名校
1 . 如图,在正四棱柱
中,
,
,点
,
分别为
,
的中点,则二面角
的大小为______ ;三棱锥
的外接球的表面积为______ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6e09725691ee7851f54c0dee86b2bf55.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/fcd0ced286a0fbc7e4862f8147264277.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6db57eca2a7cbd91bc57372592580a76.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2a30f3a8b673cc28bd90c50cf1a35281.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a0ed1ec316bc54c37c4286c208f55667.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f52a58fbaf4fea03567e88a9f0f6e37e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9d78abbad68bbbf12af10cd40ef4c353.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4e7be2f695260a14809dec7d84dfd6fc.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/580be22c91b2343e7933f8b1d925fc52.png)
您最近一年使用:0次
名校
2 . 已知四棱锥的底面
为等腰梯形,
,
,
,
平面
.
(1)求证:
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d4710f75c66f19825a3e44b48f78bbac.png)
(2)若四棱锥
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0585b6c0f156eecf9662b9846d4eb693.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/80f747eb5b2d21c9de962cbfd4ec4bb7.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0b60870baa5e3fbc33a749aa5f0a94be.png)
您最近一年使用:0次
2023-11-12更新
|
1833次组卷
|
6卷引用:四川省眉山市彭山区第一中学2023-2024学年高二上学期12月月考数学试题
3 . 已知正三棱柱
的各条棱长都是2,D,E分别是
的中点,则( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/42d3a82b8e587ee890467835bc4e854c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6a37ee2b1b0e17139fdaf63449cd77dc.png)
A.![]() ![]() |
B.平面![]() ![]() ![]() |
C.直线![]() ![]() ![]() |
D.点![]() ![]() ![]() |
您最近一年使用:0次
4 . 如图,已知
平面
与底面
所成角为
,且
.
平面
;
(2)求二面角
的大小.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5a1b49f64e0065edad868b25e9fcada3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b31a124f5f318ac67b6d6b3c47ebc2ab.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411b38a18046fea8e9fab1f9f9b80a5f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c24095e409b025db711f14be783a406c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/da2de4496cec1d28745ce7a042883d0d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1a0787d2cb66d00c49d3348b52acd407.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8f571a1aac46c6d0cf440c0ec2846bf9.png)
(2)求二面角
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/715cc9ea5e7d80930284ffb117142770.png)
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2024-02-29更新
|
823次组卷
|
8卷引用:湖南省岳阳市平江县第三中学等多校联考2023-2024学年高二普通高中学业水平合格性考试仿真模拟(专家卷二)数学试题
湖南省岳阳市平江县第三中学等多校联考2023-2024学年高二普通高中学业水平合格性考试仿真模拟(专家卷二)数学试题(已下线)专题7.3 空间角与空间中的距离问题【九大题型】(已下线)第07讲 空间直线﹑平面的垂直(二)-《知识解读·题型专练》(已下线)13.2.4 平面与平面的位置关系(2)-【帮课堂】(苏教版2019必修第二册)(已下线)专题07 空间直线﹑平面的垂直(二)-《知识解读·题型专练》(人教A版2019必修第二册)(已下线)专题3.6空间直线、平面的垂直-重难点突破及混淆易错规避(人教A版2019必修第二册)(已下线)重难点专题14 利用传统方法解决二面角问题-【帮课堂】(苏教版2019必修第二册)(已下线)第13章 立体几何初步 章末题型归纳总结 (2)-【帮课堂】(苏教版2019必修第二册)
名校
解题方法
5 . 如图所示,在长方体
中,
和
交于点
,
为棱
的中点.
![](https://img.xkw.com/dksih/QBM/editorImg/2024/2/6/2b83e586-bde1-41eb-b785-6399c124ba90.png?resizew=162)
(1)根据上下文,在“直线
平行于平面
”的证明过程中完成填空;
证明:(1)如图所示,连接
.由
是长方体,得___①___,所以四边形
为平行四边形,从而
是
的中点;再由
是
中点,
是
中平行于
的中位线.于是,__②____,根据直线与平面平行判定定理,得直线
平行于平面
,证明完毕.
