解题方法
1 . 球面几何在研究球体定位等问题有重要的基础作用.球面上的线是弯曲的,不存在直线,连接球面上任意两点有无数条曲线,它们长短不一,其中这两点在球面上的最短路径的长度称为两点间的球面距离.
纬线,赤道以北叫做北纬.如图1,将地球看作球体,假设地球半径为
,球心为
,北纬
的纬线所形成的圆设为圆
,且
是圆
的直径,球面被经过球心
和点
,
的平面截得的圆设为圆
,求圆
中劣弧
的长度,并判断其是否是
,
两点间的球面距离(只需判断、无需证明).
(2)如图2,点
,
在球心为
的球面上,且
不是球的直径,试问
,
两点间的球面距离所在的圆弧
是否与球心
共面?若是,写出证明过程,并求出当
,
时,
,
两点间球面距离所在的圆弧
与球心
所形成的扇形
的面积;若不是,请说明理由.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/235d495d88b8e51f89e2e4da27328025.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4aa0df7f1e45f9de29e802c7f19a4f64.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1dde8112e8eb968fd042418dd632759e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f6b86c22b670a8e9f3896f9e8883fbbb.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/12fe32dfbd66709875c5b9f79c9496da.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7bb0628cecbfc98d390e5447d52414e8.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/12fe32dfbd66709875c5b9f79c9496da.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1dde8112e8eb968fd042418dd632759e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e7c314398e26ffc7164b82946eeb4273.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3953cec61ac602ce5eb59b7912352179.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1dde8112e8eb968fd042418dd632759e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1dde8112e8eb968fd042418dd632759e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/240d929040e21e7991481149b73a79a1.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e7c314398e26ffc7164b82946eeb4273.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3953cec61ac602ce5eb59b7912352179.png)
(2)如图2,点
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5963abe8f421bd99a2aaa94831a951e9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7f9e8449aad35c5d840a3395ea86df6d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/23f919bd3dde10dbbc076f7ec5149699.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f52a58fbaf4fea03567e88a9f0f6e37e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5963abe8f421bd99a2aaa94831a951e9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7f9e8449aad35c5d840a3395ea86df6d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/16d65cecaf8a3dc2953f4109c75a981e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/23f919bd3dde10dbbc076f7ec5149699.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c93ef48e154646ef0564de14a990c2e5.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c467c10aa2eabce3af68c1213d88043b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5963abe8f421bd99a2aaa94831a951e9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7f9e8449aad35c5d840a3395ea86df6d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/16d65cecaf8a3dc2953f4109c75a981e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/23f919bd3dde10dbbc076f7ec5149699.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6c880639a6164aa127cf38b63aebde50.png)
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名校
解题方法
2 . 青岛胶东国际机场的显著特点之一是弯曲曲线的运用,衡量曲线弯曲程度的重要指标是曲率.考察图所示的光滑曲线
上的曲线段
,其弧长为
,当动点从A沿曲线段
运动到B点时,A点的切线
也随着转动到B点的切线
,记这两条切线之间的夹角为
(它等于
的倾斜角与
的倾斜角之差).显然,当弧长固定时,夹角越大,曲线的弯曲程度就越大;当夹角固定时,弧长越小则弯曲程度越大,因此可以定义
为曲线段
的平均曲率;显然当B越接近A,即
越小,K就越能精确刻画曲线C在点A处的弯曲程度,因此定义曲线
在点
处的曲率计算公式为
,其中
.
