2024高三·全国·专题练习
解题方法
1 . 一山坡的倾斜度(山坡面与水平面所成二面角的度数)是
,斜坡上一直道
,它和坡脚
成
,为解决山腰
处居民的饮水问题,有甲、乙两种方案.
方案甲:一次性投资12万元打深水井,取用与坡脚水平的暗河中的水(经检验符合饮用水标准);
方案乙:沿
铺设自来水管道,第一个
费用为1万元,以后每往上一个
所需费用比前一个
的费用扩大1倍;
如果
处高出暗河
,那么选用哪个方案比较合理?请你说明理由.(不考虑其他因素)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f6b86c22b670a8e9f3896f9e8883fbbb.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9d78abbad68bbbf12af10cd40ef4c353.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f52a58fbaf4fea03567e88a9f0f6e37e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/be6a6301878fed2a01413020b27310a5.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8455657dde27aabe6adb7b188e031c11.png)
方案甲:一次性投资12万元打深水井,取用与坡脚水平的暗河中的水(经检验符合饮用水标准);
方案乙:沿
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9d78abbad68bbbf12af10cd40ef4c353.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f631cfdf4666db95beb923072ced8d95.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f631cfdf4666db95beb923072ced8d95.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f631cfdf4666db95beb923072ced8d95.png)
如果
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8455657dde27aabe6adb7b188e031c11.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/323ad601828689aeea3d3d52404b3cab.png)
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2024高三·全国·专题练习
解题方法
2 . 现有
四个长方体容器,容器
和
的底面积均为
,高分别为
和
;容器
和
的底面积均为
,高分别为
和
.现规定一种游戏规则,每人一次从四个容器中取出两个,盛水多者为胜,问先取者是否有必胜的方案,为什么?
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0c82a10b4f0c9323d726804c89dd9548.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5963abe8f421bd99a2aaa94831a951e9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7f9e8449aad35c5d840a3395ea86df6d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c8cc0b4997cae4d8aec791a1d3923314.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0a6936d370d6a238a608ca56f87198de.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2c94bb12cee76221e13f9ef955b0aab1.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c5db41a1f31d6baee7c69990811edb9f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8455657dde27aabe6adb7b188e031c11.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a881309775c3b6a9f4ed408838666342.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0a6936d370d6a238a608ca56f87198de.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b25888f51725d923283a311438d68194.png)
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3 . 兴隆塔,建于隋朝,位于区博物馆内.某校开展数学建模活动,有建模课题组的学生选择测量兴隆塔的高度,为此,他们设计了测量方案.如图,兴隆塔垂直于水平面,他们选择了与兴隆塔底部
在同一水平面上的
两点,测得
米,在
两点观察塔顶
点,仰角分别为
和
,其中
,
,
的长;
(2)在(1)的条件下求多面体
的表面积;
(3)在(1)的条件下求多面体
的内切球的半径;
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8455657dde27aabe6adb7b188e031c11.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/01c74a907dda6bb7d9d56d009d9df253.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/137335385add246ec8aed081da03679c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/01c74a907dda6bb7d9d56d009d9df253.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c5db41a1f31d6baee7c69990811edb9f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/79a97bb4dcfab4ec7539bc783d563c49.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e170f206fdbbd834aad7580c727e2cc6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/52f7daaafe649f5fad149391b5992f7d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b6b0c6766bd801fa114221d0ab0bfa61.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9d78abbad68bbbf12af10cd40ef4c353.png)
(2)在(1)的条件下求多面体
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/891579e7c231584a8e16b8eeff79888e.png)
(3)在(1)的条件下求多面体
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/891579e7c231584a8e16b8eeff79888e.png)
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解题方法
4 . 数学课上,老师出示了以下习题:已知圆柱内接于半径为3的球
,求圆柱体积
的最大值.为了求出圆柱体积
的最大值,小明和小亮两位同学分别给出了如下两种方案:
(1)小明的方案:设圆柱的高为
,请你帮他写出体积
与
之间的函数关系式,并求出圆柱体积的最大值;
(2)小亮的方案:取圆柱底面圆
上一点
,连接
,
,设
,请你帮他写出体积
与
之间的函数关系式,并求出圆柱体积的最大值.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1dde8112e8eb968fd042418dd632759e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/be54e84508decfcce6d2fcbe6c8c1a92.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/be54e84508decfcce6d2fcbe6c8c1a92.png)
(1)小明的方案:设圆柱的高为
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/81dea63b8ce3e51adf66cf7b9982a248.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/be54e84508decfcce6d2fcbe6c8c1a92.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/81dea63b8ce3e51adf66cf7b9982a248.png)
(2)小亮的方案:取圆柱底面圆
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/12fe32dfbd66709875c5b9f79c9496da.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dad2a36927223bd70f426ba06aea4b45.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ef49a3ca580a144cc65a609c167facc1.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f78322f1db1b2e332225b9db53b9c54a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3c2b16d0606a8f07d62da5b3fcf55a03.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/be54e84508decfcce6d2fcbe6c8c1a92.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c24095e409b025db711f14be783a406c.png)
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名校
5 . 等腰梯形
中,
,
,
.若点
、
均在
上,且
.如图(一)所示,沿
将
折起,沿
将
折起,使
、
两点重合为
.