①___________________________________________________;
②___________________________________________________.
(2)求二面角
的正切值.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6e09725691ee7851f54c0dee86b2bf55.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1bed5edf85db24ba3e6fa7e2d89f4afd.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/87cdc08e1c4a04a18d5ecea03393e36d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2a30f3a8b673cc28bd90c50cf1a35281.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a0ed1ec316bc54c37c4286c208f55667.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f52a58fbaf4fea03567e88a9f0f6e37e.png)
![](https://img.xkw.com/dksih/QBM/editorImg/2024/2/6/2b83e586-bde1-41eb-b785-6399c124ba90.png?resizew=162)
(1)根据上下文,在“直线
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/49b50357a6545cae8348e3059312f520.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7253ffd3fc633d861810ee2e872188b6.png)
证明:(1)如图所示,连接
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/83c09eec4e14a861af83d7828797d176.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6e09725691ee7851f54c0dee86b2bf55.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8b4cd2b33bd983a9ed6575b9de04a46a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2a30f3a8b673cc28bd90c50cf1a35281.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c597ff77c65c5add6f50294e3eee9536.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a0ed1ec316bc54c37c4286c208f55667.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f52a58fbaf4fea03567e88a9f0f6e37e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/49b50357a6545cae8348e3059312f520.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/bcf8c670b78106a980fc98b6659627d5.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/83c09eec4e14a861af83d7828797d176.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/49b50357a6545cae8348e3059312f520.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7253ffd3fc633d861810ee2e872188b6.png)
①___________________________________________________;
②___________________________________________________.
(2)求二面角
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/38b8df87ef099eae61bb07018f2ab335.png)
您最近一年使用:0次
名校
解题方法
6 . 如图,在三棱柱中,
,
,
为
的中点,平面
平面
.
(1)证明:
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3ebe6a446b91e73b181f9f4d56264dd3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/41104641f3e2260d00aeadf8fb8a078a.png)
(2)若
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/42d8afb6a50406ba4c6621f4976c8dcc.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9f25c5543b39190dc2499aa66f939659.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/642a7dd471434c923f76809dfa5ee183.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/41104641f3e2260d00aeadf8fb8a078a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ab3e0dba5705e1d749cfb21ebbb2ed93.png)
您最近一年使用:0次
2024-01-31更新
|
404次组卷
|
7卷引用:新疆伊犁州华·伊高中联盟2023-2024学年高二上学期期中数学试题
名校
7 . 如图,在四棱锥
中,平面
平面
,
,
.
![](https://img.xkw.com/dksih/QBM/editorImg/2024/1/23/5670825a-cda2-4828-a98a-cf1edb20ce7a.png?resizew=162)
(1)求证:
;
(2)求平面
与平面
夹角的余弦值.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0585b6c0f156eecf9662b9846d4eb693.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e4aa9084b8fe0fe05c4388d1f835587b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411b38a18046fea8e9fab1f9f9b80a5f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4a57cf90275018dea04941fcffc11067.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3181a858d499ed787333475aecf3b894.png)
![](https://img.xkw.com/dksih/QBM/editorImg/2024/1/23/5670825a-cda2-4828-a98a-cf1edb20ce7a.png?resizew=162)
(1)求证:
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/da48240e7fc3248f773ac1500c15ec14.png)
(2)求平面
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/80f747eb5b2d21c9de962cbfd4ec4bb7.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411b38a18046fea8e9fab1f9f9b80a5f.png)
您最近一年使用:0次
名校
8 . 已知平面四边形
,
,
,
,现将
沿
边折起,使得平面
平面
,此时
,点
为线段
的中点.
