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1 . 已知正方体
的棱长为2,点
为平面
上一动点,则( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6e09725691ee7851f54c0dee86b2bf55.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dad2a36927223bd70f426ba06aea4b45.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/82b724168afaee2ecddf97257180be18.png)
A.三棱锥![]() |
B.当点![]() ![]() ![]() ![]() |
C.当点![]() ![]() ![]() ![]() ![]() ![]() |
D.当点![]() ![]() ![]() |
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2 . 已知正四棱台的上、下底面边长分别为2和4,该正四棱台的体积为
时,侧棱与底面所成的角为____________ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/28e94c19f5d462cbecde3eb31a34c538.png)
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3 . 如图,在棱长为2的正方体
中,截去三棱锥
,求
的表面积;
(2)剩余的几何体
的体积;
(3)在剩余的几何体
中连接
,求四棱锥
的体积.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6e09725691ee7851f54c0dee86b2bf55.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/cb650f48c879ea25127662b47d16feec.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/cb650f48c879ea25127662b47d16feec.png)
(2)剩余的几何体
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e2ab532ff01877b7730ec377f2045d5c.png)
(3)在剩余的几何体
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e2ab532ff01877b7730ec377f2045d5c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8cfbc0b5a8fbde804bd8425a4b76d207.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/bfd1041bb4d3bc7a3a74860c44320d07.png)
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7日内更新
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453次组卷
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2卷引用:云南省昆明市第一中学2023-2024学年高一下学期期中考试数学试卷
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解题方法
4 . 已知圆锥的侧面展开图是圆心角为
的扇形,母线长为3.
(2)在该圆锥内按如图所示放置一个圆柱,当圆柱的侧面积最大时,求圆柱的体积.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/67fb457e8ac0d3ac35e1c668ea138f91.png)
(2)在该圆锥内按如图所示放置一个圆柱,当圆柱的侧面积最大时,求圆柱的体积.
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5 . 如图,在长方体
中,
,
,M,N分别为
,
的中点,则三棱锥
的体积为_______ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6e09725691ee7851f54c0dee86b2bf55.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/27db558e8db4c957654c8e5cecd2d2dc.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e55a2310cbba5e050488cd9296eb195d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f52a58fbaf4fea03567e88a9f0f6e37e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9d88bf46ad08f9677c37eed1d0369329.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/fbbb6e880775a36ca70c5edb0f488f80.png)
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6 . 现有一个底面圆半径为3的圆柱型的盒子,小明现在找到一些半径为3的小球,往盒子中不断地放入小球,若此盒子最多只能装下6个这样的小球(盒子的盖子能封上),那么圆柱盒子的容积与一个小球的体积的比值范围为____________ .
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7 . 如图,已知菱形
中,
,
,
为边
的中点,将
沿
翻折成
(点
位于平面
上方),连接
和
,F为
的中点,则在翻折过程中,下列说法正确的是( )
![](https://img.xkw.com/dksih/QBM/editorImg/2024/6/12/0ae8f927-1aee-43ba-8f08-58e26bc8f952.png?resizew=181)
①平面
平面
;②
与
的夹角为定值
;
③三棱锥
体积最大值为
;④点
的轨迹的长度为
.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411b38a18046fea8e9fab1f9f9b80a5f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/fcd0ced286a0fbc7e4862f8147264277.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9eee296a7d9fba487f1485c61580196f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2a30f3a8b673cc28bd90c50cf1a35281.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0dc5c9827dfd0be5a9c85962d6ccbfb1.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e742966e3711cfa53dce04022acf4bcc.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/68a83fdd2ba72a2dba0b6b10bb3e06b9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/adeda53be579292e60e6d775cab6fd28.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/97c01fdc7bc471af0b264a04aef0823e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411b38a18046fea8e9fab1f9f9b80a5f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d7f6f93171329d508d491143b9d71f7b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/87cdc08e1c4a04a18d5ecea03393e36d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/87cdc08e1c4a04a18d5ecea03393e36d.png)
![](https://img.xkw.com/dksih/QBM/editorImg/2024/6/12/0ae8f927-1aee-43ba-8f08-58e26bc8f952.png?resizew=181)
①平面
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8cf7f0ae8f28b32a520d91230a64f7cb.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3ef676509065322bfc244e59607bb60d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b470c4e195cf7a07b7a331ce4b436e03.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4cae70b8a9d2d2e96dea62c00ced04b9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ac1a63ab608517bb10aa036783dfb51f.png)
③三棱锥
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d4d394c7dcf2d8f4ccf735a3ef46bc50.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/18483c9c195ecd922772527fa85c0fcb.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a0ed1ec316bc54c37c4286c208f55667.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d49f8a63ddbca52039fa9ab44cda6b29.png)
A.①② | B.①③ | C.①②④ | D.②③④ |
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解题方法
8 . 如图,四棱锥
,侧面PAD是边长为2的正三角形且与底面垂直,底面ABCD是
的菱形,
为棱PC上的动点且
.
