名校
解题方法
1 . 正三棱柱
中,
为棱
的中点,
为线段
(不包括端点)上一动点,
分别为棱
上靠近点
的三等分点,过
作三棱柱
的截面
,使得
垂直于
且交
于点
,下列结论正确的是( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/42d3a82b8e587ee890467835bc4e854c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c31dea35a4e0ca65105e1f12aeb0fe5f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/56f7ba05c54b3de1f4378f7c8eb58328.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dad2a36927223bd70f426ba06aea4b45.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/10d8eb4a9f462ca0c1d49c3fe91e720d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7789a500686c7a73770404ead6af0590.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7dec2ca6438c82b43f746057d8129885.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5963abe8f421bd99a2aaa94831a951e9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0dc5c9827dfd0be5a9c85962d6ccbfb1.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/42d3a82b8e587ee890467835bc4e854c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e170f206fdbbd834aad7580c727e2cc6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e170f206fdbbd834aad7580c727e2cc6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/20a541b81584a032f571159ea152c85a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/20a541b81584a032f571159ea152c85a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2a30f3a8b673cc28bd90c50cf1a35281.png)
A.![]() ![]() | B.存在点![]() ![]() ![]() |
C.当![]() ![]() ![]() | D.三棱锥![]() ![]() |
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2卷引用:安徽省县中联盟(江南十校)2023-2024学年高一下学期5月月考数学试题
名校
2 . 已知三棱锥
是边长为2的正三角形,
分别是
的中点,
在平面
内的投影为点
在平面
内的投影为点
.( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/899bb37ff0e8075cf8cf7d589be7d50d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/91e1e4115d78e625e9e0f47cdade3286.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a398d4645333a88e4a0816d5b7087702.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1b085fab4fc7b49bead663650b3bdeb0.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7bef5239ddbb0972700ce01daf9ee7cf.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a9521129014e5f138b49339d5b9f4dda.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f526e2fe627bb4ddebe708c07d0a22fc.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dad2a36927223bd70f426ba06aea4b45.png)
A.![]() |
B.![]() ![]() ![]() |
C.![]() |
D.形如三棱锥![]() |
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2卷引用:河南省郑州市2024届高三第三次质量预测数学试题
解题方法
3 . 在正三棱柱
中
,
的重心为
,以
为球心的球与平面
相切.若点
在该球面上,则下列说法正确的有( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/42d3a82b8e587ee890467835bc4e854c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/141ef400af3ec09829c4a640867acea9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c510b85dfbca0e3ab0744655d77e8c93.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/895dc3dc3a6606ff487a4c4863e18509.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/895dc3dc3a6606ff487a4c4863e18509.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e168672b47d7e64dc1b404f8882c7dcf.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dad2a36927223bd70f426ba06aea4b45.png)
A.存在点![]() ![]() ![]() |
B.三棱锥![]() ![]() |
C.若直线![]() ![]() ![]() ![]() ![]() |
D.若![]() ![]() ![]() |
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解题方法
4 . 故宫角楼的屋顶是我国十字脊顶的典型代表,如图1,它是由两个完全相同的直三棱柱垂直交叉构成,将其抽象成几何体如图2所示.已知三楼柱
和
是两个完全相同的直三棱柱,侧棱
与
互相垂直平分,
交于点I,
,
,则点
到平面
的距离是( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d5399fca789fea184a162bfb6d95afd1.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d9f523fc81603a5c4cdff956a5c3298b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/49b50357a6545cae8348e3059312f520.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e42887d9bf31c1dd99f13c39e63c9ab9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8856a6bbd1648fef7aaa384366e9016f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8df32f10590eccf0d07989db09ad7d48.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4c507610f462120218e2cd1894c957eb.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/895dc3dc3a6606ff487a4c4863e18509.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/fd4b93d7abcfc4c3df48f03aa969c17f.png)
A.![]() | B.![]() | C.![]() | D.![]() |
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3卷引用:北京市中国人民大学附属中学2024届高三下学期5月热身练习数学试题(三模)
名校
解题方法
5 . 记正四棱柱
为
,截面
将正四棱柱
分成两部分,点E,F,G,H分别在棱
,
,
,
上,且
,
,记
,
,
,
,则下列说法正确的是( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6e09725691ee7851f54c0dee86b2bf55.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/cffa35373ec4e4684107b42adb7a5161.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f09757d013574cf058d5bb944fdf034a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/cffa35373ec4e4684107b42adb7a5161.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2777840758e70e7dbbc18cef8f3d6d2b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e0a851907ada2ac2c3c4880a6736d28a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9d88bf46ad08f9677c37eed1d0369329.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/22adbc0da438220f9cace11b629d799b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/cb9458b63a4e8425c6f59e0e37887d6d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/681e6304ec3b733adde692837bf2602a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/17eb884c0e7414be81990409dba252f3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/28bc8a47c5268ebfc7329b3398bb9f36.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/463c91e95bf032d464b20f0c53f39d30.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d6125e6e8d7406d54c93512a9fb2cbbe.png)
A.四边形![]() |
B.![]() |
C.若截面![]() ![]() ![]() ![]() ![]() ![]() |
D.若![]() ![]() ![]() ![]() ![]() |
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解题方法
6 . 已知矩形
,其中
,
,点D沿着对角线
进行翻折,形成三棱锥
,如图所示,则下列说法正确的是__________ (填写序号即可).
