名校
1 . 已知双曲线
左右焦点分别为
,点
为右支上一动点,圆
与
的延长线、
的延长线和线段
都相切,则![](https://staticzujuan.xkw.com/quesimg/Upload/formula/24164ee062fd8c86ad35d50bb37c0090.png)
______ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3f06cddf90c2b1256b42462a270fd1e6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4d2a97987f71835f519b462f5b8f5957.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dad2a36927223bd70f426ba06aea4b45.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ac047e91852b91af639feec23a9598b2.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/da01a3abe1c9dc4e6283afa0dc1a0d39.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/643ef7d761de0e794fc39937dc72ac6a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c83e02c09428538ce8ae136cff26d3f2.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/24164ee062fd8c86ad35d50bb37c0090.png)
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解题方法
2 . 如图1,将三棱锥型礼盒
的打结点
解开,其平面展开图为矩形,如图2,其中A,B,C,D分别为矩形各边的中点,则在图1中( )
![](https://img.xkw.com/dksih/QBM/editorImg/2024/5/17/6b73349b-e32d-4caa-9721-9560b4356152.png?resizew=308)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/891579e7c231584a8e16b8eeff79888e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dad2a36927223bd70f426ba06aea4b45.png)
![](https://img.xkw.com/dksih/QBM/editorImg/2024/5/17/6b73349b-e32d-4caa-9721-9560b4356152.png?resizew=308)
A.![]() | B.![]() |
C.![]() ![]() | D.三棱锥![]() ![]() |
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名校
解题方法
3 . 已知正八边形
的边长为
,
是正八边形边上任意一点,则下列说法正确的是( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d17d4a6cf11cda87b3dfafaecdec683f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/61128ab996360a038e6e64d82fcba004.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dad2a36927223bd70f426ba06aea4b45.png)
A.![]() ![]() ![]() |
B.![]() |
C.若函数![]() ![]() ![]() |
D.![]() |
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解题方法
4 . 已知
中,
,
,若
在平面内一点
满足
,则
的最大值为_________
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15c0dbe3c080c4c4636c64803e5c1f76.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e65a3e478bb87d094e3a0af30dd10ae8.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e899c486dc49e560fc4aca05e16835b7.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15c0dbe3c080c4c4636c64803e5c1f76.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8455657dde27aabe6adb7b188e031c11.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4635725a969aef0f158ab8a8b7f72973.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3ab7ec2323e9b02cc027ffce2ce7714e.png)
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5 . 利用平面向量的坐标表示,可以把平面向量的概念推广为坐标为复数的“复向量”,即可将有序复数对
(其中
)视为一个向量,记作
,类比平面向量的相关运算法则,对于复向量
,我们有如下运算法则:
①![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9c2e1a17e5fc03e723da511f9b09e90c.png)
②
;
③![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e0822271cf00be40e775f82a7080afad.png)
④![](https://staticzujuan.xkw.com/quesimg/Upload/formula/fb467f8f90ba3c6ed8dcd5e9b385c5c0.png)
(1)设
,
为虚数单位,求
,
,
;
(2)设
是两个复向量,
①已知对于任意两个平面向量
,(其中
),
成立,证明:对于复向量
,
也成立;
②当
时,称复向量
与
平行.若复向量
与
平行(其中
为虚数单位,
),求复数
.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f1b39933abd56981a8bbcddf4b034df6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6227fc796e13ab80f2b5ccd4a8769588.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b2adcabafb9c785403537056956f8ad8.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/20bc37ab790b711f0c35a641b9bb4ae3.png)
①
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9c2e1a17e5fc03e723da511f9b09e90c.png)
②
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/09eeba4bb1dfe0975a02c38fcc1b49a3.png)
③
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e0822271cf00be40e775f82a7080afad.png)
④
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/fb467f8f90ba3c6ed8dcd5e9b385c5c0.png)
(1)设
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6a6650a5e44b601c5a50b348b6d179d6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3a7035cd4adda5d72a9fc9f9fda75995.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ebcb29b663cf1fb1ff2b3c9d1a7aebf5.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0631b4e25deaa9d9ba17dff5a3463605.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/58530dec593308e46ac5af69be13a2f7.png)
(2)设
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8bb379314dccab07cc53674173cde64d.png)
①已知对于任意两个平面向量
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/55e252e7c38b0a709ffe7c908677253b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/751f52d4cf239511828e3960e41c61df.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e255fd67f8f2318ebdb67c4a8c8496cd.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dbc8b1e5c55bce554fc4a0de48279a8b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/72659ca68087f1aa5d442637ed3c41ad.png)
②当
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ebd1c6734cf3d125541de04002b00012.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a2780422eefb9e85b89074a1ba2a159d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/433a8c622b44e1aa29e9989e6978dd7b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d77b3a6ecb6225c55fa164d801dff391.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/25c70d0dafec614d310400b919671739.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3a7035cd4adda5d72a9fc9f9fda75995.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3db22264e0df8e232e97934cb4e8b1ad.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/66e9585a1da28d403536ea48b4c37a3e.png)
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解题方法
6 . 已知中心在原点、焦点在x轴上的圆锥曲线E的离心率为2,过E的右焦点F作垂直于x轴的直线,该直线被E截得的弦长为6.
