1 . 在
的表格填上数字,设在第i行第j列所组成的数字为
,
,
,则表格中共有5个1的填表方法种数为______ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7954493b61c1d19b8bfe3a0745ad5fa6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b1955eef07ef7c701f3ec2d92bb8f4bb.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7a122dcabf7d5046f0b9c64f3d4aa03b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/387a789ee56851f32982e26b7a84ab74.png)
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2019-11-08更新
|
315次组卷
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2卷引用:上海市大同中学2018-2019学年高三上学期期中数学试题
2014高三·四川·竞赛
2 . 设在
的方格表的第
行第
列所填的数为
,
.则表中共有五个1的填表方法总数为______ (用具体数字作答).
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/954253b16a82489bb0e152543428c68a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2c05b9832b09731a574d4a4adf7448de.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7600d2cfbdc6146db96cc545706004f6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7cea71f85df9370063f74aadff1989f3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/70bd4029c61d2f61aec6aa83cd59d730.png)
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解题方法
3 . 求作一个立方体,使其体积等于已知立方体体积的2倍,这就是历史上有名的立方倍积问题.1837年法国数学家闻脱兹尔证明了立方倍积问题不能只用直尺与圆规作图来完成,不过人们发现,跳出直尺与圆规作图的框框,可以找到不同的作图方法.如图是柏拉图(公元前427—公元前347年)的方法:假设已知立方体的边长为
,作两条互相垂直的直线,相交于点
,在一条直线上截取
,在另一条直线上截取
,在直线
上分别取点
,使
(只要移动两个直角尺,使一个直角尺的边缘通过点
,另一个直角尺的边缘通过点
,并使两直角尺的另一边重合,则两直角尺的直角顶点即为
),则线段
即为所求立方体的一边.以直线
、
分别为
轴、
轴建立直角坐标系,若圆
经过点
,则圆
的方程为______ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0a6936d370d6a238a608ca56f87198de.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1dde8112e8eb968fd042418dd632759e.png)
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![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2a30f3a8b673cc28bd90c50cf1a35281.png)
![](https://img.xkw.com/dksih/QBM/editorImg/2024/1/3/33f88743-ad56-4c33-bf55-10bf779ef839.png?resizew=167)
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4 . 根据毕达哥拉斯定理,以直角三角形的三条边为边长作正方形,从斜边上作出的正方形的面积正好等于在两直角边作出的正方形面积之和.现在对直角三角形
按上述操作作图后,得如下图所示的图形,若
,则![](https://staticzujuan.xkw.com/quesimg/Upload/formula/33b62a6a6167b2832999c152ed5b96ef.png)
______ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/10fc7991ea17d54ff5f4445ac5699463.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/629303e859eb016c778dc23ed47fccdd.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/33b62a6a6167b2832999c152ed5b96ef.png)
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2024高三·全国·专题练习
5 . 舒腾尺是荷兰数学家舒腾设计的一种作图工具,如图,O是滑槽AB的中点,短杆ON可绕O转动,长杆MN通过N处的铰链与ON连接,MN上的栓子D可沿滑槽AB滑动.当点D在滑槽AB内做往复移动时,带动点N绕O转动,点M也随之而运动.若
,
,
,则
的最小值为__________ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/54298f581688081d0b0214334a0dedf2.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/02e47bb98258ebfcf1d8ad4bac10b7ba.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3d2c15801fee2405573677484f5dcfa4.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4bfd37fc64ba7825e03d509be95e93b9.png)
![](https://img.xkw.com/dksih/QBM/editorImg/2024/3/15/68221d84-739d-4854-be98-9605fe511e86.png?resizew=179)
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6 . 某种平面分形图如下图所示,一级分形图是一个边长为1的等边三角形(图(1));二级分形图是将一级分形图的每条线段三等分,并以中间的那一条线段为一底边向形外作等边三角形,然后去掉底边(图(2));将二级分形图的每条线段三等分,重复上述的作图方法,得到三级分形图(图(3));
;重复上述作图方法,依次得到四级、五级、
级分形图.则
级分形图的周长为__________ ;
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/daa5e9bd516f6282483b92cfe6074623.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/eb62e9ac330c5f354bb424050367a117.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b6a24198bd04c29321ae5dc5a28fe421.png)
