如图,在棱柱ABCD﹣A′B′C′D′中,底面ABCD为平行四边形,CD=2AD=4,∠BAD
,且D′在底面上的投影H恰为CD的中点.
![](https://img.xkw.com/dksih/QBM/editorImg/2022/11/13/54d2997d-265d-4090-96ae-1f80ab6228e5.png?resizew=192)
(1)过D′H作与BC垂直的平面α,交棱BC于点N,试确定点N的位置,并说明理由;
(2)若二面角C′﹣BH﹣A为
,求棱柱ABCD﹣A′B′C′D′的体积.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5b3052da2d1bc23ddce31da1fbe42a6f.png)
![](https://img.xkw.com/dksih/QBM/editorImg/2022/11/13/54d2997d-265d-4090-96ae-1f80ab6228e5.png?resizew=192)
(1)过D′H作与BC垂直的平面α,交棱BC于点N,试确定点N的位置,并说明理由;
(2)若二面角C′﹣BH﹣A为
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4c4b919d156fd398123816a4b5f4aac1.png)
2021·广东广州·三模 查看更多[5]
广东省广州市天河区2021届高三三模数学试题(已下线)13.3 空间图形的表面积和体积-2020-2021学年高一数学同步课堂帮帮帮(苏教版2019必修第二册)(已下线)第20题 立体几何解答题的两大主题:线面位置的证明及空间角-2021年高考数学真题逐题揭秘与以例及类(新高考全国Ⅰ卷)(已下线)查补易混易错点05 空间向量与立体几何-【查漏补缺】2022年高考数学三轮冲刺过关(新高考专用)河北省沧州市任丘市第一中学2020-2021学年高一下学期第二次阶段考数学试题
更新时间:2021-07-06 15:26:38
|
相似题推荐
【推荐1】如图,在平行六面体中
,
,
,
平面
,
与底面
所成角为
,
.
![](https://img.xkw.com/dksih/QBM/2020/2/11/2396872370823168/2397585144004608/STEM/7d1f647d1fb444aeb5954a59062f384b.png?resizew=401)
(1)求证:平行六面体
的体积
,并求
的取值范围;
(2)若
,求异面直线
与
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(1)求证:平行六面体
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6e09725691ee7851f54c0dee86b2bf55.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c8db0de179cadd656e88859c38b82e04.png)
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(2)若
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/67e696de930676f7a5b4b7be984ce400.png)
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【推荐2】如图1,在直三棱柱
中,
,
,
,
,
分别为
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的中点,平面
将三棱柱分成两个新的直三棱柱(如图2,3所示).
![](https://img.xkw.com/dksih/QBM/editorImg/2022/11/28/7183168f-7204-4fe0-8df6-f5971f7957dd.png?resizew=429)
(1)若两个新直三棱柱的表面积之和为72,求实数
的值;
(2)将图2和图3两个直三棱柱重新组合成一个直四棱柱,若组成的所有直四棱柱的表面积都小于132,求实数
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![](https://img.xkw.com/dksih/QBM/editorImg/2022/11/28/7183168f-7204-4fe0-8df6-f5971f7957dd.png?resizew=429)
(1)若两个新直三棱柱的表面积之和为72,求实数
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(2)将图2和图3两个直三棱柱重新组合成一个直四棱柱,若组成的所有直四棱柱的表面积都小于132,求实数
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解答题-证明题
|
适中
(0.65)
【推荐1】如图,在三棱柱
中,
侧面
,已知
,
,
.
![](https://img.xkw.com/dksih/QBM/2012/7/16/1570926421106688/1570926426349568/STEM/e4033190d0664822978de2c67382f98f.png?resizew=230)
(1)求证:
平面
;
(2)试在棱
(不包含端点
上确定一点
的位置,使得
;
(3)在(2)的条件下,求二面角
的平面角的正切值.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/42d3a82b8e587ee890467835bc4e854c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/21f9157fce2a8339d281178c7c0bccbe.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/58cc6184b191e6da43911e701121517e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/92535536bd3c2761724fd058427f95a8.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/21ea52361458ce2e49ed0fe99d8e6c02.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f98daab2b277b67e14454772d3e0d3fd.png)
![](https://img.xkw.com/dksih/QBM/2012/7/16/1570926421106688/1570926426349568/STEM/e4033190d0664822978de2c67382f98f.png?resizew=230)
(1)求证:
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/06ad7c180d6d084ecb25f23cb6fe9b10.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7bef5239ddbb0972700ce01daf9ee7cf.png)
(2)试在棱
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9d88bf46ad08f9677c37eed1d0369329.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d6e5090124abbafa4601c9b7b2c942c8.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2a30f3a8b673cc28bd90c50cf1a35281.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4a7fda523ada8989e466d797b6fcd2e0.png)
(3)在(2)的条件下,求二面角
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/69cbd2557ef69775b5a883c510091985.png)
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解答题-证明题
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适中
(0.65)
解题方法
【推荐2】如图,几何体ABC-EFD是由直三棱柱截得的,EF //AB,∠ABC=90°,AC=2AB =2,CD=2AE=
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(I)求三棱锥D-BEC的体积;
(I I)求证:CE⊥DB
![](https://img.xkw.com/dksih/QBM/editorImg/2022/6/15/cb01d1c9-e51f-4f26-b0de-c90a0e7e7c31.png?resizew=142)
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解答题-问答题
|
适中
(0.65)
【推荐3】如图三棱柱
中,
平面
.
