名校
解题方法
1 . 如图,点C是以AB为直径的圆O上异于A,B的点,平面
平面ABC,△PAC是边长为2的正三角形.
平面PAC;
(2)若点E,F分别是PC,PB的中点,且异面直线AF与BC所成角的正切值为
,记平面AEF与平面ABC的交线为直线l,点Q为直线l上动点,求直线PQ与平面AEF所成角的取值范围.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6d077f6da8b2c00b152d4679aa2ed7f7.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e2ffc6952e988d04f22f0fb2f7f0ab7b.png)
(2)若点E,F分别是PC,PB的中点,且异面直线AF与BC所成角的正切值为
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/860884c0017c8bceb5b0edff796c144f.png)
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2024-05-09更新
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2卷引用:江苏省盐城中学、南京二十九中联考2023-2024学年高二下学期4月期中数学试题
名校
2 . 如图,在四棱锥
中,四边形
是正方形,
,M为侧棱PD上的点,
平面
.
.
(2)若
,求二面角
的大小.
(3)在(2)的前提下,在侧棱PC上是否存在一点N,使得
平面
?若存在,求出
的值;若不存在,请说明理由.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0585b6c0f156eecf9662b9846d4eb693.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411b38a18046fea8e9fab1f9f9b80a5f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/267172a953126e44e36ab085165543ef.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5a1b49f64e0065edad868b25e9fcada3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/fb304d905125170bebfada27e7ed8960.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ccbd1316b9d1f0c1e71fd078deec61f6.png)
(2)若
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/32d0710321d97361e5782124bbf7f0c9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6f2d2fbc26a7be008f550b5828f615fe.png)
(3)在(2)的前提下,在侧棱PC上是否存在一点N,使得
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f214481e6b23307a37940f6dd0313d30.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/fb304d905125170bebfada27e7ed8960.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/23d7478de8e7971491d38e784529aff5.png)
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2024-05-08更新
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4卷引用:福建省莆田市2024届高三第四次教学质量检测(三模)数学试题
名校
3 . 如图,在三棱锥
中,平面
平
.
.
(2)若
为
的中点,求直线
与平面
所成角的正弦值.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/891579e7c231584a8e16b8eeff79888e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/fcf6dc837ae85207789b94d109c5c2eb.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/88685c5cd2d13a8d51c80e98012b32ac.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/cfc1f76257275ab4b04f9bc913535670.png)
(2)若
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/67c8a9af7f6fd91de42d30da0b327524.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9d78abbad68bbbf12af10cd40ef4c353.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/68a83fdd2ba72a2dba0b6b10bb3e06b9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7bef5239ddbb0972700ce01daf9ee7cf.png)
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2024-05-08更新
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3卷引用:甘肃省白银市2023-2024学年高二下学期5月期中考试数学试题
名校
解题方法
4 . 如图,已知在正三棱柱
中,
,且点
分别为棱
的中点.
作三棱柱截面交
于点
,求线段
长度;
(2)求平面
与平面
的夹角的余弦值.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/42d3a82b8e587ee890467835bc4e854c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4339a40ae9d1947ec3a4b3e2fa3a16cd.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ad056c25c0fdcbcc765eb5cbc6093f2b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2ef4495309b23e5218be6f611d04c38e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1f8e45b50c77bf6a2cde628ea3455ac9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ab35850dbc661ded6456b70767cc6cd0.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dad2a36927223bd70f426ba06aea4b45.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6655c413f509068d30b165f9d92bdba0.png)
(2)求平面
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b03428a8f91a5674cb8f54766c165f7e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e168672b47d7e64dc1b404f8882c7dcf.png)
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2卷引用:湖南省长沙市雅礼中学2024届高三下学期5月模拟(一)数学试卷
名校
5 . 如图,有一个正方形为底面的正四棱锥
,各条边长都是1;另有一个正三角形为底面的正三棱锥
,各条边长也都是1.
中,求
与平面
所成角的正弦值,并求二面角
的平面角的正弦值;
(2)现把它俩其中的两个三角形表面用胶水黏合起来,如黏合面
和面
.试问:由此而得的组合体有几个面?请说明理由.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0585b6c0f156eecf9662b9846d4eb693.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/fedaa3f2f2dfa9e03f5c9d12400415c9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0585b6c0f156eecf9662b9846d4eb693.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/60ef95894ceebaf236170e8832dcf7e3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e7b7c83470489253394bd288d7c920df.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b33b7213d99a817bff19bcf740a0697c.png)
(2)现把它俩其中的两个三角形表面用胶水黏合起来,如黏合面
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e7b7c83470489253394bd288d7c920df.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d1657f0781f2d325a939ebc926e4f4f6.png)
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2卷引用:重庆市巴蜀中学校2024届高三下学期高考适应性月考(九)(4月)数学试题
名校
6 . 如图,在四棱锥
中,
平面
,
,
,
是等边三角形,
为
的中点.