(1)若
,如图(二)所示,求证:平面
平面
;
(2)若
,
为
中点,当
与
重合于
时,如图(三)所示,求
与平面
所成角的余弦值;
(3)请设计一个翻折方案使四棱锥
的外接球半径为
,证明你的结论,并求此方案下的
的长度及
的大小.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411b38a18046fea8e9fab1f9f9b80a5f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8a11029ca6b4b9e7f777af0280cf163c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b040eb31b0b7073ad3ffa8bd7968d187.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/037b342a682cbd4241855a243da3c016.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2a30f3a8b673cc28bd90c50cf1a35281.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a0ed1ec316bc54c37c4286c208f55667.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f52a58fbaf4fea03567e88a9f0f6e37e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/04f8eebda19eded2b059774a8c2666c3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e6e490f703eb6c9bb1278c78ebc2d661.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a25c28359f8d8da9eaf4672a6cf8ae4f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4cae70b8a9d2d2e96dea62c00ced04b9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6830ebecddbd9759be626289c408e4f3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5963abe8f421bd99a2aaa94831a951e9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7f9e8449aad35c5d840a3395ea86df6d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/cf231f8f86fb922df4ca0c87f044cec3.png)
![](https://img.xkw.com/dksih/QBM/editorImg/2023/7/27/ba897f14-f9d7-44dc-b819-8c1cfd0adc02.png?resizew=459)
(1)若
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/27aa17bad024a9361bd0a679e10f70ac.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c6bec37dca00db5f4512ce70f16ceb20.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3747e528a1e8d45668ccf835c0175a73.png)
(2)若
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3f4aca5534bce25acaeb7379deed8f8f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1dde8112e8eb968fd042418dd632759e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f52a58fbaf4fea03567e88a9f0f6e37e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2a30f3a8b673cc28bd90c50cf1a35281.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a0ed1ec316bc54c37c4286c208f55667.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1dde8112e8eb968fd042418dd632759e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/18e5ef91fb27dd684a27ae7f1993cfba.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9ef796b46e68fe77b117ff0483d2370c.png)
(3)请设计一个翻折方案使四棱锥
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8ff027309f3108559e6b3915158a3867.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8d5989c84e320b504511f23eeb6e7357.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/03902478df1a55bc99703210bccab910.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2b3b0b11a80e8b107e55534d7fda9f2b.png)
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6 . 小波到一个广告公司去应聘包装设计师职位,考官给大家出了一道题目:某礼品厂生产一种棱长为a的正四面体形状的礼品(如图).请你为它设计一个包装盒,形状随意,可提出不同方案供考官选择(不考虑包装盒材料的质量、厚度、重量及接缝处损耗)
(1)小波给出了长方体和圆柱两个设计方案(如图),请分别计算这两个包装盒的表面积;
(2)考虑到礼品各面易碎,礼品较大,包装盒体积不能太大,但礼品各面与包装盒表面之间需要有填充物,请你帮小波设计一个方案.(需要面图表示,并配以简单说明理由)
![](https://img.xkw.com/dksih/QBM/editorImg/2023/8/3/50abad76-17cf-439e-8f5a-0e1247a0c6b6.png?resizew=392)
(1)小波给出了长方体和圆柱两个设计方案(如图),请分别计算这两个包装盒的表面积;
(2)考虑到礼品各面易碎,礼品较大,包装盒体积不能太大,但礼品各面与包装盒表面之间需要有填充物,请你帮小波设计一个方案.(需要面图表示,并配以简单说明理由)
您最近一年使用:0次
名校
解题方法
7 . 如图所示,一个仓库设计由上部屋顶和下部主体两部分组成,屋顶的形状是四棱锥
,四边形
是正方形,点
为正方形
的中心,
平面
;下部的形状是长方体
.已知上部屋顶造价与屋顶面积成正比,比例系数为
,下部主体造价与高度成正比,比例系数为
.现欲建造一个上、下总高度为12 m,
m的仓库.
