1 . 牛顿迭代法是求方程近似解的一种方法.如图,方程
的根就是函数
的零点
,取初始值
的图象在点
处的切线与
轴的交点的横坐标为
的图象在点
处的切线与
轴的交点的横坐标为
,一直继续下去,得到
,它们越来越接近
.设函数
,
,用牛顿迭代法得到
,则实数
( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/49b7bff9b2431134f7683a9cc4e68acd.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d275fbb3ee5cd1177ca5a2ceecbbef0f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/11bc05f41215f9894e11d1df0465751a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8bb39857aa4d49038751a9e69d367173.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8559f5db9b978cb2bd290dbce7268629.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/81dea63b8ce3e51adf66cf7b9982a248.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a02f9a42a1561e4b186eefa32be85dfb.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a24a2c53e3b0b1c08803e95419f909d3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/81dea63b8ce3e51adf66cf7b9982a248.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/aec19b68e3add9d5bfcc6269a1855b87.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1fe1c31a81f198c443e71b83ca662939.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/11bc05f41215f9894e11d1df0465751a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/448155ab5191a0c80a8de16d44b5aff5.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6c5603d29560e66b2293cea1e3b02289.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6059ced816e65bed957376cd52d853de.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5ccd4162c7d09f970cb77cadacdbe521.png)
A.1 | B.![]() | C.![]() | D.![]() |
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2 . 陶瓷茶壶是中国人很喜爱的一种茶具,不少陶瓷茶壶兼具实用性与艺术性,如图所示的陶瓷茶壶的主体可近似看作一个圆台型容器,忽略茶壶的壁厚,该圆台型容器的轴截面下底为10cm,上底为6cm,面积为
,则该茶壶的容积约为______ L(结果精确到0.1,参考数据:
;
).
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9aa574e9bd11e6f437175cccf618c87b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8639b0b48393b0a99719216160822336.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e17e2352d0c9ec14cb23b702efe5ba30.png)
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2卷引用:山东省智慧上进2024届高三下学期5月大联考数学试题
3 . 古希腊数学家阿基米德发现了“圆柱容球”定理.圆柱形容器里放一个球,该球顶天立地,四周碰边(即球与圆柱形容器的底面和侧面都相切),球的体积是圆柱体积的三分之二,球的表面积也是圆柱表面积的三分之二.在一个“圆柱容球”模型中,若球的体积为
,则该模型中圆柱的表面积为( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c47eb6743075d149f8dc688aca72a00a.png)
A.![]() | B.![]() | C.![]() | D.![]() |
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4 . 《九章算术》中将底面为直角三角形且侧棱垂直于底面的三棱柱称为“堑堵”;底面为矩形,一条侧棱垂直于底面的四棱锥称之为“阳马”.如图,在堑堵
中,
,且
,过点
分别作
于点
于点
,则下列结论正确的是( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/42d3a82b8e587ee890467835bc4e854c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/615fc8790237a1b09af51d6bcad6b595.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9efac5edaa4aae53750360a4856bb3a5.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5963abe8f421bd99a2aaa94831a951e9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4305d8d52fe2cc79c78129652e64bb62.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3b206c519c62ad1f75af30ffae5eab80.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a0ed1ec316bc54c37c4286c208f55667.png)
A.四棱锥![]() | B.直线AE与平面ABC所成的角为![]() |
C.![]() | D.堑堵![]() ![]() |
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解题方法
5 . 投壶是古代士大夫宴饮时做的一种投掷游戏.《礼记・投壶》说:“投壶者,主人与客燕饮,讲论才艺之礼也.”春秋战国时期,诸侯宴请宾客时的礼仪之一就是请客人射箭,后来慢慢用投壶代替了射箭,成为一种大众游戏.甲、乙两人做投壶游戏,比赛规则:第1次用抛一枚质地均匀的硬币确定甲、乙谁先投箭,投入壶内继续,未投入壶内换另一人,依次类推.假设甲、乙两人投壶互不影响,甲把箭投入壶内的概率为
,乙把箭投入壶内的概率为
.
