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解答题 | 容易(0.94) | 2022·全国高三专题练习
解题方法
1 . 已知数列eqId2c1230a9ef5a4968be599681d676dd2b满足eqId6ca9e2479cd94a628c9ce3a5079451dbeqId9286163a63004a53a7334dc742be02d2
(1)数列中有哪些项是负数?
(2)当eqId5f904d1376ac4de7a7d6cfea92ff6981为何值时,eqIdef9cef8e6d054d8dac46b8cde14953ad取得最小值?并求出此最小值.
更新:2021/07/31组卷:0
填空题 | 一般(0.65) | 2022·全国高三专题练习
解题方法
2 . 等差数列eqId2c1230a9ef5a4968be599681d676dd2b的前eqId5f904d1376ac4de7a7d6cfea92ff6981项和为eqIddb5481de79c946c0a760143297d5eade,且满足eqIdbc82f5e351f94d6ea832c619b78ac446eqId18c78343c6634c8ba109b6e9b7f3d35d,则使eqIddb5481de79c946c0a760143297d5eade取得最大值的eqId5f904d1376ac4de7a7d6cfea92ff6981______
更新:2021/07/31组卷:0
解答题 | 一般(0.65) |
3 . 已知数列eqId2c1230a9ef5a4968be599681d676dd2b的各项均为正数,前eqId5f904d1376ac4de7a7d6cfea92ff6981项和为eqIddb5481de79c946c0a760143297d5eade,且eqId7e876fbd55164cb495c852c9b382ee7c
(1)求证:eqId2c1230a9ef5a4968be599681d676dd2b为等差数列;
(2)设eqId114e5b543e2644a49dde45d125c5a857,求数列eqIda0db2906046940e19de8782f94f34137的前eqId5f904d1376ac4de7a7d6cfea92ff6981项和eqId92ed363a54bd4a8a93df9463bb3af1f5
更新:2021/07/25组卷:213
单选题 | 较易(0.85) | 2021·广西南宁三中高一期中
解题方法
4 . 如果等比数列eqId93e38ecd74a24cb59da79181b95bfd3a的前n项和为eqIddb5481de79c946c0a760143297d5eade,且eqId5adbbfacb0d947e4b542c0f4bbc31ceceqId2db6ecdb400e4e5cbddf7034733456be,那么公比eqId5512abdadb95474a84550c0bb477fd32(   )
A.2B.2或eqId4c0fea3781d84454a9f933aab6fe70bcC.eqId4c0fea3781d84454a9f933aab6fe70bcD.2或eqId5f51ce9cc7fe4412baeb871cceb26665
5 . 设数列eqId93e38ecd74a24cb59da79181b95bfd3a的前eqId5f904d1376ac4de7a7d6cfea92ff6981项和为eqIddb5481de79c946c0a760143297d5eade,对一切eqId532dc4d959024b79b546428f5856e5aa,点eqId07106eb7416443968348381830d12dec都在函数eqIdb9df3860a3dc49499138374c49f01abc的图像上.
(1)将数列eqId93e38ecd74a24cb59da79181b95bfd3a依次按1项、2项、3项、4项循环地分为eqIdf8ce4aff05534ba4b6a76932e7feca92eqId5ce94aab476c4603abbbe2fd4076d3f1eqId41be0c58f2fb46bdab04a8aa4cb8cfa3eqId8d9d396476b14b87bef13745f73551ceeqId947ea708e301457dab4f87b59576471beqIdfcdf87d4b9964369b4eeb66004ca3679eqIda74071330df04e03a8ef35601bc0a81eeqId3e525888c7714de2988de1af510916a7eqIda2564aef23644807a9e565d21625ce7c、…,分别计算各个括号内各数之和,设由这些和按原来括号的前后顺序构成新的数列为eqIdeeb4ca98872f4e6d91cea28f43fc0b63,求eqId0099a995574f42b287c4829c24564c0c的值;
(2)设eqId174d58136ce34b5089892e7bb0dd4004为数列eqIdf6db94b159c847cfa6d16771500a88ba的前eqId5f904d1376ac4de7a7d6cfea92ff6981项积,若不等式eqIdd50e3f1213d8418eb82625d63ff580e1对一切eqId532dc4d959024b79b546428f5856e5aa都成立,求eqId70a27b6ddf6b478285353abb3b1f3741的取值范围.
单选题 | 较易(0.85) | 2021·上海复旦附中高二期末
解题方法
6 . 已知数列eqId054d5a7de5684002909fe944c86227c2的通项公式为eqIde58548e1d0bd4b8fa54bb6fd3427f88deqIdd80748a60dc04eb5bc4556d4e5cad370是数列eqId054d5a7de5684002909fe944c86227c2的最小项,则实数eqId70a27b6ddf6b478285353abb3b1f3741的取值范围是(   )
A.eqId68c8a2568f6c4658bd6f9a59c0270162B.eqId9ecd602974c242c1840434e0e23dabe3
C.eqId882577fc690c4f6396d75810eaa12ac8D.eqId7ee1e484374e406ca4ceb851fafaf466
7 . 已知数列eqId93e38ecd74a24cb59da79181b95bfd3a的首项为eqId2f362741818347e9b2007006deeff9b4,前n顶和为eqIddb5481de79c946c0a760143297d5eade
(1)若eqId21aaacd91f9746ee9f72a4b4e8b23dd2,求数列eqId93e38ecd74a24cb59da79181b95bfd3a的通项公式;
(2)在(1)的条件下,是否存在eqId2f362741818347e9b2007006deeff9b4,使得对任意eqIdce57d815b3ae4582a03225a8fe63dccb,恒有eqId86532d354aa746e18e8c18622efabc58(其中k是与正整数n无关的常数),若存在,求出xk的值,若不存在,说明理由;
(3)若eqId93e38ecd74a24cb59da79181b95bfd3a是无穷等比数列,且公比eqId43aa5723d7044fb2bb6d5d8f8a26adbb,计算eqIdd821b1ccef04444fb4c163d040c7ff13
单选题 | 一般(0.65) | 2021·北京二十中高二期末
解题方法
8 . 无穷数列eqId93e38ecd74a24cb59da79181b95bfd3ak个不同的数组成,前n项和为eqIddb5481de79c946c0a760143297d5eade,若对eqId6155d5095e254297bfa6a0166b195ce2,则k的最大值是(   )
A.3B.4C.5D.6
多选题 | 较易(0.85) | 2021·湖北高二期中
9 . 已知数列eqId93e38ecd74a24cb59da79181b95bfd3a是等比数列,公比为eqIda5d0fc594d4048549d5bbda484fbecc8,前eqId5f904d1376ac4de7a7d6cfea92ff6981项和为eqIddb5481de79c946c0a760143297d5eade,下列判断正确的有(   )
A.eqId88ef23c03cc5404f9ddfcd092ce5ed85为等比数列B.eqIdcfe70cee123d4c638c1678e7d097ca70为等差数列
C.eqId62e888038e7a4983be27989b76b284ae为等比数列D.若eqId1151b5278e4945e59c91962216cf85e3,则eqId496c66f8d2e44dc9b1ab5dec200f47ad
填空题 | 较易(0.85) |
解题方法
同步
10 . 在等差数列eqId93e38ecd74a24cb59da79181b95bfd3a中,eqIde51b875643c044d9afaef0a0a3998dd8eqIdca19c700219248bdb9970e80e029af74=____.
更新:2021/07/13组卷:123
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