![](https://img.xkw.com/dksih/QBM/editorImg/2022/11/4/8cb31f1f-deb6-48bb-8cde-017a9d5ce703.png?resizew=212)
(1)证明:
平面
;
(2)求
与平面
所成的角的正弦值.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/42d3a82b8e587ee890467835bc4e854c.png)
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![](https://img.xkw.com/dksih/QBM/editorImg/2022/11/4/8cb31f1f-deb6-48bb-8cde-017a9d5ce703.png?resizew=212)
(1)证明:
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/21f9157fce2a8339d281178c7c0bccbe.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2d9a8181f7a7fe7f3fac872ce9534f15.png)
(2)求
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b470c4e195cf7a07b7a331ce4b436e03.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8f664c0db517bec6886ff0b6100fd474.png)
您最近一年使用:0次
解答题-证明题
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适中
(0.65)
【推荐1】如图,在四棱锥
中,底面
是直角梯形,
平面
,
是边
上一点,且满足
是正方形,
.
(1)求证:平面
平面
;
(2)已知:
,二面角
的平面角为
.是否存在
,使得
?若存在,求出
;若不存在,说明理由.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0585b6c0f156eecf9662b9846d4eb693.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411b38a18046fea8e9fab1f9f9b80a5f.png)
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![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411b38a18046fea8e9fab1f9f9b80a5f.png)
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![](https://img.xkw.com/dksih/QBM/editorImg/2023/8/2/8f22269a-c714-4ac3-aa57-b4d14e934a5c.png?resizew=146)
(1)求证:平面
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2d24305d21268a9b67cf6a8daae6bbe4.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0628681907ac8d7fdb94d8bc1b15feb9.png)
(2)已知:
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/61fae7879445fdd8e34f49f26d1e6ec8.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1636b4530c0b42d0e0b649e90e3b9e85.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c24095e409b025db711f14be783a406c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/df64046e91b047037f19e4032e3b6de3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a2331c755ff3034217ea3d9f45b25f62.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/df64046e91b047037f19e4032e3b6de3.png)
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解答题-证明题
|
适中
(0.65)
解题方法
【推荐2】如图,四棱锥
的底面为矩形,
,
面
,
是
的中点,
为
上一点,且
面
.
![](https://img.xkw.com/dksih/QBM/2011/4/2/1570100114989056/1570100120297472/STEM/5c1fae4f32574751b723e363a25b4fe6.png?resizew=193)
(1)证明:
为
的中点;
(2)若二面角
的平面角的余弦值为
求直线
与平面
所成的角
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0585b6c0f156eecf9662b9846d4eb693.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1cbe8961cca9440ea334ee049d109146.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ccd4fd4b7a4d6b8ca0c5827c055a9ce7.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411b38a18046fea8e9fab1f9f9b80a5f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2a30f3a8b673cc28bd90c50cf1a35281.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f52a58fbaf4fea03567e88a9f0f6e37e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a0ed1ec316bc54c37c4286c208f55667.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/48f3c9abbd78e9a6840ee5f30381daac.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/06222ee533c2484ab25321a6abbf98cb.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/852aabd89edffc1b94344ff3f1f31ccd.png)
![](https://img.xkw.com/dksih/QBM/2011/4/2/1570100114989056/1570100120297472/STEM/5c1fae4f32574751b723e363a25b4fe6.png?resizew=193)
(1)证明:
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a0ed1ec316bc54c37c4286c208f55667.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/48f3c9abbd78e9a6840ee5f30381daac.png)
(2)若二面角
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/11f8759991daa986ef2e729fb6170ccf.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/276dc08e3db48b8f2bb49b858831c6f0.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/21037e170bdbb322558e79c40c00b454.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/80f747eb5b2d21c9de962cbfd4ec4bb7.png)
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