(1)求第2次是乙投的概率;
(2)求两次投完后,甲投中的箭数的分布列和数学期望.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/eac97e6740365c85ad857aff85cefbe5.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7294f5ae2a24ff42e84cd9773b2a7287.png)
(1)求第2次是乙投的概率;
(2)求两次投完后,甲投中的箭数的分布列和数学期望.
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名校
解题方法
6 . 设
,
.如果存在
使得
,那么就说
可被
整除(或
整除
),记做
且称
是
的倍数,
是
的约数(也可称为除数、因数).
不能被
整除就记做
.由整除的定义,不难得出整除的下面几条性质:①若
,
,则
;②
,
互质,若
,
,则
;③若
,则
,其中
.
(1)若数列
满足,
,其前
项和为
,证明:
;
(2)若
为奇数,求证:
能被
整除;
(3)对于整数
与
,
,求证:
可整除
.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b72ea8ec0d9f8b1cfc4de834b8bfb608.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/20849c00c47cbdc43f18d53341b6c4e5.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/87803b7cee18366b89d51799250df510.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6705dba65746e1d4cac6a268b3c806ce.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2c94bb12cee76221e13f9ef955b0aab1.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0a6936d370d6a238a608ca56f87198de.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0a6936d370d6a238a608ca56f87198de.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2c94bb12cee76221e13f9ef955b0aab1.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/020e12ff4f028aba3a205a95e650d72b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2c94bb12cee76221e13f9ef955b0aab1.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0a6936d370d6a238a608ca56f87198de.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0a6936d370d6a238a608ca56f87198de.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2c94bb12cee76221e13f9ef955b0aab1.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2c94bb12cee76221e13f9ef955b0aab1.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0a6936d370d6a238a608ca56f87198de.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/79bda3d07c2fef4d6af4a13ade4c743e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/020e12ff4f028aba3a205a95e650d72b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1e4d6df2a57b7e5be32c05c10257ea6d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/91638bacbf4d15736d26713ba90e0fc4.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0a6936d370d6a238a608ca56f87198de.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2c94bb12cee76221e13f9ef955b0aab1.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/91638bacbf4d15736d26713ba90e0fc4.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1e4d6df2a57b7e5be32c05c10257ea6d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0601879ae4ca9592246d135bfa48658c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/383eb235f8e0ceda13367b16d29e0180.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/503618b9bfb53a06f0ec6a5e427dcdbd.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f0da20edf2714109dcfded7e212ec44a.png)
(1)若数列
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/76aef4cdcb5af742ce28003b7b6c8c20.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e12059d1dac926a235ccd40c3b61b1b6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b6a24198bd04c29321ae5dc5a28fe421.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/08eb71ecf8d733b6932f4680874dbbf3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ed9dbd8ed61db4f1c14f6b0e5f071200.png)
(2)若
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b6a24198bd04c29321ae5dc5a28fe421.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9e1e4de97f8490fddcff16afe8583266.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/20d6fc9b90f370fbb27552876b650f8f.png)
(3)对于整数
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b6a24198bd04c29321ae5dc5a28fe421.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f0a532e15e232cb4b99a8d4d07c89575.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5b96cdd9e003120b6102d927dbf53e39.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5009ce2d56180d31204f77c871fb375c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c4b326965628b5d967aafe9e696fdc07.png)
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2024-05-19更新
|
530次组卷
|
2卷引用:山东中学联盟2024届高考考前热身押题数学试题
名校
7 . 如图为世界名画《星月夜》,在这幅画中,文森特·梵高用夸张的手法,生动地描绘了充满运动和变化的星空.假设月亮可看作半径为1的圆
的一段圆弧
,且弧
所对的圆心角为
.设圆
的圆心
在点
与弧
中点的连线所在直线上.若存在圆