①点D在翻折过程中存在
的情况;
②三棱锥
可以四个面都是直角三角形;
③点D在翻折过程中,三棱锥
的表面积不变;
④点D在翻折过程中,三棱锥
的外接球的体积不变.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411b38a18046fea8e9fab1f9f9b80a5f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/54275b7e571660d0a9e0370fbfe5050b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/fc11331a7b2d2619b40ee6d34c3bd620.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/60ef95894ceebaf236170e8832dcf7e3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c586b72a984e1fd9082b9f02ef7f3e91.png)
①点D在翻折过程中存在
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dc9aabd9a42a97a1108149fafca8a919.png)
②三棱锥
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c586b72a984e1fd9082b9f02ef7f3e91.png)
③点D在翻折过程中,三棱锥
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c586b72a984e1fd9082b9f02ef7f3e91.png)
④点D在翻折过程中,三棱锥
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c586b72a984e1fd9082b9f02ef7f3e91.png)
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2卷引用:黑龙江省2024届高三信息押题卷(四)数学试卷
7 . 用一个不垂直于圆锥的轴的平面截圆锥,当圆锥的轴与截面所成的角不同时,可以得到不同的截口曲线,也即圆锥曲线.探究发现:当圆锥轴截面的顶角为
时,若截面与轴所成的角为
,则截口曲线的离心率
.例如,当
时,
,由此知截口曲线是抛物线.如图,圆锥
中,
、
分别为
、
的中点,
、
为底面的两条直径,且
、
,
.现用平面
(不过圆锥顶点)截该圆锥,则( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f8dd0c52aca1675c17b9a019aa7901e3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5b5858ee1ce52b251816757257a11c29.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e44f6ec575a7e7efb670d5c39bdcc2e7.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ffa3205b1df826d63914dcb55bb3ab43.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/09dbcaa127022fbd6b6f13345196408a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/18e5ef91fb27dd684a27ae7f1993cfba.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ac047e91852b91af639feec23a9598b2.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/54a5d7d3b6b63fe5c24c3907b7a8eaa3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/defa5b53043ae802bb1af7d14374406d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/18e5ef91fb27dd684a27ae7f1993cfba.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f52a58fbaf4fea03567e88a9f0f6e37e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9d78abbad68bbbf12af10cd40ef4c353.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a77e3c1c236141d6118429fade0a9b9d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3d2c15801fee2405573677484f5dcfa4.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1a727432fbf5b502786cdb18b84b8920.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9f435efcc7869eec21bdba1ed81dc3f5.png)
A.若![]() |
B.若![]() ![]() ![]() |
C.若![]() |
D.若截口曲线是离心率为![]() ![]() |
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2卷引用:2024届广东省汕头市普通高考第二次模拟考试数学试题
解题方法
8 . 在棱长为1的正四面体
中,P为棱
(不包含端点)上一动点,过点P作平面
,使
,
与此正四面体的其他棱分别交于E,F两点,设
,则
的面积S随x变化的图象大致为( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411b38a18046fea8e9fab1f9f9b80a5f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f52a58fbaf4fea03567e88a9f0f6e37e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e170f206fdbbd834aad7580c727e2cc6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/398a7cdc39e756d8f7f7ee1185579b37.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e170f206fdbbd834aad7580c727e2cc6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0924d39475d22d6ce04fbca2bfff2d40.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/91b51d3992644d37dc71c9b5a97d515c.png)
A.![]() | B.![]() |
C.![]() | D.![]() |
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名校
解题方法
9 . 如图,将边长为1的正
以边
为轴逆时针翻转
弧度得到
,其中
,构成一个三棱锥
.若该三棱锥的外接球半径不超过
,则
的取值范围为( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15c0dbe3c080c4c4636c64803e5c1f76.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f52a58fbaf4fea03567e88a9f0f6e37e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c24095e409b025db711f14be783a406c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4c430808cb91d66ce60b1e2f83f129db.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/476c1028ab48d8f3779e1217b8bf63d5.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/45bc09ca07b357a1ecf0c9588aa7030e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2e5f1b9a7dc93aa2cd57d6352d000bb1.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c24095e409b025db711f14be783a406c.png)
A.![]() | B.![]() | C.![]() | D.![]() |
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解题方法
10 . 设
为某正方体的一条体对角线,
为该正方体的各顶点与各棱中点所构成的点集,若从
中任选两点连成线段,则与
垂直的线段数目是( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0f85fca60a11e1af2bf50138d0e3fe62.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/cf231f8f86fb922df4ca0c87f044cec3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/cf231f8f86fb922df4ca0c87f044cec3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0f85fca60a11e1af2bf50138d0e3fe62.png)
A.12 | B.21 | C.27 | D.33 |
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|
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