名校
1 . 为了测量平面
和平面
的夹角,小明设计如下的方案:如图,设斜坡面
与水平面
的交线为
,小明分别在水平面
和斜坡面
选取
,
两点,且
,
到直线
的距离
,
到直线
的距离
,
,则平面
和平面
夹角的正切值是__________ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e170f206fdbbd834aad7580c727e2cc6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5b5858ee1ce52b251816757257a11c29.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5b5858ee1ce52b251816757257a11c29.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e170f206fdbbd834aad7580c727e2cc6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0f85fca60a11e1af2bf50138d0e3fe62.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e170f206fdbbd834aad7580c727e2cc6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5b5858ee1ce52b251816757257a11c29.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5963abe8f421bd99a2aaa94831a951e9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7f9e8449aad35c5d840a3395ea86df6d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/16e0c5cb53fd85b7a23f0580df6bb49a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5963abe8f421bd99a2aaa94831a951e9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0f85fca60a11e1af2bf50138d0e3fe62.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e8d927585a17c2e98ef7d5a9589a26ac.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7f9e8449aad35c5d840a3395ea86df6d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0f85fca60a11e1af2bf50138d0e3fe62.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/95f06298a0ae0f95f0e018f01dca89e6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2d57f1c01e6b02956297f5b64cbdc78c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e170f206fdbbd834aad7580c727e2cc6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5b5858ee1ce52b251816757257a11c29.png)
![](https://img.xkw.com/dksih/QBM/editorImg/2023/12/6/004658d7-427a-4cec-ab13-d1c55959e3ae.png?resizew=165)
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2 . 如图,在三棱柱
中,四边形
是边长为4的正方形.再从条件①、条件②、条件③中选择两个能解决下面问题的条件作为已知.
![](https://img.xkw.com/dksih/QBM/editorImg/2022/12/11/7a1b2aa1-233b-4777-8cff-97dbc11c5f37.png?resizew=169)
(1)求证:
平面
;
(2)求直线
与平面
所成角的正弦值;
(3)设
是
的中点,棱
上是否存在点
,使得![](https://staticzujuan.xkw.com/quesimg/Upload/formula/67c015d99f2677951bdcd0447240ef93.png)
平面
?若存在,求线段
的长;若不存在,说明理由.
条件①:
;
条件②:
;
条件③:平面
平面
.
注:如果选择多种方案分别解答,那么按第一种方案解答计分.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/42d3a82b8e587ee890467835bc4e854c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6ac61c24f99a4e466f1e2ea011893866.png)
![](https://img.xkw.com/dksih/QBM/editorImg/2022/12/11/7a1b2aa1-233b-4777-8cff-97dbc11c5f37.png?resizew=169)
(1)求证:
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/21f9157fce2a8339d281178c7c0bccbe.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6ac61c24f99a4e466f1e2ea011893866.png)
(2)求直线
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0d8772aa893a9c1d40f714cb25701701.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9afac7c616bbb14e1ed428a3c507c7dc.png)
(3)设
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ac047e91852b91af639feec23a9598b2.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0f1f229274a6e17977cc047814212589.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e0a851907ada2ac2c3c4880a6736d28a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/895dc3dc3a6606ff487a4c4863e18509.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/67c015d99f2677951bdcd0447240ef93.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/638537c0a30676c73fea76c80e0f8bd0.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9afac7c616bbb14e1ed428a3c507c7dc.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/06e322e0c87479bba874db9ae9ba36b5.png)
条件①:
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/02273296ef80813f45933d31a833f160.png)
条件②:
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ff4fcf607b0710d12aaabd17fd053d83.png)
条件③:平面
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a3d7090639341730951c1bc3c9b6164e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6ac61c24f99a4e466f1e2ea011893866.png)
注:如果选择多种方案分别解答,那么按第一种方案解答计分.