![](https://img.xkw.com/dksih/QBM/editorImg/2023/1/18/db3d6302-b269-46f8-a273-d4cf4d96cced.png?resizew=175)
(1)①若屋顶的高
,请将总造价表示为x的函数;
②若屋顶侧面与底面所成二面角角为
,请将总造价表示为
的函数;
(2)选择(1)中的一个方案,求出总造价的最小值.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0585b6c0f156eecf9662b9846d4eb693.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411b38a18046fea8e9fab1f9f9b80a5f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1dde8112e8eb968fd042418dd632759e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411b38a18046fea8e9fab1f9f9b80a5f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f3e126c16032892966489053f44b9048.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411b38a18046fea8e9fab1f9f9b80a5f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6e09725691ee7851f54c0dee86b2bf55.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/893d4e8d70ea2c716ac7b6c1777a77f2.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1bf8ed39e78ace72ea02b2106117d92e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/305a88d4e0249bd16d48eda01331d2d4.png)
![](https://img.xkw.com/dksih/QBM/editorImg/2023/1/18/db3d6302-b269-46f8-a273-d4cf4d96cced.png?resizew=175)
(1)①若屋顶的高
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b5b2822632a493ac9d197d11a12df512.png)
②若屋顶侧面与底面所成二面角角为
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c24095e409b025db711f14be783a406c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c24095e409b025db711f14be783a406c.png)
(2)选择(1)中的一个方案,求出总造价的最小值.
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解题方法
8 . 某部门建造了一个圆锥形仓库用于贮藏食盐(供融化高速公路上的积雪之用),已建的仓库的底面直径为12m,高为4m,该部门计划再建一个更大的圆锥形仓库,以存放更多食盐.现有两种方案:方案一是新建的圆锥形仓库的底面直径比原来增加4m(高不变);方案二是新建的圆锥形仓库的高度增加4m(底面直径不变).
(1)分别计算按这两种方案所新建的圆锥形仓库的体积;
(2)分别计算按这两种方案所新建的圆锥形仓库的侧面积;
(3)哪个方案更经济些?为什么?
(1)分别计算按这两种方案所新建的圆锥形仓库的体积;
(2)分别计算按这两种方案所新建的圆锥形仓库的侧面积;
(3)哪个方案更经济些?为什么?
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9 . 如图,在三棱柱
中,四边形
是边长为4的正方形.再从条件①、条件②、条件③中选择两个能解决下面问题的条件作为已知.
![](https://img.xkw.com/dksih/QBM/editorImg/2022/12/11/7a1b2aa1-233b-4777-8cff-97dbc11c5f37.png?resizew=169)
(1)求证:
平面
;
(2)求直线
与平面
所成角的正弦值;
(3)设
是
的中点,棱
上是否存在点
,使得![](https://staticzujuan.xkw.com/quesimg/Upload/formula/67c015d99f2677951bdcd0447240ef93.png)
平面
?若存在,求线段
的长;若不存在,说明理由.
条件①:
;
条件②:
;
条件③:平面
平面
.
注:如果选择多种方案分别解答,那么按第一种方案解答计分.
