名校
解题方法
1 . 已知菱形
的边长为2,
.将
沿着对角线
折起至
,连结
.设二面角
的大小为
,则下列说法正确的是( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5cb3f9a5da641be35117fd35ba07a6aa.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e27c034ff5ef70e5d48c0a6b83e48024.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/684c3c84da636f306191b50caf33f0f5.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e1a9c6a736e6eac98a676fa3232db5a5.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c1d9e6cb0c83b99d3a2fa38deae7cf80.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/32838e506490ef1a8969fa9ecf98fbe2.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/74d1179a0fe882b0c390ee9c4e2d35ee.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c24095e409b025db711f14be783a406c.png)
A.若四面体![]() ![]() |
B.四面体![]() |
C.四面体![]() |
D.当![]() ![]() ![]() |
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解题方法
2 . 端午节吃粽子,用箬竹叶包裹而成的三角粽是上海地区常见的一种粽子,假设其形状是一个正四面体,如图记作正四面体A-BCD,设棱长为a.![](https://staticzujuan.xkw.com/quesimg/Upload/formula/76d72a007e3c4a134956b0e3fbde5f46.png)
(2)求箬竹叶折出的二面角
的大小;
(3)用绳子捆扎三角粽,要求绳子经过正四面体的每一个面、不经过顶点,并且绳子的起点和终点重合.请设计一种捆扎三角粽的方案,使绳子长度最短(不计打结用的绳子),请在图中作出绳子捆扎的路径,并说明理由.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/76d72a007e3c4a134956b0e3fbde5f46.png)
(2)求箬竹叶折出的二面角
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5ec2524be492bca0d1566bf848066f10.png)
(3)用绳子捆扎三角粽,要求绳子经过正四面体的每一个面、不经过顶点,并且绳子的起点和终点重合.请设计一种捆扎三角粽的方案,使绳子长度最短(不计打结用的绳子),请在图中作出绳子捆扎的路径,并说明理由.
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3 . 如图,在四棱锥
中,底面
为正方形,侧面
底面
,且
.
平面
;
(2)求三棱锥
的体积;
(3)求二面角的
正切值.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0585b6c0f156eecf9662b9846d4eb693.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411b38a18046fea8e9fab1f9f9b80a5f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/93edc7bb513f40a89173121c8570cd65.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411b38a18046fea8e9fab1f9f9b80a5f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e7157fb6bcd229e82079a471898ab438.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7d0edb1508fc95765f3bb316bcb5252d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/80f747eb5b2d21c9de962cbfd4ec4bb7.png)
(2)求三棱锥
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/041434f0c90fb3cdd685b8eb1c2b4b26.png)
(3)求二面角的
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/70682f6196e6c1a08eb48da73e8919ca.png)
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4 . 如图,多面体
由正四棱锥
和正四面体
组合而成,其中
,则( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1c05efb2f567bee7d101438e86f8d3a2.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0585b6c0f156eecf9662b9846d4eb693.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/50e4e31ae381d5ceb847fcbd4c54a314.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/de13b10c940fe4cad7642a11db2e705d.png)
A.该几何体的表面积为![]() |
B.该几何体为七面体 |
C.二面角![]() ![]() |
D.存在球![]() |
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5 . 如图,该多面体的表面由18个全等的正方形和8个全等的正三角形构成,该多面体的所有顶点都在同一个正方体的表面上.若
,则( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/056c2272e0d10d6dd9706e6324d8e62d.png)
A.![]() | B.该多面体外接球的表面积为![]() |
C.直线MG与直线PQ的夹角为![]() | D.二面角![]() ![]() |
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2024-06-16更新
|
262次组卷
|
5卷引用:湖南省娄底市第三中学2023-2024学年高二下学期5月月考数学试题
名校
6 . 如图,四棱锥
中,平面
平面
,
,
,
,
,
,
,
.设
中点为
,过点
的平面
同时垂直于平面
与平面
.