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2022-12-10更新
|
535次组卷
|
5卷引用:北京市西城区2022届高三二模数学试题变式题16-21
(已下线)北京市西城区2022届高三二模数学试题变式题16-21北京市陈经纶中学2023-2024学年高二上学期期中考试数学试卷北京市对外经济贸易大学附属中学2023届高三上学期12月月考期末综合测试(一)数学试题北京市日坛中学2023届高三上学期12月月考数学试题(已下线)黄金卷04
3 . 小明设计如下的方案测二面角大小:如图,设斜坡面
与水平面
的交线为
,小明分别在水平面
和斜坡面
选取
两点,且
到直线
的距离
到直线
的距离
,则二面角
的大小为______ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5b5858ee1ce52b251816757257a11c29.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e170f206fdbbd834aad7580c727e2cc6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0f85fca60a11e1af2bf50138d0e3fe62.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e170f206fdbbd834aad7580c727e2cc6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5b5858ee1ce52b251816757257a11c29.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/01c74a907dda6bb7d9d56d009d9df253.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/70620b04ef4440e778e0cb294ce3e6b7.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0f85fca60a11e1af2bf50138d0e3fe62.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ed471231784bd6a6310247ca00c5be40.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0f85fca60a11e1af2bf50138d0e3fe62.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7e1ddab62c0c2c25e3c7636c8e5264b0.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/82f505d218a1b600292e2826aba71460.png)
您最近一年使用:0次
4 . 小波到一个广告公司去应聘包装设计师职位,考官给大家出了一道题目:某礼品厂生产一种棱长为a的正四面体形状的礼品(如图).请你为它设计一个包装盒,形状随意,可提出不同方案供考官选择(不考虑包装盒材料的质量、厚度、重量及接缝处损耗)
(1)小波给出了长方体和圆柱两个设计方案(如图),请分别计算这两个包装盒的表面积;
(2)考虑到礼品各面易碎,礼品较大,包装盒体积不能太大,但礼品各面与包装盒表面之间需要有填充物,请你帮小波设计一个方案.(需要面图表示,并配以简单说明理由)
![](https://img.xkw.com/dksih/QBM/editorImg/2023/8/3/50abad76-17cf-439e-8f5a-0e1247a0c6b6.png?resizew=392)
(1)小波给出了长方体和圆柱两个设计方案(如图),请分别计算这两个包装盒的表面积;
(2)考虑到礼品各面易碎,礼品较大,包装盒体积不能太大,但礼品各面与包装盒表面之间需要有填充物,请你帮小波设计一个方案.(需要面图表示,并配以简单说明理由)
您最近一年使用:0次
名校
解题方法
5 . 如图,在四棱柱
中,侧棱
垂直底面
,
,
,![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b4adb74be3d8886525bc02bbc2f0f556.png)
(1)求证: CD⊥平面
.
(2)已知
,求二面角
的大小.
(3)现将与四棱柱
形状和大小完全相同的两个四棱柱拼成一个新的四棱柱,规定:若拼成的新四棱柱形状和大小完全相同,则视为同一种拼接方案,问共有几种不同的拼接方案?在这些拼接成的新四棱柱中,记其中最小的表面积为
,写出
的解析式.(直接写出答案,不必说明理由)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6e09725691ee7851f54c0dee86b2bf55.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2777840758e70e7dbbc18cef8f3d6d2b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411b38a18046fea8e9fab1f9f9b80a5f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/10df84d553a8826a7ce9bff4bf0d95b9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ad1a56baf43ffdf67bc8460856e31fec.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b4adb74be3d8886525bc02bbc2f0f556.png)
![](https://img.xkw.com/dksih/QBM/editorImg/2023/11/9/cab0c144-a341-47af-911d-2805d8a96701.png?resizew=160)
(1)求证: CD⊥平面
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5ebb05874eb3353d754af24c9974273e.png)
(2)已知
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5095a28bb1b91bf6bed9e2cfbd76bb18.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e3fec4fba64d1631538fb9da2c846e23.png)
(3)现将与四棱柱
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6e09725691ee7851f54c0dee86b2bf55.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a0e6cb8d4e39fa44f71df04b74f123f4.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a0e6cb8d4e39fa44f71df04b74f123f4.png)
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名校
6 . 等腰梯形
中,
,
,
.若点
、
均在
上,且
.如图(一)所示,沿
将
折起,沿
将
折起,使
、
两点重合为
.