为直角三角形;
(2)试确定
的值,使得三棱锥
的体积为
.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0585b6c0f156eecf9662b9846d4eb693.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/26d4e574c9d139615d991a168cfbf63b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ac047e91852b91af639feec23a9598b2.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d9b88889903cd3a5708271cf0609615d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1c025ee3317be1099b7bf03a11e37ed4.png)
(2)试确定
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/df64046e91b047037f19e4032e3b6de3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d897eb3e5cd5e639380bf9bdafcaec88.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/bf31876698721a199c7c53c6b320aa86.png)
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2024-06-12更新
|
74次组卷
|
2卷引用:福建省安溪铭选中学2023-2024学年高一下学期6月份质量检测数学试题
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解题方法
9 . 如图,
平面
,
,
,
,
,
为
中点.
∥平面
;
(2)求三棱锥
的体积;
(3)求点
到平面
的距离.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9f4c3f9dd5d0343597a7f58a1989b537.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411b38a18046fea8e9fab1f9f9b80a5f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4adf90a8c2b29334cdc5aa5b554991f9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9060f03b9ee41d70d135b1e1a8902ce9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d262480ffb55b7617f44b63f130c154a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/88dac2c17c765517c2163ab43bbe1038.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a0ed1ec316bc54c37c4286c208f55667.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4eedae8d316c76e3d0b451256de03fb9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d004d2d115b477ade6af7ddb93db0df8.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/62871bb0dff211fc3bd80f9066c25b29.png)
(2)求三棱锥
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/fc9906ec3e92ecdefb55d5b1d99a928e.png)
(3)求点
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c5db41a1f31d6baee7c69990811edb9f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/34be4e71cabf458f17a6cd7f24bc70af.png)
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10 . 灯笼起源于中国的西汉时期,两千多年来,每逢春节人们便会挂起象征美好团圆意义的红灯笼,营造一种喜庆的氛围.如图1,某球形灯笼的轮廓由三部分组成,上下两部分是两个相同的圆柱的侧面,中间是球面的一部分(除去两个球缺).如图2,“球缺”是指一个球被平面所截后剩下的部分,截得的圆面叫做球缺的底,垂直于截面的直径被截得的一段叫做球缺的高.已知球缺的体积公式为
,其中
是球的半径,
是球缺的高.已知该灯笼的高为40cm,圆柱的高为4 cm,圆柱的底面圆直径为24 cm,则该灯笼的体积为(取
)( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d752ac0180ffc7ba53d1aee0286c7948.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4aa0df7f1e45f9de29e802c7f19a4f64.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3eabd5f3a86afe49dcd70571e2b96cfd.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4eb526a84a615236dc9484c873295eb8.png)
A.![]() | B.33664 cm3 | C.33792 cm3 | D.35456 cm3 |
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2024-06-11更新
|
956次组卷
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5卷引用:广东省深圳市深圳大学附属中学、龙城高级中学第二次段考2023-2024学年高一下学期5月月考数学试题