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/42d3a82b8e587ee890467835bc4e854c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6ac61c24f99a4e466f1e2ea011893866.png)
![](https://img.xkw.com/dksih/QBM/editorImg/2022/12/11/7a1b2aa1-233b-4777-8cff-97dbc11c5f37.png?resizew=169)
(1)求证:
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/21f9157fce2a8339d281178c7c0bccbe.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6ac61c24f99a4e466f1e2ea011893866.png)
(2)求直线
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0d8772aa893a9c1d40f714cb25701701.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9afac7c616bbb14e1ed428a3c507c7dc.png)
(3)设
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ac047e91852b91af639feec23a9598b2.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0f1f229274a6e17977cc047814212589.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e0a851907ada2ac2c3c4880a6736d28a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/895dc3dc3a6606ff487a4c4863e18509.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/67c015d99f2677951bdcd0447240ef93.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/638537c0a30676c73fea76c80e0f8bd0.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9afac7c616bbb14e1ed428a3c507c7dc.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/06e322e0c87479bba874db9ae9ba36b5.png)
条件①:
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/02273296ef80813f45933d31a833f160.png)
条件②:
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ff4fcf607b0710d12aaabd17fd053d83.png)
条件③:平面
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a3d7090639341730951c1bc3c9b6164e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6ac61c24f99a4e466f1e2ea011893866.png)
注:如果选择多种方案分别解答,那么按第一种方案解答计分.
您最近一年使用:0次
2022-12-10更新
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535次组卷
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5卷引用:北京市对外经济贸易大学附属中学2023届高三上学期12月月考期末综合测试(一)数学试题
北京市对外经济贸易大学附属中学2023届高三上学期12月月考期末综合测试(一)数学试题北京市日坛中学2023届高三上学期12月月考数学试题(已下线)北京市西城区2022届高三二模数学试题变式题16-21北京市陈经纶中学2023-2024学年高二上学期期中考试数学试卷(已下线)黄金卷04
名校
10 . 如图,在四棱柱
中,侧棱
底面
,
,
,
,
,
,![](https://staticzujuan.xkw.com/quesimg/Upload/formula/223036d27be5914db50fbd5cb19d4212.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b377f632949bff36083a5464113387fe.png)
![](https://img.xkw.com/dksih/QBM/editorImg/2023/3/27/41df7655-23a4-44d1-b7cc-5b525ad38bcd.png?resizew=193)
(1)求证:
平面![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5ebb05874eb3353d754af24c9974273e.png)
(2)若直线
与平面
所成角的正弦值为
,求
的值
(3)现将与四棱柱
形状和大小完全相同的两个四棱柱拼成一个新的四棱柱,规定:若拼成的新四棱柱形状和大小完全相同,则视为同一种拼接方案,问共有几种不同的拼接方案?在这些拼接成的新四棱柱中,记其中最小的表面积为
,写出
的解析式.(直接写出答案,不必说明理由).
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6e09725691ee7851f54c0dee86b2bf55.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5845ccc0d735dc14c92a8926d9b1def6.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/411b38a18046fea8e9fab1f9f9b80a5f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/68d31600cba2d5256c7e78b6122d6755.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ad1a56baf43ffdf67bc8460856e31fec.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0b9740124a284f336f20c98695af04ac.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ca5cab760038d20eac10fe6108fbb334.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8f991c5086ba855802b0331c4e02e3f4.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/223036d27be5914db50fbd5cb19d4212.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b377f632949bff36083a5464113387fe.png)
![](https://img.xkw.com/dksih/QBM/editorImg/2023/3/27/41df7655-23a4-44d1-b7cc-5b525ad38bcd.png?resizew=193)
(1)求证:
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/97f30533da2e1d2a958dc906c37eba9d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/5ebb05874eb3353d754af24c9974273e.png)
(2)若直线
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/e0a851907ada2ac2c3c4880a6736d28a.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a211ad5a06b505b8365a62c1946f3cb7.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/8a4e6eb3663870ed202cc208eaf239dc.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f0a532e15e232cb4b99a8d4d07c89575.png)
(3)现将与四棱柱
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6e09725691ee7851f54c0dee86b2bf55.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a0e6cb8d4e39fa44f71df04b74f123f4.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/a0e6cb8d4e39fa44f71df04b74f123f4.png)
您最近一年使用:0次