1 . 解不等式组及计算:
(1)解不等式组![](https://staticzujuan.xkw.com/quesimg/Upload/formula/09b2fdadaaec3762b29658146dd94010.png)
(2)因式分解:![](https://staticzujuan.xkw.com/quesimg/Upload/formula/93aeb4732bc25e7793e70e618e2a60b5.png)
(3)解方程:
;
(4)先化简,再求值:
,从
,0,2中取一个合适的数作为x的值代入求值.
(1)解不等式组
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/09b2fdadaaec3762b29658146dd94010.png)
(2)因式分解:
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/93aeb4732bc25e7793e70e618e2a60b5.png)
(3)解方程:
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6f4a16ba60d105e018f5bad9ed3e3ad0.png)
(4)先化简,再求值:
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0053981d6fa80df1c15ec84fccd700a4.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/274a9dc37509f01c2606fb3086a46f4f.png)
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2022高一·全国·专题练习
2 . 已知
,
满足方程组
,且
.
(1)试用含
的式子表示方程组的解;
(2)求实数
的取值范围;
(3)化简
.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/81dea63b8ce3e51adf66cf7b9982a248.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d053b14c8588eee2acbbe44fc37a6886.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/74505a91ab0c9038b2e5481131bb1342.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/fc8d93ef14e700c6bed4e4d31625925a.png)
(1)试用含
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/294f5ba74cdf695fc9a8a8e52f421328.png)
(2)求实数
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/294f5ba74cdf695fc9a8a8e52f421328.png)
(3)化简
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ea3d52af08461102a97ea9cc12ea168a.png)
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2022高一·全国·专题练习
3 . (1)解不等式
,并将其解集在数轴上表示出来;
(2)解不等式组并把解集在数轴上表示出来:
.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a64628175df0e4fd35d2d618e615f4bc.png)
(2)解不等式组并把解集在数轴上表示出来:
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5683b7974117fff8aa416c389b985ff3.png)
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4 . 牛顿迭代法是我们求方程近似解的重要方法.对于非线性可导函数
在
附近一点的函数值可用
代替,该函数零点更逼近方程的解,以此法连续迭代,可快速求得合适精度的方程近似解.利用这个方法,解方程
,选取初始值
,在下面四个选项中最佳近似解为( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/09f86f37ec8e15846bd731ab4fcdbacd.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/79b752f0f189e5d8666daea73e145dff.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4288ce7da394135a8c5b0b067d384d09.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/910717f3df9f31b0ff377f65a16a4ca5.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8e099a6abe3e9566b2ad385906e323fc.png)
A.![]() | B.![]() | C.![]() | D.![]() |
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名校
5 . 根据多元微分求条件极值理论,要求二元函数
在约束条件
的可能极值点,首先构造出一个拉格朗日辅助函数
,其中
为拉格朗日系数.分别对
中的
部分求导,并使之为0,得到三个方程组,如下:
,解此方程组,得出解
,就是二元函数
在约束条件
的可能极值点.
的值代入到
中即为极值.
补充说明:【例】求函数
关于变量
的导数.即:将变量
当做常数,即:
,下标加上
,代表对自变量x进行求导.即拉格朗日乘数法方程组之中的
表示分别对
进行求导.
(1)求函数
关于变量
的导数并求当
处的导数值.
(2)利用拉格朗日乘数法求:设实数
满足
,求
的最大值.
(3)①若
为实数,且
,证明:
.
