱
所在直线上,
,
,
是
的中点.
![](https://img.xkw.com/dksih/QBM/2020/6/30/2496013121249280/2496452268638208/STEM/339078dc-c5df-4fcf-aad8-b27452e03f88.png)
(1)证明:
平面
;
(2)求
以
为轴旋转所围成的几何体体积.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6e09725691ee7851f54c0dee86b2bf55.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0585b6c0f156eecf9662b9846d4eb693.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dad2a36927223bd70f426ba06aea4b45.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/22adbc0da438220f9cace11b629d799b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/58fc6a5e71fa379d613ac1ef1cdf1048.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/40560ea08d6cd8c1d4d9661ee6faaa3b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2a30f3a8b673cc28bd90c50cf1a35281.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/48f3c9abbd78e9a6840ee5f30381daac.png)
![](https://img.xkw.com/dksih/QBM/2020/6/30/2496013121249280/2496452268638208/STEM/339078dc-c5df-4fcf-aad8-b27452e03f88.png)
(1)证明:
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f8c2b786c64e6a9ed2ec5670cde74f86.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/34be4e71cabf458f17a6cd7f24bc70af.png)
(2)求
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/55a675310c8ba418e5a59beb7317e21e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/bd33764ff4efddfe11a98a609753715c.png)
您最近一年使用:0次
名校
5 . 祖暅(公元前5-6世纪),祖冲之之子,是我国齐梁时代的数学家.他提出了一条原理:“幂势既同,则积不容异.”这句话的意思是两个等高的几何体若在所有等高处的水平截面的面积相等,则这两个几何体的体积相等,该原理在西方直到十七世纪才由意大利数学家卡瓦列利发现,比祖暅晚一千一百多年.椭球体是椭圆绕其轴旋转所成的旋转体.如图将底面直径皆为2b,高皆为a的椭半球体及已被挖去了圆锥体的圆柱体放置于同一平面
上.以平行于平面
的平面距平面
任意高d处可横截得到
及
两截面,可以证明
总成立.据此,短轴长为4,长轴长为6的椭球体的体积是().
![](https://img.xkw.com/dksih/QBM/2020/4/16/2442986096869376/2443496966684672/STEM/02130107-673c-4914-9a72-c9f880a7740d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5b5858ee1ce52b251816757257a11c29.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5b5858ee1ce52b251816757257a11c29.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5b5858ee1ce52b251816757257a11c29.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1412bb5c926c15b192eefe0795015074.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/fd79498dbcdfc8f158ac6acd69cdb133.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/81a5521fd7492c1a325a423571dee25c.png)
![](https://img.xkw.com/dksih/QBM/2020/4/16/2442986096869376/2443496966684672/STEM/02130107-673c-4914-9a72-c9f880a7740d.png)
A.![]() | B.![]() | C.![]() | D.![]() |
您最近一年使用:0次
2020-04-17更新
|
377次组卷
|
2卷引用:福建省福州市第一中学2020年高二下学期开学前质检数学试题