组卷网>知识点选题>第二章 函数
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2 . 已知函数eqId4f79db489b4b4934ae1a26c88ea3dd9deqId10852d81bc184140a7780250c82c6929在区间eqId07fe60636b4d48ed881ed8fff0b52c0c上至少有5个零点,eqId10852d81bc184140a7780250c82c6929在区间eqId79a49ec73ec64f6f924d0d3e3585df66上至多有5个零点,则正数eqId70a27b6ddf6b478285353abb3b1f3741的取值范围是(   )
A.eqId0adb7bc6c94d456e8c78da2d0c5a0774B.eqId4e9f1055e3624865b2c34c34295dd9f6C.eqIdafcdc9dbd3574d0988576901f3e421f8D.eqId80351e6ebbe043a4b77508f29bedc5ba
3 . 已知eqId5db22164479c453a84d102b9ee67fd46,则abc的大小关系为(   )
A.abcB.bacC.acbD.bca
4 . 已知函数eqIdca9aeed9307d47718546f2d2198cb422是幂函数eqIde15981fbff7d4970aeecae314a80bb0f,且eqId702e7b2ae91b41669144e788f9f31395.
(1)求函数eqId10852d81bc184140a7780250c82c6929的解析式;
(2)试判断是否存在实数eqIdaea992e70d4943e49e893817eb885ed7,使得函数eqIdacdd140208a24b97998e9a6f2aa50ecc在区间eqIdd4875002eab644559d85b2e36e903b70上的最大值为6,若存在,求出b的值;若不存在,请说明理由.
填空题 | 一般(0.65) | 2021·山东高二期末
5 . 已知eqId16361fcaf60f47319db8c51a179ed472eqId7dcd2312d0bf4bb1befdfcc170e45791上的减函数,则实数eqId70a27b6ddf6b478285353abb3b1f3741的取值范围为______
填空题 | 一般(0.65) | 2021·广东高二期末
6 . 已知函数eqIdd1988f57fbaf4784aa5b8f8749dc4d4c,则函数fx)的最大值是________
单选题 | 较易(0.85) | 2021·山东高二期末
8 . 已知幂函数eqIda17b2441d7634580b15930d55bf951e8,若eqId962be12a045f4993b82559328f843027eqIddd1ffc3480bc42648d9b5c5d18ed03afeqId03f8358b94354792a5737fc4d5a1d136,则(   )
A.eqId18513915a070416db1e6b2d279419695B.eqId96f25c3294b2457ca92c563e42cd8713C.eqId2b09921788f943369b8b2d69257fdda4D.eqId0b6548a2f82b4900bf8b5c24afd5ed7a
9 . 设函数eqId144eff5c0e4649138a21f2b1b6a06907eqIdb5706584ddc64530b68e964587fe3b9a,且eqIdfadd183288e04a06ac1db96be66559a0)对任意非零实数eqId735b8047beee4dee870fc72ae837a245eqIdecaaaffea9af458c8e6dff16f15c1a73,恒有eqId6db5046444e848b89ea8a8b4a2d73e79
(1)求eqId3efcced23e2c4e159f84bb242b122cb4eqIdd2ff946b4b534d078a2c07c045b9864d的值;
(2)判断函数eqId6f13759e937144069819aed2ae5a1057的奇偶性.
10 . 设m为给定的实常数,若函数yfx)在其定义域内存在实数eqId761b2917a82b4524b8dbab7e6380f014,使得eqIdc91a6a7fee624f979b029ad5c9c5643d成立,则称函数fx)为“Gm)函数”.
(1)若函数eqIdc849966698b946dfb67f33df021d9c55为“G(2)函数”,求实数eqId761b2917a82b4524b8dbab7e6380f014的值;
(2)已知eqId9c3fada03df048bbbe7aec1a834529d3为“G(0)函数”,设eqIdc8ffb8015aaf43e7b036afe7fc44a4fb.若对任意的eqId735b8047beee4dee870fc72ae837a245eqIddb81f905534a4e94a752f5fa22b1e4c4,当eqId70c08d40596445378a3ebc3942e99852时,都有eqId7802da76f0b44acfa225d40aef91017a成立,求实数t的最大值.
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