名校
解题方法
1 . 已知
,
为两条不同的直线,
,
为两个不同的平面,则下列结论正确的是( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/294f5ba74cdf695fc9a8a8e52f421328.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b6a24198bd04c29321ae5dc5a28fe421.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e170f206fdbbd834aad7580c727e2cc6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5b5858ee1ce52b251816757257a11c29.png)
A.若![]() ![]() ![]() | B.若![]() ![]() ![]() ![]() |
C.若![]() ![]() ![]() ![]() ![]() | D.若![]() ![]() ![]() ![]() |
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2 . 我国南北朝的伟大科学教祖暅于5世纪提出了著名的祖暅原理,意思就是:夹在两个平行平面之间的两个几何体,被平行于这两个平面的任意平面所截,如果截得的两个几截面的面积总相等,那么这两个几何体的体积相等.如图1,为了求半球的体积,可以构造一个底面半径和高都与半球的半径相等的圆柱,与半球放置在同一平面上,然后在圆柱内挖去一个以圆柱下底面圆心为顶点,圆柱上底面为底面的圆锥后得到一个新几何体,用任何一个平行底面的平面去截它们时,两个截面面积总相等.如图2,某个清代陶瓷容器的上、下底面为互相平行的圆面(上底面开口,下底面封闭),侧面为球面的一部分,上、下底面圆半径都为6cm,且它们的距离为24cm,则该容器的容积为______
(容器的厚度忽略不计).
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dc6d1d99afa158b4ba4fc0dae562fcc1.png)
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3 . 已知正四棱台
的上、下底面边长分别为2和4,直线
与
的夹角为
,则该正四棱台的体积为( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6e09725691ee7851f54c0dee86b2bf55.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2777840758e70e7dbbc18cef8f3d6d2b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9d88bf46ad08f9677c37eed1d0369329.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a2d9a1a93e47dc1e50ba2779ef480724.png)
A.![]() | B.![]() | C.![]() | D.![]() |
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解题方法
4 . 某广场设置了一些石凳供大家休息,这些石凳是由正方体截去八个相同的四面体得到的(如图),若被截正方体的棱长是6dm,那么该几何体的表面积是______
.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/829047552d880c8fe5649217c74b5e17.png)
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5 . 我国魏晋时期的数学家刘徽(图a)创造了一个称为“牟合方盖”的立体图形,在正方体内作两个互相垂直的内切圆柱(图b),其相交的部外就是牟合方盖(图c).我国南北朝时期数学家祖暅基于“势幂既同则积不容异”这一观点和对牟合方盖性质的研究,推导出了球体体积公式.已知在一个棱长为2r的正方体内有一个牟合方盖(图1),设平行于水平面且与水平面距离为
的平面为
,则平面
截牟合方盖所得截面的形状为__________ (填“正方形”或“圆形”),设这个牟合方盖的体积为
(图2),并设半径为
的球的体积为
,则![](https://staticzujuan.xkw.com/quesimg/Upload/formula/caa4c480d031dedac6e81872836d04cc.png)
__________ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5547c2bb8607c1dba2bb0881777dbb34.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e170f206fdbbd834aad7580c727e2cc6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e170f206fdbbd834aad7580c727e2cc6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c4764374bd2fb78e59cd0b283637baeb.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/11bc05f41215f9894e11d1df0465751a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c63055a5d6916f99d07fede49120753f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/caa4c480d031dedac6e81872836d04cc.png)
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6 . 如图,在三棱锥
中,
平面
,E,F分别为BC,PC的中点,且
.
;
(2)求直线EF与平面ABC所成角的正弦值;
(3)求
到平面AEF的距离.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/63397cda22cb1fad59cf966dfb588643.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e56fdf217165748fafe938b64fa08179.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1e582d73b96ba649378379c3074d506d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/28a219cbad3454275ec748c3e00d535c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/bafa8c14100a4f847b41b9148954116c.png)
(2)求直线EF与平面ABC所成角的正弦值;
(3)求
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c5db41a1f31d6baee7c69990811edb9f.png)
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7 . 已知四边形
为直角梯形,
,
为等腰直角三角形,平面
平面
为
的中点,
.
平面
;
(2)求
与平面
所成角的正弦值.
(3)求二面角
的正弦值.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411b38a18046fea8e9fab1f9f9b80a5f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4795ee1f96b430529934e2231b38885d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dcdb57d8e4041a23abe672105716e587.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/93edc7bb513f40a89173121c8570cd65.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/23d11e19c84255eb0431415c2dec553d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/bd33764ff4efddfe11a98a609753715c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e99431b9cc5b5c487894efaed5500593.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c372d059202ec388960b125d4a87dc84.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/218054144a13435580cd132b9459546c.png)
(2)求
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e6e490f703eb6c9bb1278c78ebc2d661.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8f571a1aac46c6d0cf440c0ec2846bf9.png)
(3)求二面角
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/816b7f285cc55bbe5bf873538ba87230.png)
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解题方法
8 . 正三棱柱
的底面正三角形的边长为
为
的中点;
.![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e26d9636ad77369535852c6e4493446a.png)
平面
;
(2)求证:![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ca1ebdf74ee45f3736307d4a7e64717f.png)
(3)求
到平面
的距离.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/42d3a82b8e587ee890467835bc4e854c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3c1bd8a678857b47bb627e665ce58df5.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0dc5c9827dfd0be5a9c85962d6ccbfb1.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e8d927585a17c2e98ef7d5a9589a26ac.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e26d9636ad77369535852c6e4493446a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/638537c0a30676c73fea76c80e0f8bd0.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4ba9e20d667d04bf3ee7f55cc795ce01.png)
(2)求证:
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ca1ebdf74ee45f3736307d4a7e64717f.png)
(3)求
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c5db41a1f31d6baee7c69990811edb9f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/41104641f3e2260d00aeadf8fb8a078a.png)
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解题方法
9 . 如图,已知四面体
的各条棱长均等于
分别是棱
的中点.若用一个与直线
垂直,且与四面体的每一个面都相交的平面
去截该四面体,由此得到一个多边形截面
,当截面
面积最大时,四棱锥
的体积为__________ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411b38a18046fea8e9fab1f9f9b80a5f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2612d8c87010adfe87728a591b63e3a9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6d93949d8a15aca4e79cedb978590571.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/49b50357a6545cae8348e3059312f520.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e170f206fdbbd834aad7580c727e2cc6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a315e4b5963127bf8550cde03ca1966d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a315e4b5963127bf8550cde03ca1966d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9df6a9fadc944f228ec12642a194f35e.png)
![](https://img.xkw.com/dksih/QBM/editorImg/2024/6/17/50b73dc0-268c-4c34-bdb4-8ac147cdf3e5.png?resizew=168)
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10 . 在棱长为 1 的正方体
中,已知
分别为线段
的中点,点
满足
,则( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6e09725691ee7851f54c0dee86b2bf55.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3cf9b288c48c73463a2f214f02b6952a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/85789b7d63712c81dcc0fb60014bbb8d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dad2a36927223bd70f426ba06aea4b45.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9b829ac65651fac7a19a0b837939c3ff.png)
A.当![]() ![]() |
B.当![]() ![]() ![]() |
C.![]() ![]() |
D.若![]() ![]() ![]() |
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2卷引用:浙江省名校新高考研究联盟(Z20名校联盟)2024届高三第三次联考(三模)数学试题