的圆弧的平均曲率;
(2)已知函数
,求曲线
的曲率的最大值;
(3)已知函数
,若
曲率为0时x的最小值分别为
,求证:
.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5eefffa1689b5a68786b9a5875f12c0e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/16d65cecaf8a3dc2953f4109c75a981e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/505d83f4d34a8cd385577a6ce93a4b11.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/16d65cecaf8a3dc2953f4109c75a981e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/aea61ddc41f927684c6dfaacdd7f8e0a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0636a11a086df66133bd50e43481a546.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/427eceadd7bb569ff140ea73d650db1e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0636a11a086df66133bd50e43481a546.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/aea61ddc41f927684c6dfaacdd7f8e0a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6bb01270362284437d082c3a2268c6b6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/16d65cecaf8a3dc2953f4109c75a981e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/505d83f4d34a8cd385577a6ce93a4b11.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/51c530f4b7491b95acb8ce3eef9aa09d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/07fa72fc4959804b944bfaa93dbe2b21.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/04a9d0e16638396fea6bb3612a96f447.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0a8f385c811ed59d13e7df7f79c39d74.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2d5bca00fa20e6e80480b9d06d2e52ee.png)
(2)已知函数
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d7bce420cf236e5f429afee284239010.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/51c530f4b7491b95acb8ce3eef9aa09d.png)
(3)已知函数
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e86f9b172e8232ee105d0436dab312b3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0c7921ee6a8981f1f4980cdcb0f921bb.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8ce7ae90d808f05e86ea063238e4b2f9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9f3966bd8e4857ccb70afc0fdbab8e87.png)
您最近一年使用:0次
2024-04-15更新
|
471次组卷
|
3卷引用:广东省江门市第一中学2023-2024学年高二下学期第一次段考数学试题
名校
解题方法
3 . 如图是一种升降装置结构图,支柱
垂直水平地面,半径为1的圆形轨道固定在支柱
上,轨道最低点
,
,
.液压杆
、
,牵引杆
、
,水平横杆
均可根据长度自由伸缩,且牵引杆
、
分别与液压杆
、
垂直.当液压杆
、
同步伸缩时,铰点
在圆形轨道上滑动,铰点
在支柱
上滑动,水平横杆
作升降运动(铰点指机械设备中铰链或者装置臂的连接位置,通常用一根销轴将相邻零件连接起来,使零件之间可围绕铰点转动).
的长为
,求水平横杆
的长和
离水平地面的高度
(用
表示);
(2)在升降过程中,求铰点
距离的最大值.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0101a7b5c8a4aed0de2af363792e39a1.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0101a7b5c8a4aed0de2af363792e39a1.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8455657dde27aabe6adb7b188e031c11.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d9f9651b17b98d75a87a7e502202d32e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4a987d8689e9a5556f98c37ea485afeb.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ae7a3e520a16d4fdd73c4e6a4ce7be0e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d62e8aadaadebf1454fde21a390ebdea.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/14b49022a6f55817b5d7e3ab443b5491.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/971b23e3ee827018557d6c88edd5369a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b79dd200766db27fb90d6bd1992cf658.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/14b49022a6f55817b5d7e3ab443b5491.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/971b23e3ee827018557d6c88edd5369a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ae7a3e520a16d4fdd73c4e6a4ce7be0e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d62e8aadaadebf1454fde21a390ebdea.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ae7a3e520a16d4fdd73c4e6a4ce7be0e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d62e8aadaadebf1454fde21a390ebdea.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/32f268424db595e480bbd58f1b7a2e1f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/09af0df7030bbefc8711456da8d87b38.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0101a7b5c8a4aed0de2af363792e39a1.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b79dd200766db27fb90d6bd1992cf658.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/107fd7b3176ecb59eba848fe8d87d114.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/81dea63b8ce3e51adf66cf7b9982a248.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b79dd200766db27fb90d6bd1992cf658.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b79dd200766db27fb90d6bd1992cf658.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/598c4ff9fc8518fa4829e39254d3f6e5.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/81dea63b8ce3e51adf66cf7b9982a248.png)
(2)在升降过程中,求铰点
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/09af0df7030bbefc8711456da8d87b38.png)