![](https://img.xkw.com/dksih/QBM/editorImg/2023/3/6/51186c45-c170-46c7-be7c-89b8141bdeaf.png?resizew=370)
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7 . 如图,菱形架ABCD是一种作图工具,由四根长度均为4的直杆用铰链首尾连接而成.已知A,C可在带滑槽的直杆
上滑动;另一根带滑槽的直杆DH长度为4,且一端记为H,另一端用铰链连接在D处,上述两根带滑槽直杆的交点P处有一栓子(可在带滑槽的直杆上滑动).若将H,B固定在桌面上,且两点之间距离为2,转动杆HD,则点P到点B距离的最大值为__________ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0f85fca60a11e1af2bf50138d0e3fe62.png)
![](https://img.xkw.com/dksih/QBM/editorImg/2023/4/29/ae31bd56-b24c-41a4-a0fc-f1ea5087f09d.png?resizew=199)
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8 . 通过研究正五边形和正十边形的作图,古希腊数学家毕达哥拉斯发现了黄金分割率,黄金分割率的值也可以用
表示,即
.记
,则![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6174a44a2648729609c33d4e06670a1e.png)
______ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/fc18437ab173674af015b995620641d6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/21a36b1f44fa8d91da01a901b0364cd3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3c00e8432656b1cc2db534fb5a524a6a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6174a44a2648729609c33d4e06670a1e.png)
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9 . 舒腾尺是荷兰数学家舒腾(1615-1660)设计的一种作图工具,如图,
是滑槽
的中点,短杆
可绕
转动,长杆
通过
处的铰链与
连接,
上的栓子
可沿滑槽
滑动,当点
在滑槽
内作往复移动时,带动点
绕
转动,点
也随之而运动,记点
的运动轨迹为
,点
的运动轨迹为
.若
,
,且
,过
上的点
向
作切线,则切线长的最大值为______
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1dde8112e8eb968fd042418dd632759e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f52a58fbaf4fea03567e88a9f0f6e37e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/88e9f7d1272b7344346b58b660aa260a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1dde8112e8eb968fd042418dd632759e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411461db15ee8086332c531e086c40c7.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/54a5d7d3b6b63fe5c24c3907b7a8eaa3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/88e9f7d1272b7344346b58b660aa260a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411461db15ee8086332c531e086c40c7.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8455657dde27aabe6adb7b188e031c11.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f52a58fbaf4fea03567e88a9f0f6e37e.png)
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![](https://staticzujuan.xkw.com/quesimg/Upload/formula/02e47bb98258ebfcf1d8ad4bac10b7ba.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/919e839fe46b774bfdd7e01206793d39.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/23f3ffe7abc59e2f65d827c8eab8d36a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dad2a36927223bd70f426ba06aea4b45.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b1241216f3c1cb5e73043dd1037f556d.png)
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10 . 舒腾尺是荷兰数学家舒腾设计的一种作图工具,如图,O是滑槽AB的中点,短杆ON可绕O转动,长杆MN通过N处的铰链与ON连接,MN上的栓子D可沿滑槽AB滑动.当点D在滑槽AB内做往复移动时,带动点N绕O转动,点M也随之而运动.记点N的运动轨迹为
,点M的运动轨迹为
.若
,
,过
上的点P向
作切线,则切线长的最大值为______ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b1241216f3c1cb5e73043dd1037f556d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/23f3ffe7abc59e2f65d827c8eab8d36a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/54298f581688081d0b0214334a0dedf2.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/02e47bb98258ebfcf1d8ad4bac10b7ba.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/23f3ffe7abc59e2f65d827c8eab8d36a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b1241216f3c1cb5e73043dd1037f556d.png)
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