1 . 数学家泰勒给出如下公式:
,
,
这些公式被编入计算工具,计算工具计算足够多的项就可以确保显示值的精确性.若根据以上公式估算
的值,则以下数值中最精确的是( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7dc9e1f1c8fdfa0395c4ba1a08d1f1a6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3a456ea92bfb3ce171144e8ae5cb2663.png)
这些公式被编入计算工具,计算工具计算足够多的项就可以确保显示值的精确性.若根据以上公式估算
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e6c0e54bd4b3293658a6a666625bfb5d.png)
A.0.952 | B.0.994 | C.0.995 | D.0.996 |
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解题方法
2 . 函数
在
的最大值为m,在
的最大值为n,则以下命题为假命题的是( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/58c65d71e57e6e7697e2f627dcd58583.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/983fa8d30993077d136d644a4de7a394.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6ca44b51af56d89266c3aba528d8a8d0.png)
A.![]() ![]() ![]() | B.![]() ![]() ![]() |
C.![]() ![]() ![]() | D.![]() ![]() ![]() |
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解题方法
3 . 将足够多的一批规格相同、质地均匀的长方体薄铁块叠放于水平桌面上,每个铁块总比其下层铁块向外伸出一定的长度,如下图,那么最上层的铁块最多可向桌缘外伸出多远而不掉下呢?这就是著名的“里拉斜塔”问题.将铁块从上往下依次标记为第1块、第2块、第3块、……、第n块,将前
块铁块视为整体,若这部分的重心在第
块的上方,且全部铁块整体的重心在桌面的上方,整批铁块就保持不倒.设这批铁块的长度均为1,若记第n块比第
块向桌缘外多伸出的部分的最大长度为
,则根据力学原理,可得
,且
为等差数列.
的通项公式;
(2)记数列
的前
项和为
.
①比较
与
的大小;
②对于无穷数列
,如果存在常数
,对任意的正数
,总存在正整数
,使得
,
,则称数列
收敛于
,也称数列
的极限为
,记为
;反之,则称
不收敛.请根据数列收敛的定义判断
是否收敛?并据此回答“里拉斜塔”问题.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8c5abd5f2fc2744d7f706656575b7262.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/12444d6e8d3b097a9d090e6ed06042e4.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7a0876215b2fd463d151523cd3c6b447.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/96abfe2da27a63e6affb19a0c80236d9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5ee45219629dd30af171588e646f8b12.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b7b78e4a03d4595f14be42054b61dfc6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/76aef4cdcb5af742ce28003b7b6c8c20.png)
(2)记数列
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/76aef4cdcb5af742ce28003b7b6c8c20.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b6a24198bd04c29321ae5dc5a28fe421.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/08eb71ecf8d733b6932f4680874dbbf3.png)
①比较
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/08eb71ecf8d733b6932f4680874dbbf3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4c6b6c6934eda8f0838d0ba881be2211.png)
②对于无穷数列
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c1fd18a909cecbaee7115d6b15631d83.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5963abe8f421bd99a2aaa94831a951e9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/711c92626a97e6b778b3aa86e663ee97.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e4ccd4537f4dee2050ade38b972eb9b9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/74d1d3b9d14068d68a7cff35ce3e872c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7f4691ee07234d7cfc8a21bed1236c98.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c1fd18a909cecbaee7115d6b15631d83.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5963abe8f421bd99a2aaa94831a951e9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c1fd18a909cecbaee7115d6b15631d83.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5963abe8f421bd99a2aaa94831a951e9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1b85738365edd32d8df21b2d36518029.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c1fd18a909cecbaee7115d6b15631d83.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d013861990cf331c82eb453416ae31bc.png)
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解题方法
4 . 如图所示的几何体是由圆锥
与圆柱
组成的组合体,其中圆柱的轴截面
是边长为2的正方形,圆锥的高
,M为圆柱下底面圆周上异于A,B的点.
∥平面
;
(2)若
,求直线
与平面
所成角的正切值的取值范围.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/41a8c34f622f1b979feed5ae6ae5d0e8.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ae0a4f38420bb9215dbc9c875b755838.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411b38a18046fea8e9fab1f9f9b80a5f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a55a6b8045f2d6429ac49997c1124a25.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/defa5b53043ae802bb1af7d14374406d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/08452588675f76da2f8d31387b3a8224.png)
(2)若
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8b10c2bc31ab83c89237b93159ae64c1.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/03902478df1a55bc99703210bccab910.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/08452588675f76da2f8d31387b3a8224.png)
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名校
解题方法
5 . 泉州花灯技艺源于唐朝中期从形式上有人物灯、宫物灯、宫灯,绣房灯、走马灯、拉提灯、锡雕元宵灯等多种款式.在2024年元宵节,小明制做了一个半正多面体形状的花灯,他将正方体沿交于一顶点的三条棱的中点截去一个三棱锥,共截去八个三棱锥,得到一个有十四个面的半正多面体,如图所示.已知该半正多面体的体积为
,M为
的中心,过M截该半正多面体的外接球的截面面积为S,则S的最大值与最小值之比( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f3d754c4ad51e4482e12a615d20a13fb.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15c0dbe3c080c4c4636c64803e5c1f76.png)
A.![]() | B.![]() | C.3 | D.9 |
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6 . 已知
,动点
满足
,动点
的轨迹为曲线
交
于另外一点
交
于另外一点
.