(1)求E的方程;
(2)若面积为3的
的三个顶点均在E上,边
过F,边
过原点,求直线
的方程:
(3)已知
,过点
的直线l与E在y轴的右侧交于不同的两点P,Q,l上是否存在点S满足
,且
?若存在,求点S的横坐标的取值范围,若不存在,请说明理由.
(1)求E的方程;
(2)若面积为3的
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15c0dbe3c080c4c4636c64803e5c1f76.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0dc5c9827dfd0be5a9c85962d6ccbfb1.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f52a58fbaf4fea03567e88a9f0f6e37e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0dc5c9827dfd0be5a9c85962d6ccbfb1.png)
(3)已知
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b2a29ba49963134a7232fa8574105fc3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d196dfa1217d0db795705c28eb988c1c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5f25d2d5078ac5925c12ddbbb57eb67d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a137073216d1de26f3923e08614306f9.png)
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2024-03-26更新
|
1137次组卷
|
2卷引用:福建省泉州市2024届高三质量监测(三)数学试题
名校
解题方法
7 . “费马点”是由十七世纪法国数学家费马提出并征解的一个问题.该问题是:“在一个三角形内求作一点,使其与此三角形的三个顶点的距离之和最小.”意大利数学家托里拆利给出了解答,当
的三个内角均小于
时,使得
的点
即为费马点;当
有一个内角大于或等于
时,最大内角的顶点为费马点.试用以上知识解决下面问题:已知
的内角
所对的边分别为
,
(1)若
,
①求
;
②若
,设点
为
的费马点,求
;
(2)若
,设点
为
的费马点,
,求实数
的最小值.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15c0dbe3c080c4c4636c64803e5c1f76.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a6c0927afc571a7c966c98192040979e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7e8036a881da6a4eef036529028a11d8.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1dde8112e8eb968fd042418dd632759e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15c0dbe3c080c4c4636c64803e5c1f76.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a6c0927afc571a7c966c98192040979e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15c0dbe3c080c4c4636c64803e5c1f76.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/24e0c10fb103930eabd5fa18e8f9bb06.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/76f0649064a085fb74c997fb507a9b6d.png)
(1)若
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2766e2c697dbefcef5f9fc0f43d7efed.png)
①求
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5963abe8f421bd99a2aaa94831a951e9.png)
②若
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/44ac38c5cc951497a4a37778b191bcce.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dad2a36927223bd70f426ba06aea4b45.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15c0dbe3c080c4c4636c64803e5c1f76.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3b8f8a1e38db0e55b9b1934569b24e74.png)
(2)若
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1aa1240d911a4276d86ea2ac218084c7.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dad2a36927223bd70f426ba06aea4b45.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15c0dbe3c080c4c4636c64803e5c1f76.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b01862dfc85d45102a1343c36cb6dfe5.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/36a1b09c653185842513e24ebba60bb3.png)
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2024-03-25更新
|
1342次组卷
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7卷引用:江苏省无锡市第一中学2023-2024学年高一下学期阶段性质量检测(3月月考)数学试题
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解题方法
8 . 若实数x,y满足
,则
的最大值为______
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a143573e9fe53e6a861154bf5b4c27c3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a3345715f6a5c7f80a4898d1745b01bb.png)
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|
1624次组卷
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5卷引用:安徽省芜湖市安徽师范大学附属中学2024届高三第二次模拟考试数学试题
安徽省芜湖市安徽师范大学附属中学2024届高三第二次模拟考试数学试题安徽省天域全国名校协作体2024届高三下学期联考(二模)数学试题江苏省无锡市锡东高级中学2024届高三下学期4月月考数学试题(已下线)安徽省天域全国名校协作体2024届高三下学期联考(二模)数学试题变式题11-15(已下线)压轴题06向量、复数压轴题16题型汇总-1
名校
解题方法
9 . 已知
,
分别是椭圆
的左、右焦点,如图,过
的直线与C交于点A,与y轴交于点B,
,
,设C的离心率为
,则( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f5076289823db419f94e9c0c8f4aafd9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a3fb78c5f885034612c0e030b920143d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/851a5d6ec23256f9b4a9e98aa92945fe.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a3fb78c5f885034612c0e030b920143d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e4efa339dbb8c7026b0959971349ae18.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/77fd6f15bd77332ca6defccf3ebd65c5.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/168b3e4b1d6f04226fa2687a72a268b4.png)
A.![]() | B.![]() |
C.![]() | D.![]() |
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2024-02-06更新
|
585次组卷
|
4卷引用:河南省信阳市固始县2023-2024学年高二上学期期末考试数学试卷
名校
解题方法
10 . 已知圆
,若曲线
上存在四个点
,过点
作圆
的两条切线,
为切点,满足
,则
的取值范围是( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/560adea7b0d4fbe4131fc41f3fcbd871.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/578b1203f764746e6c78587a5e1764a8.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/905fafa9e2152430fa6ece7825abaa73.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/59c709117ab1d3ef620883a732aed68b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1dde8112e8eb968fd042418dd632759e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/01c74a907dda6bb7d9d56d009d9df253.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d5e226c3eae258b571b6b868bd71e88b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f0a532e15e232cb4b99a8d4d07c89575.png)
A.![]() | B.![]() | C.![]() | D.![]() |
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