A | B | C | D | E | F | G | H | |
购买春节档电影票的人数 | 40 | 30 | 30 | 30 | 30 | 20 | 10 | 10 |
曾经购买过电影票的人数 | 92 | 88 | 80 | 80 | 70 | 62 | 25 | 15 |
(2)现从样本中在A,D,E平台上购买春节档电影票的消费者中按照分层抽样的方法抽取n个人,已知抽取的在A平台上购买春节档电影票的人数比在D平台与E平台上购买春节档电影票的人数之和少2.
①求n的值;
②从抽取的n个人中再随机抽取4人,记这4人中在E平台上购买春节档电影票的人数为X,求X的分布列及数学期望.
(1)若从新旧两台设备生产的产品中分别随机抽取100箱作为样本,其中新设备生产的100箱样本中有10箱存在不合格品,旧设备生产的100箱样本中有25箱存在不合格品,由样本数据,填写完成
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7b72fcdc709e77910cd36a26369648b3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8bdaf501302beeec9d077be02909e3bd.png)
单位:箱
是否有不合格品 设备 | 无不合格品 | 有不合格品 | 合计 |
新 | |||
旧 | |||
合计 |
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/29c8578f06897aa6fb84aa95c797d3d8.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ed1f109f79547d6ae0d94339e689e8f7.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ed1f109f79547d6ae0d94339e689e8f7.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b1010846eeec6c9da29640f5aa3f8738.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3606c4a853a6a34cb7f33bea81b15a1f.png)
(3)现对一箱产品检验了20个,结果恰有3个不合格品,以(2)中确定的
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3606c4a853a6a34cb7f33bea81b15a1f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b1010846eeec6c9da29640f5aa3f8738.png)
附表:
0.100 | 0.05 | 0.01 | 0.005 | 0.001 | |
2.706 | 3.841 | 6.635 | 7.879 | 10.828 |
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e7dc70b5e1ba847b9918a50f67bfbe8f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/356b05e46b10ee51c3e43546d73ec96c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/940ebdc0cc7801866b21d9b6e76cd088.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/436c623f611c2a5f0aae9aec71fb8be1.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5d6ad4513e557197d9d5b27860f4348e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/29c8578f06897aa6fb84aa95c797d3d8.png)
(1)求每个AI芯片智能检测不达标的概率;
(2)人工检测抽检50个AI芯片,记恰有1个不达标的概率为
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ed1f109f79547d6ae0d94339e689e8f7.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/098e663b79254b0a2e0e00f92bd14b8d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ed1f109f79547d6ae0d94339e689e8f7.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3606c4a853a6a34cb7f33bea81b15a1f.png)
(3)若AI芯片的合格率不超过93%,则需对生产工序进行改良.以(2)中确定的
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3606c4a853a6a34cb7f33bea81b15a1f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f89eef3148f2d4d09379767b4af69132.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f89eef3148f2d4d09379767b4af69132.png)
(1)若两人各抛掷3次,求抛掷结果中甲正面朝上次数大于乙正面朝上次数的概率;
(2)若甲抛掷
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/aceb113626093e0e431f30fa45c2c444.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/cea4ac187cbb465180e89f38250b3970.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/44fed1be8b7e50f18cb90077d9fce8e4.png)
(1)记某位员工被淘汰的概率为
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/060d9334136396f95e9dcd328486f9d2.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/63fef5f357f94e1e162cc47a99f9ab1e.png)
(2)每位员工不需要重新测试的费用为120元,需要重新测试的总费用为200元,除测试费用外,其他费用总计为1万元,且该300名员工全部参与测试,预算为6万元,问上述方案是否会超过预算?请说明理由.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f51efd0ca4b6c3d42afdc6b8feb330a1.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3b1065ae0947705c7d16a5a86c78f07e.png)
(1)求该顾客参与活动后恰好返还240元的概率;
(2)设该顾客参与活动后,最终支付商场的金额为Y,求Y的分布列与数学期望.(四舍五入取整数)
7 . 为了检测某种抗病毒疫苗的免疫效果,需要进行动物与人体试验.研究人员将疫苗注射到200只小白鼠体内,一段时间后测量小白鼠的某项指标值,按分组,绘制频率分布直方图如图所示,实验发现小白鼠体内产生抗体的共有160只,其中该项指标值不小于60的有110只,假设小白鼠注射疫苗后是否产生抗体相互独立.
抗体 | 指标值 | 合计 | |
小于60 | 不小于60 | ||
有抗体 | |||
没有抗体 | |||
合计 |
(1)填写下面的2×2列联表,并根据列联表及
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/056d56593dc76b14c0b64851e7f34827.png)
(2)为检验疫苗二次接种的免疫抗体性,对第一次注射疫苗后没有产生抗体的40只小白鼠进行第二次注射疫苗,结果又有20只小自鼠产生抗体.
(i)用频率估计概率,求一只小白鼠注射2次疫苗后产生抗体的概率p;
(ii)以(i)中确定的概率p作为人体注射2次疫苗后产生抗体的概率,进行人体接种试验,记n个人注射2次疫苗后产生抗体的数量为随机变量X.试验后统计数据显示,当X =99时,P(X)取最大值,求参加人体接种试验的人数n.
参考公式:(其中
为样本容量)
0.50 | 0.40 | 0.25 | 0.15 | 0.100 | 0.050 | 0.025 | |
0.455 | 0.708 | 1.323 | 2.072 | 2.706 | 3.841 | 5.024 |
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/bf31876698721a199c7c53c6b320aa86.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b1010846eeec6c9da29640f5aa3f8738.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f16d09692f7b0fb5633964437202d21d.png)
(1)求
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b1010846eeec6c9da29640f5aa3f8738.png)
(2)求甲、乙两人在三轮竞答活动中答对4题的概率.
假设携带病毒(阳性)的人在人群中的占比为
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/29c8578f06897aa6fb84aa95c797d3d8.png)
(1)现有10份单人单检的样本,其中有2份为阳性.求恰好经过3次检测就排查出所有阳性样本的概率.
(2)请结合离散型随机变量及其分布列的有关知识,计算当
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b1010846eeec6c9da29640f5aa3f8738.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6a780541831554f2ef82fc0e626ae3d1.png)
第一步,拿出n个外观相同,但酸碱值不同的药品B用试剂A检测,要求其按酸碱值大小为它们排序;
第二步,过一段时间,再用试剂A检测这n个药品B,并重新按酸碱值大小为它们排序,这称为一轮测试.
根据一轮测试中的两次排序的偏离程度的高低检验试剂A的检测效果的稳定性.
现设
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/fac3649308b528fd56545ba102dc42d5.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dec99c57bf7997bd93e1ed8f48d5af9a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4e335bf8a1f1146c6905f8f121a2523a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dec99c57bf7997bd93e1ed8f48d5af9a.png)
(1)写出
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f022950e0faa45b617d497b01b5292b9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f022950e0faa45b617d497b01b5292b9.png)
(2)若试剂A在连续进行的三轮测试中,都有
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2e2b48a0d42c87341f7f5755a9ef955a.png)