您最近一年使用:0次
2024-01-29更新
|
443次组卷
|
3卷引用:浙江省台州市2023-2024学年高一上学期1月期末数学试题
浙江省台州市2023-2024学年高一上学期1月期末数学试题湖北省襄阳市第四中学2023-2024学年高一下学期质量检测(一)数学试题(已下线)专题02三角函数的图像与性质期末10种常考题型归类-《期末真题分类汇编》(人教B版2019必修第三册)
名校
解题方法
4 . 已知直角梯形
,
,
,
,扇形圆心角
,
,如图,将
,
以及扇形
的面积分别记为![](https://staticzujuan.xkw.com/quesimg/Upload/formula/36477401af8ec19b82d682ab184753a2.png)
的表达式,并指出其大小关系(不需证明);
(2)用
表示梯形
的面积
;并证明:
;
(3)设
,
,试用代数计算比较
与
的大小.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411b38a18046fea8e9fab1f9f9b80a5f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f571396be1aa4a8914a66f7d7abd6381.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/36572a10fcb483a9abb63a5039e09ec3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ced06b71073e1bb777f326f06016ce17.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/201339005285d682fbc2cf65fbabddd1.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4138f6987cd2ee9e56b2ac80e84f9e24.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d7ac5396c5ea442e0364b50c1db3d2da.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15c0dbe3c080c4c4636c64803e5c1f76.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/23ba3f676fda6a2aaaa55c9f32874a51.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/36477401af8ec19b82d682ab184753a2.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/36477401af8ec19b82d682ab184753a2.png)
(2)用
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1fec41d46ca97d3e900ef1db5a1f002c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411b38a18046fea8e9fab1f9f9b80a5f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e6cc4a85bbf152031dc8ebd182e44ead.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/be31dfad4f16cf1f2158b3011e3b68b9.png)
(3)设
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/22e8d7d33749979b7d7acc17532d86b2.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c7787a01998f68ccc931c00ccb475f6c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3c1ba6b6ee00c4b2763cb3fa59caa69f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f3bf4af3d4543cada4b52871ac9dfb1a.png)
您最近一年使用:0次
2023-07-09更新
|
607次组卷
|
6卷引用:上海市复旦大学附属中学2022-2023学年高一下学期期末数学试题
上海市复旦大学附属中学2022-2023学年高一下学期期末数学试题(已下线)高一上学期期末考试解答题压轴题50题专练-举一反三系列(已下线)6.2 常用三角公式-高一数学同步精品课堂(沪教版2020必修第二册)上海市华东师范大学第二附属中学2023-2024学年高一下学期3月月考试题(已下线)专题06 期末解答压轴题-《期末真题分类汇编》(上海专用)(已下线)专题04 三角-《期末真题分类汇编》(上海专用)
名校
5 . 宜昌一中江南新校区拟建一个扇环形状的花坛(如图所示),按设计要求扇环的周长为30米,其中大圆弧所在圆的半径为10米,设小圆弧所在圆的半径为
米,圆心角
(弧度).
![](https://img.xkw.com/dksih/QBM/2017/3/23/1650174128562176/1650788506591232/STEM/f5f59454d9a94421b90ea685e6914cb9.png?resizew=157)
(1)求
关于
的函数关系式;
(2)已知对花坛的边缘(实线部分)进行装饰时,直线部分的装饰费用为4元/米,弧线部分的装饰费用为9元/米,设花坛的面积与装饰总费用之比为
,求
关于
的函数关系式,并求出
的最大值.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/81dea63b8ce3e51adf66cf7b9982a248.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c24095e409b025db711f14be783a406c.png)
![](https://img.xkw.com/dksih/QBM/2017/3/23/1650174128562176/1650788506591232/STEM/f5f59454d9a94421b90ea685e6914cb9.png?resizew=157)
(1)求
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c24095e409b025db711f14be783a406c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/81dea63b8ce3e51adf66cf7b9982a248.png)
(2)已知对花坛的边缘(实线部分)进行装饰时,直线部分的装饰费用为4元/米,弧线部分的装饰费用为9元/米,设花坛的面积与装饰总费用之比为
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d053b14c8588eee2acbbe44fc37a6886.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d053b14c8588eee2acbbe44fc37a6886.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/81dea63b8ce3e51adf66cf7b9982a248.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d053b14c8588eee2acbbe44fc37a6886.png)
您最近一年使用:0次
2017-03-24更新
|
2763次组卷
|
5卷引用:2016-2017学年湖北省宜昌市第一中学高一3月月考数学试卷
解题方法
6 . 如图,有一景区的平面图是一半圆形,其中AB长为2km,C、D两点在半圆弧上,满足BC=CD.设
.
![](https://img.xkw.com/dksih/QBM/2015/7/9/1572176667361280/1572176673267712/STEM/3ee9303aba6d43d8809b399f94aabb20.png?resizew=174)
(1)现要在景区内铺设一条观光道路,由线段AB、BC、CD和DA组成,则当θ为何值时,观光道路的总长
最长,并求
的最大值.
(2)若要在景区内种植鲜花,其中在
和
内种满鲜花,
在扇形
内种一半面积的鲜花,则当θ为何值时,鲜花种植面积S最大.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/813b1b0327154103afd7a728f00cfeda.png)
![](https://img.xkw.com/dksih/QBM/2015/7/9/1572176667361280/1572176673267712/STEM/3ee9303aba6d43d8809b399f94aabb20.png?resizew=174)
(1)现要在景区内铺设一条观光道路,由线段AB、BC、CD和DA组成,则当θ为何值时,观光道路的总长
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0f85fca60a11e1af2bf50138d0e3fe62.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0f85fca60a11e1af2bf50138d0e3fe62.png)
(2)若要在景区内种植鲜花,其中在
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/372629a8666de1e9bac3e7daadcac7b6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3a7ffcd1925a2b1259221c6a476152f7.png)
在扇形
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6bf126cfed85fa9b7720ec6f7b0008dc.png)
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