;
(2)若
,求平面
与平面
夹角的正弦值.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0585b6c0f156eecf9662b9846d4eb693.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/97f30533da2e1d2a958dc906c37eba9d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8e106f4233be16e98f2c1bf9f1635622.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8a11029ca6b4b9e7f777af0280cf163c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a301baf6cc0628366e6661a87a2d93ed.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3da7bcea5a45eeae211f5851f12a7517.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2a30f3a8b673cc28bd90c50cf1a35281.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9fd17a66a2af938c89e46f22e4d893b1.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f4486d52b6e410fd7b60428121d96cef.png)
(2)若
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/945afcea28b58fe22976f29246f36ed8.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e7b7c83470489253394bd288d7c920df.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c09afc70f448545336304333d5b5658b.png)
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2024-04-29更新
|
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2卷引用:河南省2023-2024学年高二下学期期中联考数学试题
名校
7 . 如图,在四棱锥
中,四边形ABCD 为直角梯形,AB∥CD,
,平面
平面ABCD,F为线段BC的中点,E为线段PF上一点.
;
(2)当EF为何值时,直线BE 与平面PAD夹角的正弦值为
.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0585b6c0f156eecf9662b9846d4eb693.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3a98aa64f0a6bf23dcfa81367b0ab852.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a1a71f5d1c37a808f3ead6964afa960d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c0b9fe5f2f1c2841912d24e4ef9cfbca.png)
(2)当EF为何值时,直线BE 与平面PAD夹角的正弦值为
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/059d02ae074c7c2f7dfde8058dfa55ab.png)
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3卷引用:山东省济南市名校考试联盟2024届高三下学期4月高考模拟数学试题
8 . 如图,在三棱锥
中,
的中点分别为
.
的长;
(2)证明:平面
平面
;
(3)求平面
和平面
夹角的余弦值.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/63397cda22cb1fad59cf966dfb588643.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/607d2e6bf6337d559bcd3d45f1f45afb.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/630201207817c1b492c50332eabebaa7.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/60ef95894ceebaf236170e8832dcf7e3.png)
(2)证明:平面
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a3d7090639341730951c1bc3c9b6164e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e7b7c83470489253394bd288d7c920df.png)
(3)求平面
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/06bf006d9cf9568dd567c25fd20a0c85.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/87c0bfeadcf17b2a45896071f07a4a5a.png)
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2卷引用:内蒙古自治区呼和浩特市第二中学2023-2024学年高二下学期4月月考数学试题
名校
解题方法
9 . 如图,在三棱柱
中,平面
平面
,
.
为
中点,证明:
平面
;
(2)求平面
与平面
夹角的余弦值.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/42d3a82b8e587ee890467835bc4e854c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0671b4776e142e17a79af5b3f0378ef7.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d16867cc0fe4d229ff757b6bc44dcac7.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4cf1cc9995c3846117daa8cf10aadf22.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8455657dde27aabe6adb7b188e031c11.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/60ef95894ceebaf236170e8832dcf7e3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e56fdf217165748fafe938b64fa08179.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8f4525d2a5cfdd4c82f62c28177d6cf9.png)
(2)求平面
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/447ead7907c10dad61dd486b66831d87.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2d9a8181f7a7fe7f3fac872ce9534f15.png)
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4卷引用:福建省福州市2024届高三第三次质量检测数学试题
名校
10 . 如图,在三棱柱
中,
,
,四边形
是菱形.
;
(2)若
,求二面角
的正弦值.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/42d3a82b8e587ee890467835bc4e854c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b09257183a9578be6adf9ad4310e4000.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/080db3af81b29ed10144a1c2e2a4fb8a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e168672b47d7e64dc1b404f8882c7dcf.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1b65798afbc7efaed6d65d0719c3c391.png)
(2)若
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1e0af487efe25c906740c70b6616e4fb.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6dfb64c679bf4a62e5ee092d8885fc09.png)
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2024-04-13更新
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6卷引用:2024年普通高等学校招生圆梦杯统一模拟考试(四)数学试题及答案