名校
1 . 嵩岳寺塔位于河南郑州登封市嵩岳寺内,历经1400多年风雨侵蚀,仍巍然屹立,是中国现存最早的砖塔.如图,为测量塔的总高度
,选取与塔底
在同一水平面内的两个测量基点
与
,现测得
,
,
,在
点测得塔顶
的仰角为
,则塔的总高度为( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f52a58fbaf4fea03567e88a9f0f6e37e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7f9e8449aad35c5d840a3395ea86df6d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c5db41a1f31d6baee7c69990811edb9f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8455657dde27aabe6adb7b188e031c11.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/13b1e717e9fc4481050672eec8ac5c0e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6d1bef59e1247b1bb7522ac9122b4f89.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/fe716456277ae45f602185cf5bb03700.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c5db41a1f31d6baee7c69990811edb9f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5963abe8f421bd99a2aaa94831a951e9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2d5bca00fa20e6e80480b9d06d2e52ee.png)
A.(![]() | B.(![]() |
C.(![]() | D.(![]() |
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2024-03-15更新
|
510次组卷
|
6卷引用:数学建模-测量与距离问题(空间)
(已下线)数学建模-测量与距离问题(空间)河北省沧州市2020-2021学年高一下学期期末数学试题四川省宜宾市宜宾市第四中学校2022-2023学年高一下学期期末数学试题(已下线)6.4.3 第3课时 余弦定理、正弦定理应用举例【第一练】“上好三节课,做好三套题“高中数学素养晋级之路重庆市清华中学校2023-2024学年高一下学期5月期中检测数学试题(已下线)专题02 平面向量的应用-《期末真题分类汇编》(人教A版2019必修第二册)
解题方法
2 . 如图所示,为测量一树的高度,在地面上选取A,B两点,从A,B两点测得树尖的仰角分别为
和
,且A,B两点之间的距离为60m,则树的高度为( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f6b86c22b670a8e9f3896f9e8883fbbb.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/79a97bb4dcfab4ec7539bc783d563c49.png)
![](https://img.xkw.com/dksih/QBM/editorImg/2023/7/9/b4633482-9978-4def-9487-62a2e81c8a4a.png?resizew=197)
A.![]() | B.![]() |
C.![]() | D.![]() |
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3 . 钝角三角形的三边长分别
,
,
,且最大角不超过
,求实数
的取值范围.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0a6936d370d6a238a608ca56f87198de.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/83666674f1111c699d7c5f7b792e0285.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7570c77bd375f4dfdffee64fce8d1a9a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a6c0927afc571a7c966c98192040979e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0a6936d370d6a238a608ca56f87198de.png)
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4 . 如图所示,在海岸A处,发现北偏东45°方向,距A为
km的B处有一艘走私船.在A处北偏西75°方向,距A为2 km的C处的缉私船奉命以
km/h的速度追截走私船.此时走私船正以10km/h的速度从B处向北偏东30°方向逃窜,则缉私船沿什么方向能最快追上走私船?并求出所需要的时间.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d4ec0a07284e75d0fbb56a8587987069.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/84e4123975f257306440158659634c4a.png)
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2023-07-10更新
|
222次组卷
|
2卷引用:1.6.3 解三角形应用举例 课时作业
5 . 某人沿一条折线段组成的小路前进,从
到
,方位角(从正北方向顺时针转到
方向所成的角)是
,距离是
;从
到
,方位角是
,距离是
;从
到
,方位角是
,距离是 ![](https://staticzujuan.xkw.com/quesimg/Upload/formula/68db0ad6a96b58b71f6e879af61b8eae.png)
(1)求从
到
的方位角;
(2)计算从
到
的距离.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5963abe8f421bd99a2aaa94831a951e9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7f9e8449aad35c5d840a3395ea86df6d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f52a58fbaf4fea03567e88a9f0f6e37e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2fb94bd9eb80fb9f5f02f518bb8f2211.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1890f0b4e81634bb7e013412698640f3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7f9e8449aad35c5d840a3395ea86df6d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c5db41a1f31d6baee7c69990811edb9f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/27ef3e89c37d21fd86537bee7c57b053.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1890f0b4e81634bb7e013412698640f3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c5db41a1f31d6baee7c69990811edb9f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8455657dde27aabe6adb7b188e031c11.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6e012dbccbaac604c8d9f48159fb21d1.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/68db0ad6a96b58b71f6e879af61b8eae.png)
(1)求从
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5963abe8f421bd99a2aaa94831a951e9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8455657dde27aabe6adb7b188e031c11.png)
(2)计算从
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5963abe8f421bd99a2aaa94831a951e9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8455657dde27aabe6adb7b188e031c11.png)
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解题方法
6 . 在
中,角A,
,
所对的边分别为
,
,
,且
,则下列结论正确的是( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15c0dbe3c080c4c4636c64803e5c1f76.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7f9e8449aad35c5d840a3395ea86df6d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c5db41a1f31d6baee7c69990811edb9f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0a6936d370d6a238a608ca56f87198de.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2c94bb12cee76221e13f9ef955b0aab1.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/071a7e733d466949ac935b4b8ee8d183.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c1805ddec0817faad2d0dda33c4f39d9.png)
A.![]() |
B.![]() |
C.![]() |
D.若![]() ![]() ![]() |
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解题方法
7 . 在
中,若
,则
的形状为______ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15c0dbe3c080c4c4636c64803e5c1f76.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ed92c6b7ba2704901e52c665b9f4dd71.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15c0dbe3c080c4c4636c64803e5c1f76.png)
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8 . 如图所示,为了测量隧道口AB的长度,给定下列四组数据,测量时应选用数据( )
![](https://img.xkw.com/dksih/QBM/editorImg/2023/7/9/dcf24534-130b-4560-bcb8-ffe0b50ff04c.jpg?resizew=146)
A.![]() | B.![]() |
C.![]() | D.![]() |
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9 . 如图所示,为了测量河对岸的塔高AB,有不同的方案,其中之一是选取与塔底B在同一水平面内的两个测点C和D,测得CD=200米,在C点和D点测得塔顶A的仰角分别是45°和30°,且∠CBD=30°,求塔高AB.
![](https://img.xkw.com/dksih/QBM/editorImg/2023/7/9/8b0d98bd-a931-4355-875e-5ff315bcbd1b.png?resizew=160)
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10 . 某人在山外一点测得山顶的仰角为42°,沿水平面退后30米,又测得山顶的仰角为39°,则山高为( )(sin42°≈0.6691,sin39°≈0.6293,sin3°≈0.0523)
A.180米 | B.214米 | C.242米 | D.266米 |
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