(1)求曲线
的标准方程;
(2)已知
是定值,求该定值;
(3)求
面积的范围.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/107a80eeecf2efcb25cb008945c1c241.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dad2a36927223bd70f426ba06aea4b45.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8cced7a3d18b398c1da1218d74a96542.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dad2a36927223bd70f426ba06aea4b45.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/81ac4aa6db80d4edfd287abc4580e68b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f09757d013574cf058d5bb944fdf034a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3c72be8e3e113103ca7de54ac39c2313.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f09757d013574cf058d5bb944fdf034a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4aa0df7f1e45f9de29e802c7f19a4f64.png)
(1)求曲线
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f09757d013574cf058d5bb944fdf034a.png)
(2)已知
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/da79ae7251aa6d5822b5396a632b01c7.png)
(3)求
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1c28abb154f41e1ca9816c9c9c2433ca.png)
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7日内更新
|
629次组卷
|
3卷引用:福建省漳州市龙文区2024届高三6月模拟预测数学试题
名校
7 . 椭球面镜具有改变光路的方向、使光束会聚的作用,它经常被用来制作精密的光学仪器的部件.椭球面镜是以椭圆的长轴为旋转轴,把椭圆转动
形成的立体图形,其内表面全部做成反射面,中空,椭球面镜可以将从某个焦点发出的光线全部反射到另一个焦点处.从椭球面镜的焦点
射出的两条光线,经椭球面镜上的
两点反射后汇聚于焦点
,若
,且
,则椭球面镜的轴截面椭圆的离心率为______ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/54e7a123c9cc0e058db28841fb0edcf3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f5076289823db419f94e9c0c8f4aafd9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/01c74a907dda6bb7d9d56d009d9df253.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a3fb78c5f885034612c0e030b920143d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/bea693124f0e69270669bf34a2c4ad9f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b9766e5e316ac8e8ecae1779070799a4.png)
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解题方法
8 . 某雕刻师在切割玉料时,切割出一块如图所示的三棱锥型边料,测得在此三棱锥
中,侧面
底面
,且
,该雕刻师计划将其打磨成一颗球形玉珠,则磨成的球形玉珠的直径的最大值为( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/891579e7c231584a8e16b8eeff79888e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a3d7090639341730951c1bc3c9b6164e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ca67a5b8f69507c8b80379e86f90a8ce.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/fe3faa82da218bcd6aaf987a4743954c.png)
A.![]() | B.![]() |
C.![]() | D.![]() |
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名校
9 . 已知函数
是
的导函数,则( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/fc9ca8d13fcffa6e9fb07efdd05e4a56.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/09f86f37ec8e15846bd731ab4fcdbacd.png)
A.“![]() ![]() |
B.“![]() ![]() |
C.若不等式![]() ![]() ![]() ![]() ![]() |
D.若![]() ![]() ![]() ![]() ![]() |
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10 . 某大型商场的所有饮料自动售卖机在一天中某种饮料的销售量
(单位:瓶)与天气温度
(单位:
)有很强的相关关系,为能及时给饮料自动售卖机添加该种饮料,该商场对天气温度
和饮料的销售量
进行了数据收集,得到下面的表格:
经分析,可以用
作为
关于
的经验回归方程.
(1)根据表中数据,求
关于
的经验回归方程(结果保留两位小数);
(2)若饮料自动售卖机在一天中不需添加饮料的记1分,需添加饮料的记2分,每台饮料自动售卖机在一天中需添加饮料的概率均为
,在商场的所有饮料自动售卖机中随机抽取3台,记总得分为随机变量
,求
的分布列与数学期望.
参考公式及数据:对于一组数据
,经验回归方程
的斜率和截距的最小二乘估计公式分别为
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d053b14c8588eee2acbbe44fc37a6886.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/81dea63b8ce3e51adf66cf7b9982a248.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/de96374212b9a5df820d78d10e7d1291.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/81dea63b8ce3e51adf66cf7b9982a248.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d053b14c8588eee2acbbe44fc37a6886.png)
![]() | 10 | 15 | 20 | 25 | 30 | 35 | 40 |
![]() | 4 | 16 | 64 | 256 | 2048 | 4096 | 8192 |
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e8029f44c190cd8ced93ed27ba0c18b6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d053b14c8588eee2acbbe44fc37a6886.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/81dea63b8ce3e51adf66cf7b9982a248.png)
(1)根据表中数据,求
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d053b14c8588eee2acbbe44fc37a6886.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/81dea63b8ce3e51adf66cf7b9982a248.png)
(2)若饮料自动售卖机在一天中不需添加饮料的记1分,需添加饮料的记2分,每台饮料自动售卖机在一天中需添加饮料的概率均为
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4dac452fbb5ef6dd653e7fbbef639484.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f022950e0faa45b617d497b01b5292b9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f022950e0faa45b617d497b01b5292b9.png)
参考公式及数据:对于一组数据
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/eafbe64ec9acf78f3624abbd06d516e6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1db6103cb0f1d2bd6b19235d53ee7e98.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/666e172502a39172a8379934128101f8.png)
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