(1)若
,如图(二)所示,求证:平面
平面
;
(2)若
,
为
中点,当
与
重合于
时,如图(三)所示,求
与平面
所成角的余弦值;
(3)请设计一个翻折方案使四棱锥
的外接球半径为
,证明你的结论,并求此方案下的
的长度及
的大小.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411b38a18046fea8e9fab1f9f9b80a5f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8a11029ca6b4b9e7f777af0280cf163c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b040eb31b0b7073ad3ffa8bd7968d187.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/037b342a682cbd4241855a243da3c016.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2a30f3a8b673cc28bd90c50cf1a35281.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a0ed1ec316bc54c37c4286c208f55667.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f52a58fbaf4fea03567e88a9f0f6e37e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/04f8eebda19eded2b059774a8c2666c3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e6e490f703eb6c9bb1278c78ebc2d661.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a25c28359f8d8da9eaf4672a6cf8ae4f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4cae70b8a9d2d2e96dea62c00ced04b9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6830ebecddbd9759be626289c408e4f3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5963abe8f421bd99a2aaa94831a951e9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7f9e8449aad35c5d840a3395ea86df6d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/cf231f8f86fb922df4ca0c87f044cec3.png)
![](https://img.xkw.com/dksih/QBM/editorImg/2023/7/27/ba897f14-f9d7-44dc-b819-8c1cfd0adc02.png?resizew=459)
(1)若
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/27aa17bad024a9361bd0a679e10f70ac.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c6bec37dca00db5f4512ce70f16ceb20.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3747e528a1e8d45668ccf835c0175a73.png)
(2)若
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3f4aca5534bce25acaeb7379deed8f8f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1dde8112e8eb968fd042418dd632759e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f52a58fbaf4fea03567e88a9f0f6e37e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2a30f3a8b673cc28bd90c50cf1a35281.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a0ed1ec316bc54c37c4286c208f55667.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1dde8112e8eb968fd042418dd632759e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/18e5ef91fb27dd684a27ae7f1993cfba.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9ef796b46e68fe77b117ff0483d2370c.png)
(3)请设计一个翻折方案使四棱锥
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8ff027309f3108559e6b3915158a3867.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8d5989c84e320b504511f23eeb6e7357.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/03902478df1a55bc99703210bccab910.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2b3b0b11a80e8b107e55534d7fda9f2b.png)
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解题方法
7 . 如图所示,一个仓库设计由上部屋顶和下部主体两部分组成,屋顶的形状是四棱锥
,四边形
是正方形,点
为正方形
的中心,
平面
;下部的形状是长方体
.已知上部屋顶造价与屋顶面积成正比,比例系数为
,下部主体造价与高度成正比,比例系数为
.现欲建造一个上、下总高度为12 m,
m的仓库.
![](https://img.xkw.com/dksih/QBM/editorImg/2023/1/18/db3d6302-b269-46f8-a273-d4cf4d96cced.png?resizew=175)
(1)①若屋顶的高
,请将总造价表示为x的函数;
②若屋顶侧面与底面所成二面角角为
,请将总造价表示为
的函数;
(2)选择(1)中的一个方案,求出总造价的最小值.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0585b6c0f156eecf9662b9846d4eb693.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411b38a18046fea8e9fab1f9f9b80a5f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1dde8112e8eb968fd042418dd632759e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411b38a18046fea8e9fab1f9f9b80a5f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f3e126c16032892966489053f44b9048.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411b38a18046fea8e9fab1f9f9b80a5f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6e09725691ee7851f54c0dee86b2bf55.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/893d4e8d70ea2c716ac7b6c1777a77f2.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1bf8ed39e78ace72ea02b2106117d92e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/305a88d4e0249bd16d48eda01331d2d4.png)
![](https://img.xkw.com/dksih/QBM/editorImg/2023/1/18/db3d6302-b269-46f8-a273-d4cf4d96cced.png?resizew=175)
(1)①若屋顶的高
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b5b2822632a493ac9d197d11a12df512.png)
②若屋顶侧面与底面所成二面角角为
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c24095e409b025db711f14be783a406c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c24095e409b025db711f14be783a406c.png)
(2)选择(1)中的一个方案,求出总造价的最小值.
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19-20高一·全国·课后作业
8 . 地面上插有一根直杆,将地面看成平面,只借助于绳子与米尺,你能检测出直杆与地面是否垂直吗?写出你的方案并说明理由.
