解题方法
1 . 已知实数
为函数
的零点,
为函数
的零点,则![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1f947d030c265753e4201ae4d9c69e99.png)
________ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c814128ea2139e33db94ea590e7c2223.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0576a0520249b48fd302a0d47317678f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/aec19b68e3add9d5bfcc6269a1855b87.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/34516f09a665374834b1b165e1a43b4f.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/1f947d030c265753e4201ae4d9c69e99.png)
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2 . 乒乓球(table tennis),被称为中国的“国球”,是一种世界流行的球类体育项目.已知某次乒乓球比赛单局赛制为:两球换发制,每人发两个球,然后由对方发球,先得11分者获胜,若单局比赛中,甲发球时获胜的概率为
,甲接球时获胜的概率为
,甲先发球,则单局比赛中甲
获胜的概率为______ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/bf31876698721a199c7c53c6b320aa86.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f89eef3148f2d4d09379767b4af69132.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7e3407dcd0e695d2f6e1cfac0a99c4f7.png)
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3 . 存在过点
的直线与曲线
相切,则实数
的取值范围是______ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/d3b119d0cf10a948cdc53c1066af0b8b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6454a912d65423ed04506f1d791d866e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/36a1b09c653185842513e24ebba60bb3.png)
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解题方法
4 . 已知点
,则线段
的垂直平分线的一般式方程为__________ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/bfcef50cabebb11afc0ea70791ad23a8.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f52a58fbaf4fea03567e88a9f0f6e37e.png)
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5 . 直线
被曲线
所截得的弦长为
,则实数
的值为__________ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/07565f10847840e0fb07b05218ad17fa.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/aafae84e7fe39dc5b694c39405201d32.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4e2031d209711b058f3d278ede3c1d33.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/2c94bb12cee76221e13f9ef955b0aab1.png)
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6 . 古希腊数学家阿波罗尼奥斯(约公元首262公元前190年)的著作《圆锥曲线论》是古代世界光辉的科学成果,著作中这样一个命题:平面内与两定点距离的比为常数
且
的点的轨迹是圆,后人将这个圆称为阿波罗尼斯圆.已知点
满足
,则点
的轨迹与圆
的位置关系是__________ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6fbf56f44f995858afc4f6ae1306bdbb.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/15bb8775b827a649b07b6c2f8c3ea284.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b6f6802187232e008e5a24d83fb2122d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/3ab34ce6cee0673ab0d37b660d57bc07.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dad2a36927223bd70f426ba06aea4b45.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0590d795f63a3b6a9df731d4ead1d6da.png)
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解题方法
7 . 若曲线
与
恰有两个不同的交点,则实数
的取值范围是为__________ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/30268fadc181e93003913fc30b862235.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/7dfffb79b03312977edde3993ad2882d.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/df64046e91b047037f19e4032e3b6de3.png)
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解题方法
8 . 已知函数
在
处的切线斜率为
,且
,则![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dd707b69a11f8de5566f23c1a2a9ff5a.png)
__________ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/942c2141d01bde6b48210c56a17fc75e.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/707ea658f3a9359f5740d5aab48f7948.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/f0a532e15e232cb4b99a8d4d07c89575.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/470e051ec1701f654672ad3d9d6225c9.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dd707b69a11f8de5566f23c1a2a9ff5a.png)
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9 . 若椭圆
与双曲线
的焦点重合,则正实数
的值是__________ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/996e27bd38f73ac37970225f09a9ee95.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c36e858bb2b512701c65e064c14f5131.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/0a6936d370d6a238a608ca56f87198de.png)
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解题方法
10 . 已知椭圆
,双曲线
.设椭圆
两个焦点分别为
,椭圆
的离心率为
,双曲线
的离心率为
,记双曲线
的一条渐近线与椭圆
的一个交点为
,若
且
,则
的值为__________ .
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/36c6162828793e697cb1ad643b287c4b.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/cb27fed96fe0a3445beb873be8dd57c3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ac047e91852b91af639feec23a9598b2.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/4d2a97987f71835f519b462f5b8f5957.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ac047e91852b91af639feec23a9598b2.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/b1ffc3f634f435d40f9caba97a66187c.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/54a5d7d3b6b63fe5c24c3907b7a8eaa3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/6681ba848304fe48791781a6d36cd3bb.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/54a5d7d3b6b63fe5c24c3907b7a8eaa3.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/ac047e91852b91af639feec23a9598b2.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/dad2a36927223bd70f426ba06aea4b45.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/c2427943a38dcd93c9ec9b735ffc9fe5.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/9113004f4a1baf9f099ba50407ab93ef.png)
![](https://staticzujuan.xkw.com/quesimg/Upload/formula/018f68cd8f4b0d1c5eaaf772fcc14ff3.png)
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