②设
,求
的最小值.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e4a1d0dba29a77dd111efcde543d6c1f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/bc4c14935585e8fa61d032730867d771.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/67b6f154c6b2de5695eb1807b98c2c63.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/df64046e91b047037f19e4032e3b6de3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/809615d1f91508e2c6c0cda7e592c479.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/244021f826099b18e31af1143597bba2.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/eb5be11a5e6aaf00b2833930b198b4cf.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0203b006524305c3d8ee0b6c34cd872b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e4a1d0dba29a77dd111efcde543d6c1f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/bc4c14935585e8fa61d032730867d771.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9b0fffbec1fe851795dfdd448bf0d165.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f1c3c1ed4fb65ab9505ad8078d8d0fb5.png)
补充说明:【例】求函数
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0d7ca0caa9933b7afd4bed2683140a07.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/81dea63b8ce3e51adf66cf7b9982a248.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d053b14c8588eee2acbbe44fc37a6886.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/aebdee8d81b048b5aa520f7e8ba56ff2.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/81dea63b8ce3e51adf66cf7b9982a248.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5a1e15a54c6122c695239107dd0901bc.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/244021f826099b18e31af1143597bba2.png)
(1)求函数
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9b3d9ab2fcf15b94f33cb64f84ed906c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d053b14c8588eee2acbbe44fc37a6886.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9b384412acba251d87902ab928902f16.png)
(2)利用拉格朗日乘数法求:设实数
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9b0fffbec1fe851795dfdd448bf0d165.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6c45d8122b61de13875003d00c002c5b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/de725a9fc66f67abbe0015131846a648.png)
(3)①若
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1a14c388e1e2e5a2ff1ccf6caffbee0d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/bd24c686fbaaa68705d654b880481ffe.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e778f95c72fec00bfbbc63e6dfd0c460.png)
②设
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/497d269c30eec393e3f0e877ddbe2983.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ade042c085bbad8aeaf111b9f4c33408.png)
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6 . 阅读理解:高斯上小学时,有一次数学老师让同学们计算“从1到100这100个正整数的和”.许多同学都采用了依次累加的计算方法,计算起来非常烦琐,且易出错.聪明的小高斯经过探索后,给出了下面漂亮的解答过程.
解:设
①,则
②,
①+②,得
.
(两式左右两端分别相加,左端等于2S,右端等于100个101的和)
所以
,
③,所以
.
后来人们将小高斯的这种解答方法概括为“倒序相加法”
计算:
= _____ .
解:设
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/45d05f7125540086a961efd2afddb588.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4663fd551144091fcd826a6ecd7a9603.png)
①+②,得
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6800c25d59d4bf730f469ce16412a7fe.png)
(两式左右两端分别相加,左端等于2S,右端等于100个101的和)
所以
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d46540f510d1f3537e0453ebb1bd6e9a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/da9c674c761493e544d7af9bb5046a86.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4ac52232d822e91ac25df49702ba8c71.png)
后来人们将小高斯的这种解答方法概括为“倒序相加法”
计算:
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/24d7c6e74c5501a04785b710ffe91ec6.png)
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解题方法
7 . 在组合恒等式的证明中,构造一个具体的计数模型从而证明组合恒等式的方法叫做组合分析法,该方法体现了数学的简洁美,我们将通过如下的例子感受其妙处所在.
(1)对于
元一次方程
,试求其正整数解的个数;
(2)对于
元一次方程组
,试求其非负整数解的个数;
(3)证明:
(可不使用组合分析法证明).
注:
与
可视为二元一次方程的两组不同解.
(1)对于
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b6a24198bd04c29321ae5dc5a28fe421.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/114b84ba3234b9bb1bf9f64c172292d7.png)
(2)对于
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b6a24198bd04c29321ae5dc5a28fe421.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/aa38e21db62123319c9557d1bc52825d.png)
(3)证明:
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d63a043e64f7ed5d168cd2c9384e953b.png)
注:
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/65fe832c0460e00120d4bc3636aebcaf.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/aa6c8fe63bb58df1c5a12422e9c9e291.png)
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2024-03-08更新
|
1113次组卷
|
3卷引用:压轴题08计数原理、二项式定理、概率统计压轴题6题型汇总
8 . “黄金分割”是古希腊的毕达哥拉斯学派在研究数学问题时提出的一个比例关系,即:将一线段分割成大小两段,如果小段与大段的长度之比恰好等于大段与整段的长度之比,那么称这个比值为“黄金分割比”,经常用希腊字母
来表示.在数学中也可用无穷连分数
(其中“…”代表无限次重复)来表示“黄金分割比”,它可以通过方程
解得
,即黄金分割比为
.类比上述过程,计算式子
的值为( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a37502db587be8f665f851e952162ae2.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/34171e130641b4c17fe9c659be63d14e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b6a31a869c72e1330b2e12716ddd0b8e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c86cb753ef281db76db9f9fffea1a998.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/029d393bb07b7140905b85f550519de4.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b3f4d0c458d8751f5d19e8a44fc97315.png)
A.1 | B.![]() | C.![]() | D.![]() |
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2021-07-01更新
|
377次组卷
|
3卷引用:考点42 合情推理与演绎推理-备战2022年高考数学(理)一轮复习考点微专题
2022高一·全国·专题练习
9 . 新定义:若一元一次方程的解在一元一次不等式组解集范围内,则称该一元一次方程为该不等式组的“相依方程”,例如:方程
的解为
,而不等式组
的解集为
,不难发现
在
的范围内,所以方程
是不等式组
的“相依方程”.