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2020-01-31更新
|
49次组卷
|
3卷引用:人教B版(2019)必修第四册课本例题11.4.1 直线与平面垂直
人教B版(2019)必修第四册课本例题11.4.1 直线与平面垂直(已下线)【新教材精创】11.4.1 直线与平面垂直(第1课时)导学案(1)人教B版(2019) 必修第四册 逆袭之路 第十一章 立体几何初步 11.4.1 直线与平面垂直
名校
9 . 如图,在直四棱柱
中,![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6b05db872c7a37e0d06ca9f0278f9562.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f6f8caf1d83ac27191a7a4ce3d81c769.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8e5fb45af7400c71ac728f9dfa09a5cb.png)
,![](https://staticzujuan.xkw.com/quesimg/Upload/formula/48d30832deeebfc30b1799624e75b75f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/223036d27be5914db50fbd5cb19d4212.png)
:
![](https://img.xkw.com/dksih/QBM/editorImg/2022/12/29/727ef02f-bf3c-4f85-8b52-52dc0d6654f1.png?resizew=182)
(1)求证:
平面
;
(2)现将与四棱柱
形状和大小完全相同的两个四棱柱拼成一个新的四棱柱,规定:若拼成的新四棱柱形状和大小完全相同,则视为同一种拼接方案,问共有几种不同的拼接方案?在这些拼接成的新四棱柱中,记其中最小的表面积为
,写出
的解析式;(直接写出答案,不必说明理由)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6e09725691ee7851f54c0dee86b2bf55.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6b05db872c7a37e0d06ca9f0278f9562.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f6f8caf1d83ac27191a7a4ce3d81c769.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8e5fb45af7400c71ac728f9dfa09a5cb.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ca5cab760038d20eac10fe6108fbb334.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/48d30832deeebfc30b1799624e75b75f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/223036d27be5914db50fbd5cb19d4212.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b377f632949bff36083a5464113387fe.png)
![](https://img.xkw.com/dksih/QBM/editorImg/2022/12/29/727ef02f-bf3c-4f85-8b52-52dc0d6654f1.png?resizew=182)
(1)求证:
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/97f30533da2e1d2a958dc906c37eba9d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5ebb05874eb3353d754af24c9974273e.png)
(2)现将与四棱柱
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6e09725691ee7851f54c0dee86b2bf55.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a0e6cb8d4e39fa44f71df04b74f123f4.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a0e6cb8d4e39fa44f71df04b74f123f4.png)
您最近一年使用:0次
2020-01-13更新
|
304次组卷
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4卷引用:第10讲 柱、锥、台的表面积(核心考点讲与练)-2022-2023学年高二数学考试满分全攻略(沪教版2020必修第三册)
(已下线)第10讲 柱、锥、台的表面积(核心考点讲与练)-2022-2023学年高二数学考试满分全攻略(沪教版2020必修第三册)上海市复旦大学附属中学2015-2016学年高二下学期期中数学试题(已下线)专题4.5 简单几何体【压轴题型专项训练】-2020-2021学年高二数学下学期期末专项复习(沪教版)(已下线)第二章 立体几何中的计算 专题三 空间面积的计算 微点2 空间面积的计算综合训练【基础版】
15-16高三上·上海浦东新·期中
名校
10 . 如图,在四棱柱
中,侧棱
底面
,
,
,
,
,
,
,(
)
平面
;
(2)若直线
与平面
所成角的正弦值为
,求
的值;
(3)现将与四棱柱
形状和大小完全相同的两个四棱柱拼成一个新的四棱柱,规定:若拼成的新四棱柱形状和大小完全相同,则视为同一种拼接方案,问共有几种不同的拼接方案?在这些拼接成的新四棱柱中,记其中最小的表面积为
,写出
的解析式.(直接写出答案,不必说明理由)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6e09725691ee7851f54c0dee86b2bf55.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5845ccc0d735dc14c92a8926d9b1def6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411b38a18046fea8e9fab1f9f9b80a5f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/86c0ad79161fb29ec231dd0248623ed3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ad1a56baf43ffdf67bc8460856e31fec.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0b9740124a284f336f20c98695af04ac.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ca5cab760038d20eac10fe6108fbb334.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8f991c5086ba855802b0331c4e02e3f4.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/223036d27be5914db50fbd5cb19d4212.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2f0d68648b10fce54dfc19c5ee60086d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/97f30533da2e1d2a958dc906c37eba9d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5ebb05874eb3353d754af24c9974273e.png)
(2)若直线
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2777840758e70e7dbbc18cef8f3d6d2b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a211ad5a06b505b8365a62c1946f3cb7.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8a4e6eb3663870ed202cc208eaf239dc.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f0a532e15e232cb4b99a8d4d07c89575.png)
(3)现将与四棱柱
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6e09725691ee7851f54c0dee86b2bf55.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/fa7a84d7e5d6236009a8be655bd500fd.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/fa7a84d7e5d6236009a8be655bd500fd.png)
您最近一年使用:0次
2020-02-05更新
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851次组卷
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5卷引用:第一章 空间向量与立体几何(压轴必刷30题4种题型专项训练)-【满分全攻略】2023-2024学年高二数学同步讲义全优学案(人教A版2019选择性必修第一册)
(已下线)第一章 空间向量与立体几何(压轴必刷30题4种题型专项训练)-【满分全攻略】2023-2024学年高二数学同步讲义全优学案(人教A版2019选择性必修第一册)(已下线)上海市华东师大二附中2016届高三上学期期中数学试题(已下线)上海市华东师范大学第二附属中学2020-2021学年高二下学期期中数学试题北京市一零一中学2021-2022学年高二上学期期末考试数学试题辽宁省实验中学2024届高三考前模拟数学试卷