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解答题 | 一般(0.65) | 2021·全国高三专题练习
解题方法
3 . 已知函数eqIdb70bd9e59700443e865b1af8e413fecceqId41f04097a07d4d03941921a18fc42004).
(1)若当eqIdb5706584ddc64530b68e964587fe3b9a时,eqId6f13759e937144069819aed2ae5a1057的最大值为eqIdcf0e8924f6544d789d37564d497215a5,最小值为eqId5c1c12d4b3ba4aaab6267324ae66c81e,求实数ab的值
(2)若eqIdaff6b88cfefe462d93ea6d1d1e5047a0eqId24c04f97e1964d369aaf5c738513d5dc设函数eqId07284279754343dcaa3c895f2164eddf,且当eqId702d9e2080e24e6d990e83650abd7a76时,eqId71c65e830d184181b9a0e0a83280edf2恒成立,求实数m的取值范围.
解答题 | 较易(0.85) | 2021·全国高一课时练习
解题方法
同步
4 . 设向量eqIdbd5c117f6aa1430a9d05bca1e4a0148e,在eqId64b9b599fdb6481e9f8d9a94c102300b中,abc分别为角ABC的对边,且eqId71ed5dbd100c4f24835e9cc4896e50de.
(1)求角C
(2)若eqIda6002ac978ce41fbb28e656514038cc9,边长eqIdf33085e1bdfc4c56904f2a8a10432355,求eqId64b9b599fdb6481e9f8d9a94c102300b的周长l和面积S的值.
5 . 设eqId2efda802d5534f6d92d9f8af7aaec28b为坐标原点,定义非零向量eqId4126706d912b4533b4b7162b384abf44的“相伴函数”为eqIddaba3981507c4eed89c33a3a02277310,向量eqId4126706d912b4533b4b7162b384abf44称为函数eqId5cbcc06b2b6748c695d4aa404eddd8ec的“相伴向量”.记平面内所有向量的“相伴函数”构成的集合为eqId51d8a094ee99497ea839941c67407d85.
(1)设函数eqId432e11e94da74342b3552dd3e9fb95d2,求证:eqId3a419779b2d34df288f6999ed48b521c
(2)记eqIda159be535b1c4c91bfd67824bedd3199的“相伴函数”为eqId10852d81bc184140a7780250c82c6929,若函数eqId35516d49685b4ad397686746e6063e78eqIdcafc0fcddbbe41f2a19b236340c0e82b与直线eqIdea78f46f76b94267a3058a4185ca432d有且仅有四个不同的交点,求实数eqId4d2187284c5d4de29906363f7d21f60f的取值范围;
(3)已知点eqId38a73ac878314b8490313a1a5d5c6219满足eqIde41c99863cd9475680a679d80f883750,向量eqId868498ff9fa642879b7d44341bb0282c的“相伴函数”eqId10852d81bc184140a7780250c82c6929eqId02b4fd87b6dc469297673255c63eed1c处取得最大值.当点eqId2381423d4cd146cab95f55527681a766运动时,求eqId5d0340ec8e6a4ae88e067690b9e1b04b的取值范围.
