已知函数f(x)=ln
+ax﹣1(a≠0).
(I)求函数f(x)的单调区间;
(Ⅱ)已知g(x)+xf(x)=﹣x,若函数g(x)有两个极值点x1,x2(x1<x2),求证:g(x1)<0.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/cf35027e76f8ea593f82023973d4aba3.png)
(I)求函数f(x)的单调区间;
(Ⅱ)已知g(x)+xf(x)=﹣x,若函数g(x)有两个极值点x1,x2(x1<x2),求证:g(x1)<0.
更新时间:2017-09-02 15:59:47
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