名校
1 . 已知平面非零向量
满足:
,且
与
的夹角为
,则在所有的情况中,
的最小值为______________ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ae951e0bb5a2a406f1572fc1e4964265.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e5c98ca1ecbade737ca81853dc7c42b9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c94075193c11fe43f2396cff5a485054.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d366d8fbb7258ee051f49977441e14a2.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e6c26b2e3a5f4771ac6db26df1b98ae0.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a8b2cfeb00900c367a3874438e315d06.png)
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2 . 已知
,则
的最小值为____________ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d4d01d5cb535c537b2d0a8c854651516.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b6a61cd9a7a66e97c4b889ffad4eb825.png)
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2024-05-28更新
|
603次组卷
|
2卷引用:重庆市重庆乌江新高考协作体2024届高三下学期模拟监测(三)数学试题
名校
解题方法
3 . 已知圆
:
,过点
的直线
与
轴交于点
,与圆
交于
,
两点,则
的取值范围是( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c5db41a1f31d6baee7c69990811edb9f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e5bef4132be669f94f3703898c75e2e6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ed1a65d88f9823d49da8f3b96ea9ec6f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0f85fca60a11e1af2bf50138d0e3fe62.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/81dea63b8ce3e51adf66cf7b9982a248.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dad2a36927223bd70f426ba06aea4b45.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c5db41a1f31d6baee7c69990811edb9f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5963abe8f421bd99a2aaa94831a951e9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7f9e8449aad35c5d840a3395ea86df6d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/61cbbcddb3801bcd6ff894fea10a0773.png)
A.![]() | B.![]() | C.![]() | D.![]() |
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2024-05-13更新
|
597次组卷
|
3卷引用:重庆市乌江新高考协作体2024届高考模拟监测(二)数学试题
名校
解题方法
4 . 如图,在平面四边形
中,
,对任意实数
都有
,若
为
的面积,且
,
,则
的最大值是______ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411b38a18046fea8e9fab1f9f9b80a5f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8f144992e1cbee34868abce1e5ad38c9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/df64046e91b047037f19e4032e3b6de3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1e6cd645dc20fe84351409216b01fc97.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/cf231f8f86fb922df4ca0c87f044cec3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ab2a2834d80ff574e79eae8ca8d4e94f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/130fca17859fc262f24ea769537c6468.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/61fda819f0b890ee07fae86000b8915d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/03902478df1a55bc99703210bccab910.png)
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5 . 重庆南开中学校徽的核心图像为八角星形,八角星形由两个正方形叠加、结合而成,八个角皆为直角,分别指向东、西、南、北、东南、东北、西南、西北八个方向.一是体现“方方正正做人”之意,二是体现南开人“面向四面八方,胸怀博大,广纳新知,锐意进取”之精神.八角星形方圆互动,融合东西,体现了南开中学“智圆行方”的入世哲学、“追求卓越”的立世哲学和“允公允能”的济世哲学.如图,
,
,
,
,
,
,
,
是半径为1的
上的八个等分点,则以下说法正确的有( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5963abe8f421bd99a2aaa94831a951e9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/97c01fdc7bc471af0b264a04aef0823e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7f9e8449aad35c5d840a3395ea86df6d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b1241216f3c1cb5e73043dd1037f556d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c5db41a1f31d6baee7c69990811edb9f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6795cae2df43a722e1355e9562d93c09.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8455657dde27aabe6adb7b188e031c11.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a18722354086c42e62334983fc50eb6a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3d97cdc586744d208b6f69c9813af977.png)
A.![]() |
B.![]() |
C.若![]() ![]() ![]() ![]() 则 ![]() |
D.若![]() ![]() ![]() ![]() ![]() ![]() ![]() |
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解题方法
6 . “费马点”是由法国数学家费马提出并征解的一个问题.该问题是:“在一个三角形内求作一点,使其与此三角形的三个顶点的距离之和最小.”意大利数学家托里拆利给出了解答,当
的三个内角均小于
时,使得
的点
即为费马点;当
有一个内角大于或等于
时,最大内角的顶点为费马点.试用以上知识解决下面问题:已知
的内角
所对的边分别为
,且![](https://staticzujuan.xkw.com/quesimg/Upload/formula/178606c42de1fc581d6aad2932289ba0.png)
(1)求
;
(2)若
,设点
为
的费马点,求
;
(3)设点
为
的费马点,
,求实数
