解题方法
1 . 已知以
为左、右焦点的双曲线
的一条渐近线为
.点
是双曲线
上异于顶点的动点,若
是
的平分线上的一点,且
,则
的取值范围是_____________ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6f0b0da26aac472886b8345cfb9bf8ac.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c5db41a1f31d6baee7c69990811edb9f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d77f5191798242b7b9b88a75e17e4425.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dad2a36927223bd70f426ba06aea4b45.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c5db41a1f31d6baee7c69990811edb9f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ac047e91852b91af639feec23a9598b2.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c94fe48bf7af022ecbbe13833fdcc2c8.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ff8398a001fcf2bc80b13cce4ca1caa1.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4586226c7e189c5f55f6e9f61c474efb.png)
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解题方法
2 . “用一个不垂直于圆锥的轴的平面截圆锥,当圆锥的轴与截面所成的角不同时,可以得到不同的截口曲线”,利用这个原理,小强在家里用两个射灯(射出的光锥视为圆锥)在墙上投影出两个相同的椭圆(图1),光锥的一条母线恰好与墙面垂直.图2是一个射灯投影的直观图,圆锥
的轴截面
是等边三角形,椭圆
所在平面为
,则椭圆
的离心率为______________ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ef49a3ca580a144cc65a609c167facc1.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/745e0525a41fe2e2a7739c75a942290b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/23f919bd3dde10dbbc076f7ec5149699.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3f4b27f503ce08bc7851006a98f9ce32.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/23f919bd3dde10dbbc076f7ec5149699.png)
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解题方法
3 . 若任取正方体
的12条棱中的一条棱,则这条棱所在直线平行于平面
的概率为_____________ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6e09725691ee7851f54c0dee86b2bf55.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411b38a18046fea8e9fab1f9f9b80a5f.png)
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4 . 如图所示:在一个无限延展的平面上,铺满了边长为1的正方形网格,已知某质点从
出发,只能沿着网格线走,每次走一格,且每次向右走的概率为
,向上走的概率为
,向左走的概率为
,向下走的概率为
,且每一步之间相互独立.若要求质点按最短路径从
到达
,则可能的不同路径有__________ 条(用数字作答);设按最短路径从
到达
的概率记为
,则当
取得最大值的时候
的取值为__________ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5963abe8f421bd99a2aaa94831a951e9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/21198c85acf9672fafcfaa094de88342.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/40b29d292eaa8743e4f534d4c85e999c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/56d266a04f3dc7483eddbc26c5e487db.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/56d266a04f3dc7483eddbc26c5e487db.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5963abe8f421bd99a2aaa94831a951e9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7f9e8449aad35c5d840a3395ea86df6d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5963abe8f421bd99a2aaa94831a951e9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7f9e8449aad35c5d840a3395ea86df6d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/19a0be4eebc5d70c51f72f28dbfc11e9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/19a0be4eebc5d70c51f72f28dbfc11e9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b1010846eeec6c9da29640f5aa3f8738.png)
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5 . 化循环小数为分数:![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b1614b07a69a5c23ef6902a2770569c6.png)
___________
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b1614b07a69a5c23ef6902a2770569c6.png)
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解题方法
6 . 甲、乙、丙、丁四人相互做传球训练,第1次由甲将球传出,每次传球时,传球者都等可能地将球传给另外三个人中的任何一个人.则4次传球的不同方法总数为_________ (用数字作答);4次传球后球在甲手中的概率为_________ .
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解题方法
7 . 已知数列
是首项是1,公比为
的等比数列,数列
的通项公式是
.设双曲线
的离心率为
且
,则当![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0f3cb8d72bb2e281b943b3b430138ef7.png)
________ 时,
最大.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/63d471926f7b27322d90c82b9ce21d3d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7c22c96b4d06bc3172cbeb08f4e8c4d2.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5fce83115a50f99e08e9a2db7267aeed.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1eb9cfdb0458c13bd70d68248c9d8524.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/baeb2eb229c4a6a90cb1db2cfaf43177.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e8f567549e66b339299dbf8369ab5812.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/de43b581704cf3fbd2984340919672f3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0f3cb8d72bb2e281b943b3b430138ef7.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e8f567549e66b339299dbf8369ab5812.png)
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8 . 已知集合
,
,则![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b4b9b470218359a4a47be9244980489e.png)
________ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/54de2455dfd7028974f0b9254f9299a6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/09d0a7fab64bbd0b5c7b74b5d15157bd.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b4b9b470218359a4a47be9244980489e.png)
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9 . 已知
,当
时,则
的值是_______
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/eeb9f992de6398e5de944d14d246eef1.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/764eff906937f9b1fb58e5abfb2eb8a3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b7ccfc43be1d95f5a308ffbdfea60fd4.png)
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解题方法
10 . 已知集合
,
,任取
,则
为偶函数的概率为______ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/64fec0517a959cc0e672d9f8608f41e7.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4b897f7391c3892214c271f79734c25a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0940c99f26a7f7dee1d67624cd75cab9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/42d7af0e3a995decd0f500d2232247b2.png)
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