2024·全国·模拟预测
解题方法
1 . 在四棱锥
中,已知底面
为正方形,平面
、平面
都与平面
垂直,
,点
分别为
的中点,点
在棱
上,则( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0585b6c0f156eecf9662b9846d4eb693.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411b38a18046fea8e9fab1f9f9b80a5f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1e582d73b96ba649378379c3074d506d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/852aabd89edffc1b94344ff3f1f31ccd.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411b38a18046fea8e9fab1f9f9b80a5f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0f5019d74a9497f861a0f755ea31d010.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2fe7fd9b0c3c203a053a7ea52b71e7c9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4762d59261265112fef9ac74d5bb9a36.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2a30f3a8b673cc28bd90c50cf1a35281.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/48f3c9abbd78e9a6840ee5f30381daac.png)
A.四边形BCTS为等腰梯形 |
B.不存在点![]() ![]() ![]() |
C.存在点![]() ![]() |
D.点![]() ![]() ![]() |
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解题方法
2 . 已知正方体
的边长为1,现有一个动平面
,且![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e170f206fdbbd834aad7580c727e2cc6.png)
平面
,当平面
截此正方体所得截面边数最多时,记此时的截面的面积为
,周长为
,则( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6e09725691ee7851f54c0dee86b2bf55.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e170f206fdbbd834aad7580c727e2cc6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e170f206fdbbd834aad7580c727e2cc6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/638537c0a30676c73fea76c80e0f8bd0.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7935fe3125f247b7bea4f065ce9ad985.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e170f206fdbbd834aad7580c727e2cc6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/cf231f8f86fb922df4ca0c87f044cec3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0f85fca60a11e1af2bf50138d0e3fe62.png)
A.![]() ![]() | B.![]() ![]() |
C.![]() ![]() | D.![]() ![]() |
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3 . 已知正四面体
的棱长为1,若棱长为
的正方体能整体放入正四面体
中,则实数
的最大值为__________ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/891579e7c231584a8e16b8eeff79888e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0a6936d370d6a238a608ca56f87198de.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/891579e7c231584a8e16b8eeff79888e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0a6936d370d6a238a608ca56f87198de.png)
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2024·全国·模拟预测
解题方法
4 . 在四棱锥
中,底面
为正方形,平面
都与平面
垂直,
,点
分别为
的中点,且
是线段
上一点(包含端点),给出下列结论:①四边形
为等腰梯形;②不存在点
,使得
平面
;③存在点
,使得
;④
的最小值为
.其中所有正确结论的序号为______ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0585b6c0f156eecf9662b9846d4eb693.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411b38a18046fea8e9fab1f9f9b80a5f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a05792860611772f0525f4acc6b06212.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411b38a18046fea8e9fab1f9f9b80a5f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0f5019d74a9497f861a0f755ea31d010.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2fe7fd9b0c3c203a053a7ea52b71e7c9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4762d59261265112fef9ac74d5bb9a36.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2a30f3a8b673cc28bd90c50cf1a35281.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/48f3c9abbd78e9a6840ee5f30381daac.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7f27e1f707fdd30a58d8a019e6a1440c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2a30f3a8b673cc28bd90c50cf1a35281.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/497b94185aad68ee732a4435b0189c68.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/aea3cebae1762106ecd2a4fd56d07763.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2a30f3a8b673cc28bd90c50cf1a35281.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0b757706eee506a078fc25e3f33a70cb.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4ae7c0b22a09146fe87955159f70454b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/20c29c3bfdae2d4fbe8a8deaa572a2e6.png)
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解题方法
5 . 校足球社团为学校足球比赛设计了一个奖杯,如图,奖杯的设计思路是将侧棱长为6的正三棱锥
的三个侧面沿AB,BC,AC展开得到面
,使得平面
均与平面ABC垂直,再将球
放到上面使得
三个点在球
的表面上,若奖杯的总高度为
,且
,则球