的最小值.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15c0dbe3c080c4c4636c64803e5c1f76.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/231b861d6d1f1d0b9f52b041cb40eb62.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8eeafab7e93d2dba0b18aa61b16dfce4.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1dde8112e8eb968fd042418dd632759e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15c0dbe3c080c4c4636c64803e5c1f76.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/231b861d6d1f1d0b9f52b041cb40eb62.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15c0dbe3c080c4c4636c64803e5c1f76.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/24e0c10fb103930eabd5fa18e8f9bb06.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/76f0649064a085fb74c997fb507a9b6d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/178606c42de1fc581d6aad2932289ba0.png)
(1)求
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5963abe8f421bd99a2aaa94831a951e9.png)
(2)若
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/44ac38c5cc951497a4a37778b191bcce.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dad2a36927223bd70f426ba06aea4b45.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15c0dbe3c080c4c4636c64803e5c1f76.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3b8f8a1e38db0e55b9b1934569b24e74.png)
(3)设点
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dad2a36927223bd70f426ba06aea4b45.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e428e7a09732be85c1224e9c8f6a71c5.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d283585c357101b13084466420e1202b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/36a1b09c653185842513e24ebba60bb3.png)
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7 . 已知双曲线
的左、右焦点分别为
,
,左、右顶点分别为
,
,
为坐标原点,直线
交双曲线
的右支于
,
两点(不同于右顶点),且与双曲线
的两条渐近线分别交于
,
两点,则( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b5bef93a53a2004910a8cac32f93c4b0.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f5076289823db419f94e9c0c8f4aafd9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a3fb78c5f885034612c0e030b920143d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ac047e91852b91af639feec23a9598b2.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/54a5d7d3b6b63fe5c24c3907b7a8eaa3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1dde8112e8eb968fd042418dd632759e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0f85fca60a11e1af2bf50138d0e3fe62.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c5db41a1f31d6baee7c69990811edb9f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dad2a36927223bd70f426ba06aea4b45.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/acc290b44635265137fdf13146b6a6d9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c5db41a1f31d6baee7c69990811edb9f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5963abe8f421bd99a2aaa94831a951e9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7f9e8449aad35c5d840a3395ea86df6d.png)
A.![]() |
B.![]() |
C.点![]() ![]() |
D.不存在直线![]() ![]() |
您最近一年使用:0次
2024-05-08更新
|
821次组卷
|
3卷引用:重庆市乌江新高考协作体2024届高考模拟监测(一)数学试题
名校
解题方法
8 . 对于一组向量
,(
且
),令
,如果存在
,使得
,那么称
是该向量组的“长向量”.
(1)设
,
且
,若
是向量组
的“长向量”,求实数
的取值范围;
(2)若
且
,向量组
是否存在“长向量
”?若存在,求出正整数
;若不存在,请说明理由;
(3)已知
均是向量组
的“长向量”,其中
,
.设在平面直角坐标系中有一点列
满足,
为坐标原点,
为
的位置向量的终点,且
与
关于点
对称,
与
(
且
)关于点
对称,求
的最小值.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/77f81d9f99e641bb157713fdeedc259f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dd4613271f782a90ab580131d09d03d1.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3bcfc48f9bc23cc43085bdb910e7a136.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/92c1d22f02fa7f8f1ff1db3f322a9fc5.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e955b4525bb55e72c131d829406df508.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c98c622975aaf93ed0c63be1294d2170.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1f50ecfa147131019f969c3bc78169f7.png)
(1)设
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3c33a899454f0d42377d4ea0324dd812.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dd4613271f782a90ab580131d09d03d1.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/de8610232c77741a37463feba1a66c94.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/67dbe2e19d8960789ec873b687998b58.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/be0aca31150d49fff8a60dc4d5df88a7.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/81dea63b8ce3e51adf66cf7b9982a248.png)
(2)若
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/13c75496cf010597a274404439722ba9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/de8610232c77741a37463feba1a66c94.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/aaa63e77491c081392e287e60b507da8.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/cd2c185dfb8bccce40ca2818c652cd99.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9aa8a716a31b0f51b70fdf9bdb257909.png)
(3)已知
