如图,在四棱锥P﹣ABCD中,AB⊥平面PAD,AB∥DC,E为线段PD的中点,已知PA=AB=AD=CD=2,∠PAD=120°.
(1)证明:直线PB∥平面ACE;
(2)求直线PB与平面PCD所成角的正弦值.
![](https://img.xkw.com/dksih/QBM/editorImg/2023/5/26/bfc1a93a-5733-4b67-b6b6-16f00ac9f832.png?resizew=173)
(1)证明:直线PB∥平面ACE;
(2)求直线PB与平面PCD所成角的正弦值.
19-20高三上·浙江·阶段练习 查看更多[14]
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更新时间:2023-05-25 10:11:33
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解答题-证明题
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【推荐1】如图,三棱柱ABC-
的侧棱AA1⊥底面ABC,∠ACB=90°,E是棱
的中点,F是AB的中点,AC=BC=1,
=2.
![](https://img.xkw.com/dksih/QBM/editorImg/2022/12/6/e7d3c2c0-1786-420b-8b8d-d76b3be98492.png?resizew=173)
(1)求证:CF∥平面
;
(2)求三棱锥C-
的高.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/99b16cff607cdc2d69afc70dc778acbb.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9d88bf46ad08f9677c37eed1d0369329.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2777840758e70e7dbbc18cef8f3d6d2b.png)
![](https://img.xkw.com/dksih/QBM/editorImg/2022/12/6/e7d3c2c0-1786-420b-8b8d-d76b3be98492.png?resizew=173)
(1)求证:CF∥平面
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(2)求三棱锥C-
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/69bcb3226e013650b7d8827c31dd41d0.png)
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【推荐2】如图:在直三棱柱
中,
,
是
的中点,
是
的中点
![](https://img.xkw.com/dksih/QBM/2021/6/3/2734935037870080/2803553471266816/STEM/9cba6fe7-a4f7-477b-aa18-73501bdcb0ef.png?resizew=215)
(1)证明:
平面![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7bef5239ddbb0972700ce01daf9ee7cf.png)
(2)求证:
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![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9d88bf46ad08f9677c37eed1d0369329.png)
![](https://img.xkw.com/dksih/QBM/2021/6/3/2734935037870080/2803553471266816/STEM/9cba6fe7-a4f7-477b-aa18-73501bdcb0ef.png?resizew=215)
(1)证明:
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a9abe6e8d1f4f1e8bdc46ddbae0cd789.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7bef5239ddbb0972700ce01daf9ee7cf.png)
(2)求证:
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解题方法
【推荐1】正方体
中.
![](https://img.xkw.com/dksih/QBM/editorImg/2023/1/14/11031758-d27d-4692-acff-e5b787b7952e.png?resizew=183)
(1)已知
,
,
分别为
,
中点.
①若过
的截面与平面
平行,求此截面的面积;
②若
,
分别是
,
上动点,且
,求
长度的最小值;
(2)若正方体各个顶点都在平面
的同侧,且A,
,
,
到平面
的距离分别为1,2,3,5,试求
与平面
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![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6e09725691ee7851f54c0dee86b2bf55.png)
![](https://img.xkw.com/dksih/QBM/editorImg/2023/1/14/11031758-d27d-4692-acff-e5b787b7952e.png?resizew=183)
(1)已知
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/fcd0ced286a0fbc7e4862f8147264277.png)
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![](https://staticzujuan.xkw.com/quesimg/Upload/formula/394c5d2f55221975503be8aa18022480.png)
①若过
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/895dc3dc3a6606ff487a4c4863e18509.png)
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②若
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![](https://staticzujuan.xkw.com/quesimg/Upload/formula/03902478df1a55bc99703210bccab910.png)
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![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c83f1f880e5ffbff036953acaca90c41.png)
(2)若正方体各个顶点都在平面
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e170f206fdbbd834aad7580c727e2cc6.png)
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【推荐2】如图1,E,F,G分别是正方形的三边AB,CD,AD的中点,先沿着虚线段FG将等腰直角三角形FDG裁掉,再将剩下的五边形ABCFG沿着线段EF折起,分别连接AB,CG就得到了如图2所示的几何体.
![](https://img.xkw.com/dksih/QBM/editorImg/2022/11/16/41481d52-9e14-4b1b-849e-65b40ddee963.png?resizew=318)
(1)若O是四边形EBCF对角线的交点,证明:AO//平面GCF;
(2)若二面角
的大小为
,求直线AB与平面GCF所成角的正弦值.
![](https://img.xkw.com/dksih/QBM/editorImg/2022/11/16/41481d52-9e14-4b1b-849e-65b40ddee963.png?resizew=318)
(1)若O是四边形EBCF对角线的交点,证明:AO//平面GCF;
(2)若二面角
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![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9f785147690f83dcee0a0bc6c327e75a.png)
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