与平面
夹角的正弦值;
(2)求平面
截四棱锥
所得多边形的周长.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a8e7cedc39297d66dbb177f2a1f6bee2.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a3d7090639341730951c1bc3c9b6164e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/65c42bce098904b241986bb91c65ab33.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/047dc9795efa99b6fb9fdf9778085dab.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e2d212c1709b8e72a055cf1b5381ef64.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b53df2a88f461611f7159d0f2f8ef60e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/421291381be28da4bd16560fd383b4a9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/663f139d687116cba2d3badfbfb987cb.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9b972027fef607dc50001a3895442a32.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6ea03a10b5bbd8e745ecce6f3e598375.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0dc5c9827dfd0be5a9c85962d6ccbfb1.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/73465a1f9aa03481295bf6bd3c6903ac.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/73465a1f9aa03481295bf6bd3c6903ac.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e170f206fdbbd834aad7580c727e2cc6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3ecfe1bf6f7bfe17f9bd28e97b0147f6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/383ec3453527947ed7a5960e9a8fbe0b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e170f206fdbbd834aad7580c727e2cc6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/65c42bce098904b241986bb91c65ab33.png)
(2)求平面
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e170f206fdbbd834aad7580c727e2cc6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a8e7cedc39297d66dbb177f2a1f6bee2.png)
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解题方法
7 . 如图,四棱锥
的底面是正方形,每条侧棱的长都是底面边长的
倍,
平面
,
为侧棱
上的点,则二面角
的余弦值为( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/faeb97acf19bd3b2c6c77c2814df4d2f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/cf298f00799cbf34b4db26f5f63af92f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5fb2e071d4e01107dcf7d95cbb86b415.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0628681907ac8d7fdb94d8bc1b15feb9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dad2a36927223bd70f426ba06aea4b45.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/defa5b53043ae802bb1af7d14374406d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/bf29d07c3751c41ab3503065a5a5052e.png)
A.![]() | B.![]() | C.![]() | D.![]() |
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8 . 在如图所示的直三棱柱
中,
分别是线段
上的动点.
平面
,求
的值;
(2)若三棱柱是正三棱柱,
是
的中点,求二面角
余弦值的最小值.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/42d3a82b8e587ee890467835bc4e854c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2864ced1084cb88df6839a2852eda760.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4ddef39ef9ed3da136c4ed8b5d28b73e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b78172568aac9805d2ea2d5f742bf80c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/118817feb9aa44bfd97b921068d6d92e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4d572696eb3a79147a1bbcd75ddda858.png)
(2)若三棱柱是正三棱柱,
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8455657dde27aabe6adb7b188e031c11.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0dc5c9827dfd0be5a9c85962d6ccbfb1.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a879800a059ce741a99bb2c171f32afe.png)
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解题方法
9 . 已知正方体
的棱长为1,点
,
分别为
,
的中点,则下列说法正确的是( )
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6e09725691ee7851f54c0dee86b2bf55.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2a30f3a8b673cc28bd90c50cf1a35281.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a0ed1ec316bc54c37c4286c208f55667.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e0a851907ada2ac2c3c4880a6736d28a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9d78abbad68bbbf12af10cd40ef4c353.png)
A.![]() ![]() |
B.![]() ![]() ![]() |
C.二面角![]() ![]() |
D.点![]() ![]() ![]() |
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10 . 在《九章算术》中,将底面为长方形且有一条侧棱与底面垂直的四棱锥称为“阳马”.如图,在“阳马”
中,侧棱
底面
,且
.
,试计算底面
面积的最大值;
(2)过棱
的中点
作
,交
于点
,连
,若平面
与平面
所成锐二面角的大小为
,
(i)证明:
平面
(ii)试求
的值.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0585b6c0f156eecf9662b9846d4eb693.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5a1b49f64e0065edad868b25e9fcada3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411b38a18046fea8e9fab1f9f9b80a5f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/37e2267c84394668eff2e9f5918de4fb.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/89b336e518ac4ff04c6c26e4b8a15844.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411b38a18046fea8e9fab1f9f9b80a5f.png)
(2)过棱
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/48f3c9abbd78e9a6840ee5f30381daac.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2a30f3a8b673cc28bd90c50cf1a35281.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9a4a6a1e70241d600bc6c104313eac61.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d2be49c37e30a3ced0364c3e74d8c687.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a0ed1ec316bc54c37c4286c208f55667.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c976ef3847a109d7b7228fbfe935cc15.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/134ef0b1a2669a09f05bd4dc2496f706.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411b38a18046fea8e9fab1f9f9b80a5f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ac1a63ab608517bb10aa036783dfb51f.png)
(i)证明:
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c45fbffb9e2c7fa7c5006cde8da0cabe.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/128ad2638f3f027b4e2033b116550253.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/54625f5af5647c5dad88675510c4711b.png)
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