(1)在方程①
;②
;③
中,不等式组
的“相依方程”是 ;(填序号)
(2)若关于x的方程
是不等式组
的“相依方程”,求k的取值范围.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/eb8e4bbc9f6c98374f360c90f4cc8940.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f23d29646155e27b172ecdf263e2d702.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c3788cfd95beef71f146c508fbc387cc.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8ef8634d2d5a531ebffd843f50644b27.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f23d29646155e27b172ecdf263e2d702.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8ef8634d2d5a531ebffd843f50644b27.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/eb8e4bbc9f6c98374f360c90f4cc8940.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c3788cfd95beef71f146c508fbc387cc.png)
(1)在方程①
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/815650356afb1f42207c27d3b11635f1.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9ce0d12723a479d03bcdcf36b61dc9ab.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/08863eecc79e481b27b550ee9f89d54f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5848b00576e5e657ce3ef889f117d04d.png)
(2)若关于x的方程
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/00b3493fcf2f0b76dfc7249a24c5556f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/057ee5107a86fd287a33f5a5b706163d.png)
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10 . 对一般的实系数一元三次方程
,由于总可以通过代换
消去其二次项,就可以变为方程
.在一些数学工具书中,我们可以找到方程
的求根公式,这一公式被称为卡尔丹公式,它是以16世纪意大利数学家卡尔丹(J.Cardan)的名字命名的.
卡尔丹公式的获得过程如下:三次方程
可以变形为
,把未知数x写成两数之和
,再把等式
的右边展开,就得到
,即
.将上式与
相对照,得到
,把此方程组中的第一个方程两边同时作三次方,
,并把
与
看成未知数,解得
,于是,方程
一个根可以写成
.
阅读以上材料,求解方程
.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/eccb3856fa5aa8dc822a593ec88ca2bf.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ae0f3c81f415857813838d4b9b714d56.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b5dd275a6062b21f9c3e9155c7e0ba62.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b5dd275a6062b21f9c3e9155c7e0ba62.png)
卡尔丹公式的获得过程如下:三次方程
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b5dd275a6062b21f9c3e9155c7e0ba62.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7ead1b77b69e6b51d6d483331fd01d41.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f0bed1a02239821a616bc173181e7ed2.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8c26aacdd3362aa65b2966045cbfcddf.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3f02c3aa1326c9b1e069b6997cd29bfa.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/11792ad247341c0dbc80663dd0fa6f77.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7ead1b77b69e6b51d6d483331fd01d41.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b7a28d84fa30daeb6cfcb0347d1d40a9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/718a7346b05d9a0c4f31a60d8786404b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/36accab23dbd172687769aea43e5781c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411a315870ed3e6d0e8ea885f1a04bcf.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8b79aba80a3fc337b27ed567abf1e5c4.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b5dd275a6062b21f9c3e9155c7e0ba62.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/49d63387694fd1caafce80adfb43c86b.png)
阅读以上材料,求解方程
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/93c3d494147195cf4f5e1fa3f6f5a0b9.png)
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