解答题 | 一般(0.65) | 2021·丽水外国语实验学校高一月考
解题方法
6 . 如图,某公园内有两条道路eqId99a3187c2b8f4bcc9703c74c3b72f1f3eqId6dc069fc1fa74d889be09b5324e7e625,现计划在eqId6dc069fc1fa74d889be09b5324e7e625上选择一点eqId19a4eb16029e4550a14f2afe4741a3c3,新建道路eqId0627be51821d4be7b3e024a354815d64,并把eqId64b9b599fdb6481e9f8d9a94c102300b所在区域改造成绿化区域,已知eqId544ef11927bc45c6aadef590b0e16346
说明: figure
(1)若绿化区域eqId64b9b599fdb6481e9f8d9a94c102300b的面积为eqIdd6806596a3f348d1ad630a58219f85ee求道路eqId0627be51821d4be7b3e024a354815d64的长度;
(2)绿化区域eqId64b9b599fdb6481e9f8d9a94c102300beqIdb165b2b4e28e4edb87706d0df727fc1f的改造费用与新建道路eqId0627be51821d4be7b3e024a354815d64eqId35929d4751e2467cac0ed87f54460a45费用都是角eqId6c2ac5c036c74647a680198b592d7958的函数,其中绿化区域eqId64b9b599fdb6481e9f8d9a94c102300b改造费用为eqIdc6e363d294894b2291c7791e09466ea2万元eqIdb536aab15ad54b5fbd1e44c4f75f27b0,新建道路eqId0627be51821d4be7b3e024a354815d64改造费用为eqId315bb4d652fd437bbcdd2923afacf24d万元eqId856674ff8e9248debc30ba00002c7785,设eqIde05aa115aac045cb9952cf35e796732e某工程队承包了该公园的绿化区域改造与新道路修建.当eqId6c9518e43fd5459798a30cfc10026e3c为何值时,该工程队获得最高毛利润?
填空题 | 较易(0.85) | 2021·信阳市浉河区新时代学校
解题方法
7 . 一扇形的周长为4cm,面积为1cm2,则该扇形的圆心角为______
单选题 | 一般(0.65) | 2021·玉溪第二中学高二月考(文)
解题方法
同步
8 . eqId64b9b599fdb6481e9f8d9a94c102300b中,内角eqId10bbe48f886a4fa78fdf8c1fd064f9b4所对的边分别为eqId0ce93bfa1f6a4a23b3258410dd19847a.若eqId9a88155b016748ae9ec6b2af044f7fcaeqId77e1437821354362a90ac9e738e2d38aeqId64b9b599fdb6481e9f8d9a94c102300b的面积为(   )
A.eqId8898c1dc81824f3098bbeae74e8f11fdB.eqIdfed834edb3ac4e6fa7edb5d707fc810fC.eqIda35cf66775a24732b08dc411968e2420D.eqIdefe7549d43a142158aee9b47aa9a1354
更新:2021/09/10组卷:361引用[47]
9 . 已知点eqIdcf8541ee4ce34446bc56a5d6fbf933c3是函数eqIdd5165d5ff0dd4e7fbde4b3d9522bd443图像上的任意两点,且角eqId145940d03af4447eabd753d76abd2a1d的终边经过点eqIdc8f581097b3340f6b160055f67fea56d,若eqIdf0d379bed152412cbcfae4f69b3844f7时,eqIdbd159365b035491095ddb37b9dacf102的最小值为eqId236bfe74f1024849b3818a5cd741f299
(1)求函数eqIde4a0e3706b56447b90fe1b2781f91b14的解析式;
(2)求函数eqIde4a0e3706b56447b90fe1b2781f91b14eqIded0b5b64073f4533ac875546a67c7e3e上的单调递增区间;
(3)当eqId4dd6169d30654c8db8b33bba78dbb919时,不等式eqId6e16ac1116d745e68d07d711dd0dc264恒成立,求实数eqIda4be99d332154d13a4a6ed1ff6444fe7的取值范围.
双空题 | 困难(0.15) | 2021·江苏泰州中学高一期中
10 . 在eqId64b9b599fdb6481e9f8d9a94c102300b中,eqId312ef2c826304089b9b0f1d1e88b0f50eqId0627be51821d4be7b3e024a354815d64边上一点,且eqId3ccb1775087642a6879531380dd3a753eqId960f0f99f6754f369288c575595288b8,若eqId312ef2c826304089b9b0f1d1e88b0f50eqId0627be51821d4be7b3e024a354815d64的中点,则eqIdb1f040dae91243aaba3063bcdf46a416______;若eqId6af078f62a8b4799b1d63955b0c66766,则eqId19081cc6b1ee4c34b85e9245d585572d的面积的最大值为_________