平面
;
(2)若
为
的中点
①求
与平面
所成角的正弦值;
②求二面角
的平面角的余弦值.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411b38a18046fea8e9fab1f9f9b80a5f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/27db558e8db4c957654c8e5cecd2d2dc.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f945a69cf7e8213e50622125cde652f5.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/bcfac9ab1dc776c9ec076ab2a132fcd2.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/80c505c02c59313fe0108392a5bf5127.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d40b319212a7e7528b053e1c7097e966.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/fcf6dc837ae85207789b94d109c5c2eb.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ca67a5b8f69507c8b80379e86f90a8ce.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/cdb2dd10731b99c0f4f89ee957f8a239.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dad2a36927223bd70f426ba06aea4b45.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/03902478df1a55bc99703210bccab910.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f2b4e753ef119608188c46a50ec597e6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b4eb7e9ad5486cf1c5e506b20c5469e8.png)
(2)若
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ac047e91852b91af639feec23a9598b2.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9d78abbad68bbbf12af10cd40ef4c353.png)
①求
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/438f34bc8b04e8c494b91306ac6fe352.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/aeb5255e2159617505e0c87d01437a57.png)
②求二面角
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f04e376d75882fa61c533dbf33ea6f17.png)
您最近一年使用:0次
7日内更新
|
544次组卷
|
13卷引用:江西省赣州市第四中学2023-2024学年高二上学期开学考试数学试题
江西省赣州市第四中学2023-2024学年高二上学期开学考试数学试题(已下线)第02讲 玩转立体几何中的角度、体积、距离问题-【暑假自学课】2022年新高二数学暑假精品课(苏教版2019选择性必修第一册)(已下线)高一下学期数学期末考试高分押题密卷(三)-《考点·题型·密卷》湖南省长沙市实验中学2022-2023学年高一下学期期末数学试题广东省揭阳市普宁市华侨中学2022-2023学年高一下学期5月月考数学试题江西省丰城中学2023-2024学年高一(创新班)上学期第一次段考(10月)数学试题浙江省湖州中学2021-2022学年高一下学期第二次质量检测数学试题广东省广州市华南师范大学附属中学2021-2022学年高一下学期期末数学试题(已下线)高一升高二开学分班选拔考试卷(测试范围:苏教版2019必修第二册)(已下线)第二章 立体几何中的计算 专题一 空间角 微点8 二面角大小的计算(三)【培优版】专题05 空间直线、平面的垂直-《期末真题分类汇编》(新高考专用)江苏省南京市中华中学2023-2024学年高一下学期5月月考数学试卷(已下线)高一数学下学期期末押题试卷01-期末真题分类汇编(新高考专用)
解题方法
9 . 如图,在三棱锥
中,
,
,
,平面
平面
,则三棱锥
的体积的最大值为_______ ;二面角
的正弦值的最小值为________ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/63397cda22cb1fad59cf966dfb588643.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/83640592853a53872d7af69c0cffc1bb.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/63e4d19bf237a6fca67e0d01a9ddb726.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/526908dfb46cf151b8ab1492a9d52047.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e4aa9084b8fe0fe05c4388d1f835587b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7bef5239ddbb0972700ce01daf9ee7cf.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/63397cda22cb1fad59cf966dfb588643.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/bf29d07c3751c41ab3503065a5a5052e.png)
您最近一年使用:0次
10 . 正多面体也称柏拉图立体,被喻为最有规律的立体结构,其所有面都只由一种正多边形构成的多面体(各面都是全等的正多边形,且每一个顶点所接的面数都一样,各相邻面所成二面角都相等).数学家已经证明世届上只存在五种柏拉图立体,即正四面体、正六面体、正八面体、正十二面体、正二十面体.已知一个正四面体
和一个正八面体
的棱长都是
(如图),把它们拼接起来,使它们一个表面重合,得到一个新多面体
![](https://img.xkw.com/dksih/QBM/editorImg/2024/1/10/5c007745-309d-4bb0-b19e-c0c47a3828ef.png?resizew=258)
(1)求新多面体的体积;
(2)求二面角
的余弦值.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6cb6c9306a25f041d7801274838b43dd.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c87bc797aad25e4ccdc9d722a87b642c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0a6936d370d6a238a608ca56f87198de.png)
![](https://img.xkw.com/dksih/QBM/editorImg/2024/1/10/5c007745-309d-4bb0-b19e-c0c47a3828ef.png?resizew=258)
(1)求新多面体的体积;
(2)求二面角
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e4b820c84570da9c38d0a81c22788b76.png)
您最近一年使用:0次