的表面积为( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/63397cda22cb1fad59cf966dfb588643.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/66a3857b390b5cd3618625795b0cd4fa.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/66a3857b390b5cd3618625795b0cd4fa.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1dde8112e8eb968fd042418dd632759e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3f7807638578edd712265463a7a5eab0.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1dde8112e8eb968fd042418dd632759e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8ec978eb43bc4f9e7df83b0d0195dcda.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3d2c15801fee2405573677484f5dcfa4.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1dde8112e8eb968fd042418dd632759e.png)
A.![]() | B.![]() | C.![]() | D.![]() |
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2024高三下·全国·专题练习
解题方法
6 . 已知在直三棱柱
中,
,
,
为线段
的中点,点
在线段
上,若
平面
,则三棱锥
外接球的体积为( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/42d3a82b8e587ee890467835bc4e854c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/080db3af81b29ed10144a1c2e2a4fb8a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/34c488b33d3d0bbaa79ceaaab9980d48.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/54a5d7d3b6b63fe5c24c3907b7a8eaa3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9d88bf46ad08f9677c37eed1d0369329.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ac047e91852b91af639feec23a9598b2.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0f1f229274a6e17977cc047814212589.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/edcf19a7f0dd0cdf59516ae585025110.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9afac7c616bbb14e1ed428a3c507c7dc.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ec21825261a0433b03cc9d962429496a.png)
A.![]() | B.![]() | C.![]() | D.![]() |
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解题方法
7 . 在三棱锥
中,
为正三角形,
为等腰直角三角形,
且
,
,则三棱锥
的外接球
的体积为______ ;若点
满足
,过点
作球
的截面,当截面圆面积最小时,其半径为______ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/891579e7c231584a8e16b8eeff79888e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ab2a2834d80ff574e79eae8ca8d4e94f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/661ff55b5ebbadfb600989af3cfce2fd.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4bd6a2b112facda441f4e34bf5c145fa.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/aa7aeb2a8d1437eeb4482c3b6ad9f315.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/29e240a6378adf6d23ebf9cc710c9bd6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/891579e7c231584a8e16b8eeff79888e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1dde8112e8eb968fd042418dd632759e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2a30f3a8b673cc28bd90c50cf1a35281.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c1f408c8e7d0a17e9e2be9417800a8f0.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2a30f3a8b673cc28bd90c50cf1a35281.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1dde8112e8eb968fd042418dd632759e.png)
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解题方法
8 . 4个半径为1的球两两相切,下面3个上面1个堆放两层摆放在桌上,问上面的球的最高处到桌面的距离为______ ,在4个球的中间再放1个小球和4个球都相切,小球的半径为______ .
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解题方法
9 . 圆锥内半径最大的球称为该圆锥的内切球,若圆锥的顶点和底面的圆周都在同一个球面上,则称该球为圆锥的外接球.如图,圆锥
的内切球和外接球的球心重合,且圆锥
的底面直径为6,则( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ef49a3ca580a144cc65a609c167facc1.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ef49a3ca580a144cc65a609c167facc1.png)
A.设圆锥的轴截面三角形为![]() |
B.设内切球的半径为![]() ![]() ![]() |
C.设圆锥的体积为![]() ![]() ![]() |
D.设![]() ![]() ![]() ![]() |
您最近一年使用:0次
2024-05-04更新
|
858次组卷
|
4卷引用:重庆市第十一中学校教育集团2023-2024学年高一下学期期中考试数学试题
重庆市第十一中学校教育集团2023-2024学年高一下学期期中考试数学试题四川省成都市成飞中学2023-2024学年高一下学期5月月考数学试题河北省沧州市2024届高三下学期6月保温考试数学试卷(已下线)专题6 组合体中的外接与内切问题【练】(高一期末压轴专项)
名校
10 . 半正多面体是由两种或两种以上的正多边形围成的多面体.半正多面体体现了数学的对称美.如图在一个棱长为4的正方体中,
,
,……,
,过
三点可做一截面,类似地,可做8个形状完全相同的截面.关于截面之间的位于正方体正中间的这个几何体,下列说法正确的是( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d36fb8219ce5186e7bb59a132eb881ab.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a3ff01e2d34ecd3a793aefca53539ba1.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/05700c3d8a6eddac23d7ff80dcccccc6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d2e2fff17f81d5d24e3c76039b7ed51b.png)
A.当此半正多面体是由正八边形与正三角形围成时,边长为2 |
B.当此半正多面体是由正方形与正三角形围成时,表面积是![]() |
C.当此几何体为半正多面体时![]() ![]() |
D.当此几何体是半正多面体时,可能由正方形与正六边形围成 |
您最近一年使用:0次
2024-05-03更新
|
166次组卷
|
2卷引用:浙江省北斗联盟2023-2024学年高一下学期4月期中联考数学试题