满足:弧
上存在四点满足过这四点作圆
的切线,这四条切线与圆
也相切,则弧
上的点与圆
上的点的最短距离的取值范围为__________ .(参考数据:
)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1dde8112e8eb968fd042418dd632759e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2a30f3a8b673cc28bd90c50cf1a35281.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2a30f3a8b673cc28bd90c50cf1a35281.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/052a11dbe3ffb5fb2060ef673a7f0917.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c5db41a1f31d6baee7c69990811edb9f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c5db41a1f31d6baee7c69990811edb9f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1dde8112e8eb968fd042418dd632759e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2a30f3a8b673cc28bd90c50cf1a35281.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c5db41a1f31d6baee7c69990811edb9f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2a30f3a8b673cc28bd90c50cf1a35281.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1dde8112e8eb968fd042418dd632759e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c5db41a1f31d6baee7c69990811edb9f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2a30f3a8b673cc28bd90c50cf1a35281.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c5db41a1f31d6baee7c69990811edb9f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f626a3b0ce7d148a23f456a9812e80b0.png)
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2024-04-19更新
|
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3卷引用:山东省青岛第二中学2024届高三下学期二模考试数学试题
8 . 12世纪以前的某时期,盛行欧洲的罗马数码采用的是简单累数制进行记数,现在一些场合还在使用,比如书本的卷数、老式表盘等.罗马数字用七个大写的拉丁文字母表示数目:
例如:
,
.依据此记数方法,
( )
I | V | X | L | C | D | M |
1 | 5 | 10 | 50 | 100 | 500 | 1000 |
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ee5c7388410a2546c11954767192a35d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4b529f1592b4c07e0158e139656ad827.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3c24ce95b5b691b4e15b4fb12cdf2311.png)
A.2025 | B.2035 | C.2050 | D.2055 |
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名校
9 . 2024年2月4日,“龙行中华——甲辰龙年生肖文物大联展”在山东孔子博物馆举行,展览的多件文物都有“龙”的元素或图案.出土于鲁国故城遗址的“出廓双龙勾玉纹黄玉璜”(图1)就是这样一件珍宝.玉璜璜身满刻勾云纹,体扁平,呈扇面状,璜身外镂空雕饰“S”型双龙,造型精美.现要计算璜身面积(厚度忽略不计),测得各项数据(图2):
cm,
cm,
cm,若
,
,则璜身(即曲边四边形ABCD)面积近似为( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/07ba73a9568691f79a654b80fa30012b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/21addc919c14c98fdd0dc94be059f34f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a3df3c1d034440240e3d4d73615b091f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e517611970f373a84c470b7365bdb42f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/47d553e4a26eb3012410ef7558a5fd6d.png)
A.![]() | B.![]() | C.![]() | D.![]() |
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2024-03-15更新
|
1507次组卷
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6卷引用:山东省青岛市2024届高三下学期第一次适应性检测数学试题
10 . 球面被平面所截得的一部分叫做球冠,截得的圆叫做球冠的底,垂直于截面的直径被截得的一段叫做球冠的高.球被平面截下的一部分叫做球缺,截面叫做球缺的底面,垂直于截面的直径被截下的线段长叫做球缺的高,球缺是旋转体,可以看做是球冠和其底所在的圆面所围成的几何体.如图1,一个球面的半径为
,球冠的高是
,球冠的表面积公式是
,与之对应的球缺的体积公式是
.如图2,已知
是以
为直径的圆上的两点,
,则扇形
绕直线
旋转一周形成的几何体的表面积为__________ ,体积为__________ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4aa0df7f1e45f9de29e802c7f19a4f64.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3eabd5f3a86afe49dcd70571e2b96cfd.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/aef5e6ee09edc8b6e274cd45a2e7af02.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d24f6e152f122a7b0c7b72cd40429fda.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/39acab3cfb59bfc9591371721ab01d93.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f52a58fbaf4fea03567e88a9f0f6e37e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4f784040120239d7e75c591029d56c31.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6bf126cfed85fa9b7720ec6f7b0008dc.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f52a58fbaf4fea03567e88a9f0f6e37e.png)
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2024-03-10更新
|
1274次组卷
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4卷引用:山东省临沂市2024届高三下学期一模考试数学试题
山东省临沂市2024届高三下学期一模考试数学试题山东省泰安市新泰第一中学2024届高三下学期高考模拟测试(一)数学试题(已下线)第六章 突破立体几何创新问题 专题二 融合科技、社会热点 微点3 融合科技、社会热点等现代文化的立体几何和问题综合训练【培优版】(已下线)高一 模块3 专题1 小题进阶提升练