名校
1 . 已知正实数x,y满足
,则
的最大值为______ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a7b97fbf27885aa90cc397eb27263cd2.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6f29d5f376c75c41ae6af0c8a8565449.png)
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2023-09-03更新
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984次组卷
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11卷引用:山东省临沂第一中学2023-2024学年高三上学期周末强基训练数学试题
山东省临沂第一中学2023-2024学年高三上学期周末强基训练数学试题全国名校大联考2023-2024学年高三上学期第一联考(月考)数学试题陕西省榆林市府谷县第一中学2023-2024学年高三上学期第一次联考理科数学试题贵州省2024届高三上学期第一次联考(月考)数学试题吉林省通榆县第一中学校2024届高三上学期第二次质量检测数学试题新疆乌鲁木齐市第七十中学2024届高三上学期第一次联考(月考)数学试题四川省2024届高三上学期第一次联考(月考)理科数学试题四川省2024届高三上学期第一次联考(月考)文科数学试题广东省深圳市深圳外国语学校2024届高三上学期元月阶段测试数学试题河北省廊坊市香河县第一中学2023-2024学年高三下学期模拟考试数学试卷(已下线)专题5 指数对数同构问题(过关集训)(压轴题大全)
名校
解题方法
2 .
,不等式
恒成立,求a的最小值是______
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/927f7899fec72d5f9462670751698342.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6137c1e0e178ca3a3567cd1b0381f4b6.png)
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2023-08-13更新
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9卷引用:山东省平邑县第一中学2022-2023学年高二下学期6月月考数学试题
山东省平邑县第一中学2022-2023学年高二下学期6月月考数学试题江苏省常州市高级中学2019-2020学年高三下学期二模适应性训练(二)数学试题浙江省三校(新昌中学、浦江中学、富阳中学)2020-2021学年高三上学期第一次联考数学试题(已下线)专题02同构法在解题中的应用重庆市西南大学附属中学校2022-2023学年高三上学期12月月考数学试题湖北省黄冈市浠水县第一中学2022-2023学年高二下学期期末数学试题(已下线)第六章 导数与不等式恒成立问题 专题六 单变量恒成立之参变分离法 微点3 单变量恒成立之同构或放缩后参变分离江西省赣州市南康中学2024届高三上学期七省联考考前数学猜题卷(八)(已下线)专题11 不等式恒成立、能成立、恰好成立问题【讲】
3 . 已知函数
有两个零点
,则![](https://staticzujuan.xkw.com/quesimg/Upload/formula/450398974b1561ca801e102e16df6789.png)
________
(填大于或小于号),实数
的取值范围是________ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5b526c857bb86d48793b88199a32ecb7.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8ce7ae90d808f05e86ea063238e4b2f9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/450398974b1561ca801e102e16df6789.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3edbd40e04e2a943051fa83d6e511add.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0a6936d370d6a238a608ca56f87198de.png)
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解题方法
4 . 祖暅原理:“幂势既同,则积不容异”.即:夹在两个平行平面之间的两个几何体,被平行于这两个平面的任意平面所截,如果截得的两个截面的面积总相等,那么这两个几何体的体积相等.如图①是一个椭圆球形瓷凳,其轴截面为图②中的实线图形,两段曲线是椭圆
的一部分,若瓷凳底面圆的直径为4,高为6,则![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a27d404afb858505e4894aeae3449699.png)
__________ ;利用祖暅原理可求得该椭圆球形瓷凳的体积为__________
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0454fdaf05c2bcce639c592941b3ca1d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a27d404afb858505e4894aeae3449699.png)
![](https://img.xkw.com/dksih/QBM/2022/5/7/2974418415230976/2977119201443840/STEM/adb2f1b9-cc9f-4a3d-827b-cd82e4d304e0.png?resizew=182)
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5 . 已知椭圆
(
)的离心率为
,长轴
上的
等分点从左到右依次为点
,
,
,
,过
(
,
,
,
)点作斜率为
(
)的直线
(
,
,
,
),依次交椭圆上半部分于点
,
,
,
,
,交椭圆下半部分于点
,
,
,
,
,则
条直线
,
,
,
的斜率乘积为 .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1d7aea48c44781a844b5c19191f70f61.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9374d3462754e846cbb0f7dd5fd28277.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8d5989c84e320b504511f23eeb6e7357.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6d86a0a3e867a448094f74a54a1fee64.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0efba7147f5b9ced8bc4a72f0a9fb8af.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c2e13276547015662b41b5e56bc396a2.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0729b34dbd970b53737364a0b615cd55.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2537b72c74ac9482d538480c7af1fc40.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f8335769d1ac5e50c55742a18af734ec.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7a032ed1b6c1542b6efa4ccf2d297e6f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7c45176df950dfe48b8ca7eac08ee349.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/61128ab996360a038e6e64d82fcba004.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2537b72c74ac9482d538480c7af1fc40.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0e9ba3f640f57c0cece089dfd19b4970.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f0a532e15e232cb4b99a8d4d07c89575.png)
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![](https://staticzujuan.xkw.com/quesimg/Upload/formula/468edcfef1bcd7e74491a57a70c1bcb1.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7c45176df950dfe48b8ca7eac08ee349.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/61128ab996360a038e6e64d82fcba004.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2537b72c74ac9482d538480c7af1fc40.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0e9ba3f640f57c0cece089dfd19b4970.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2e121c542f13bc89d8ea6b89faccafda.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/10f51c38e7efeab76c0a7b026c44fad9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/db5516392bae9e1d889ca62ad5ab9e20.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2537b72c74ac9482d538480c7af1fc40.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/fcb014fc5d3b238ce8d7f5fc3f62e194.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0b90fd793a3e47c5505d3c8be3d82dee.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9ec7054ef46f5ebeec376eb8181931d0.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b7c8a79eec0a734db61cbb598b64b5e1.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2537b72c74ac9482d538480c7af1fc40.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8cfbfe358cc1d39167427fef056f2a63.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b26cfaedb1ad7aee599ae02b4ebe7135.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/37bfcf635b2bab9ddf399bd0e11b6494.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7cbf003f3d822a5609f9506c27aec85f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2537b72c74ac9482d538480c7af1fc40.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f1a462baa5839588a046fc8fb51c5e0f.png)
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