首页>知识点选题>等差数列通项公式的基本量计算
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已知eqId2c1230a9ef5a4968be599681d676dd2b为等差数列,其公差为2,且eqIdde5836d9a77e4e648c784e42488f7df8eqId5cae532f2168495188622189ec8df62ceqId439c99efb33245439aa0fa374eb91983的等比中项,eqIddb5481de79c946c0a760143297d5eadeeqId2c1230a9ef5a4968be599681d676dd2beqIdf458db68122849abb588feb2e682d9ac项和,则eqIdbc24c6e646ef45d78124b2ff20ca875b的值为_____.
难度: 0.85 | 2020·江西高一期末
已知eqId93e38ecd74a24cb59da79181b95bfd3a是等差数列,其前n项和为eqIddb5481de79c946c0a760143297d5eade,且满足eqId5ee5d76b0541454081cbea39be9eb2cbeqId032284ef281340a78dbf643944ff8cd4
(Ⅰ)求数列eqId93e38ecd74a24cb59da79181b95bfd3a的通项公式;
(Ⅱ)设eqId4917b8abebab47dda47d4ed401509e03,求数列eqIdeeb4ca98872f4e6d91cea28f43fc0b63的前n项和为eqId92ed363a54bd4a8a93df9463bb3af1f5
难度: 0.65 | 2020·江西高一期末
已知数列eqId93e38ecd74a24cb59da79181b95bfd3a为等差数列,且eqId0e801a963e1f48d288aa18976f32a650eqIda33e3e13a16f48909e94003cc56e8a9d,数列eqIdeeb4ca98872f4e6d91cea28f43fc0b63的前n项和为eqIde3cfd15b316244ca80bbc5c191d56b3b
(Ⅰ)求数列eqId93e38ecd74a24cb59da79181b95bfd3aeqIdeeb4ca98872f4e6d91cea28f43fc0b63的通项公式;
(Ⅱ)现剔除数列eqId93e38ecd74a24cb59da79181b95bfd3a中与数列eqIdeeb4ca98872f4e6d91cea28f43fc0b63相同项,按照原顺序组成一个新的数列eqId74ef5fe5183946caaee41d8974816a20,其前n项和为eqId92ed363a54bd4a8a93df9463bb3af1f5,求eqIdba87d57b2e064b7f83aca2edead32c34
难度: 0.85 | 2020·江西高一期末
已知数列eqId93e38ecd74a24cb59da79181b95bfd3a为等差数列,eqIdc60df934817a48528e3bd750cf12052aeqIdeeb38fc086bf40c2aa4dbbd3126a92d4,则eqId82d7151c6dfc4c53badcd863a4615593(   )
A.39B.38C.35D.33
难度: 0.65 | 2020·山东高三其他
在等差数列eqId93e38ecd74a24cb59da79181b95bfd3a中,已知eqId92a61d5857584ad299174b9794f08102eqId22be89bf5d6b4b90830d35a6ca09265b .
(1)求数列eqId93e38ecd74a24cb59da79181b95bfd3a的通项公式eqIdef9cef8e6d054d8dac46b8cde14953ad
(2)若________,求数列eqIdeeb4ca98872f4e6d91cea28f43fc0b63的前eqIdf458db68122849abb588feb2e682d9ac项和eqIddb5481de79c946c0a760143297d5eade
在①eqIdeed392ea3909433c8858e5e2b0b6f4bf,②eqId5c2dd6e5e037444189e681d9f8ff9005,③eqIdb703c8cbe757437aa500b459236077f9这三个条件中任选一个补充在第(2)问中,并
对其求解.
注:如果选择多个条件分别解答,按第一个解答计分.
更新:2020/08/11 |题型:解答题 |组卷:52|引用[1]