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/be0aca31150d49fff8a60dc4d5df88a7.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/be0aca31150d49fff8a60dc4d5df88a7.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/45647cbdf82e8c6a1fe3ea5f79d760dd.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/280cf6971687fe4fc518d29f24c40709.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e47e7afd7287b26737db83b5e709a881.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2708fa6298e52f617383efc175b71ddc.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9b9cb8e6ff801523b0304576cd69fd2d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/82dc7540c4cdee4c34a9311c79b35d95.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0fc4dc226800792c55eaa32134041837.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/36f306a75051c9a11c92aa30a836a016.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2708fa6298e52f617383efc175b71ddc.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c2b5ea93b62e9b06f0060ab0d09e6633.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0fc4dc226800792c55eaa32134041837.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0e10f2f74e201f77f853e9ed9078615c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2f0d68648b10fce54dfc19c5ee60086d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9b9cb8e6ff801523b0304576cd69fd2d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f13215fec5fb9d2a4f19a60ddc7fdb70.png)
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解题方法
9 . 在
中,内角
所对应边分别为
,则下列说法正确的是( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15c0dbe3c080c4c4636c64803e5c1f76.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/24e0c10fb103930eabd5fa18e8f9bb06.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/76f0649064a085fb74c997fb507a9b6d.png)
A.若点![]() ![]() ![]() |
B.若满足![]() ![]() ![]() ![]() ![]() ![]() |
C.若点![]() ![]() ![]() ![]() |
D.若![]() ![]() ![]() |
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10 .
个有次序的实数
,
,
,
所组成的有序数组
,
,
,
称为一个
维向量,其中
,2,
,
称为该向量的第
个分量.特别地,对一个
维向量
,若
,
,
,称
为
维信号向量.设
,
,则
和
的内积定义为
,且
.
(1)直接写出4个两两垂直的4维信号向量.
(2)证明:不存在6个两两垂直的6维信号向量.
(3)已知
个两两垂直的2024维信号向量
,
,
,
满足它们的前
个分量都是相同的,求证:
.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b6a24198bd04c29321ae5dc5a28fe421.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e72adb45c60c2f63b46e65ff787302bf.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3e88093a749c0d46e0ee931ecfaff925.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/07096af3b99fd1cb11c31f19a2c6408e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/96abfe2da27a63e6affb19a0c80236d9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/de5b983949f56bc3137d48e72a393b57.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3e88093a749c0d46e0ee931ecfaff925.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/07096af3b99fd1cb11c31f19a2c6408e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/11e3810cf1eca832ef7487d354e474d4.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b6a24198bd04c29321ae5dc5a28fe421.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/811ba47ff724fd153378ffe14c1e0b9d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/07096af3b99fd1cb11c31f19a2c6408e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/713ac1eb0d8cce55d51e62ef4a2b1634.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2c05b9832b09731a574d4a4adf7448de.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b6a24198bd04c29321ae5dc5a28fe421.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f42b3123092bbc1c62e30b0253edd09b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/80bd9ca5f1ebecf069be3b25efafd29a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7c45176df950dfe48b8ca7eac08ee349.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6460555341932b6b590af7d74b8f0db7.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7a2f4b1178f68bd147d1a2a6acd04435.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b6a24198bd04c29321ae5dc5a28fe421.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f42b3123092bbc1c62e30b0253edd09b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3507f3193277c2f2a5e9d83d25cc9366.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7a2f4b1178f68bd147d1a2a6acd04435.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c94075193c11fe43f2396cff5a485054.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3b73255f197b518efc343bc9776837e8.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/44cfce6ff54e403e1486244d51395bed.png)
(1)直接写出4个两两垂直的4维信号向量.
(2)证明:不存在6个两两垂直的6维信号向量.
(3)已知
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f0a532e15e232cb4b99a8d4d07c89575.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c814128ea2139e33db94ea590e7c2223.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/aec19b68e3add9d5bfcc6269a1855b87.png)
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![](https://staticzujuan.xkw.com/quesimg/Upload/formula/294f5ba74cdf695fc9a8a8e52f421328.png)
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